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The reaction of PPh3 with Di-μ-chlorobis(arylazooximato)dipalladium(II)

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Summary

Di-μ-chlorobis(arylazooximato)dipalladiuni(II) compounds react with PPh3 to give the four-coordinate complexes (5) and (4) in which the azooxime acts as a unidentate and bidentate ligand respectively. Hydrogen bonding in polar solvents such as MeOH or EtOHetc. stabilize (5) whereas, polar solvents such as Me2CO, py and Et2O convert (5) into (4). The equilibrium: (4) + PPh3 ⇋ (5) exists in PhH solution and equilibrium constants at 30°C have been calculated spectrophotometrically. The variation in equilibrium constants and the stabilities of (5) have been explained on the basis of electron-releasing and electron-withdrawing properties of substituents, R, in the azooxime ligand.

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References

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Authors and Affiliations

  1. Department of Chemistry, Punjabi University, 147002, Patiala, India

    Krishan C. Kalia, Meenakshi Singla & Anil Kumar

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  1. Krishan C. Kalia
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  2. Meenakshi Singla
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  3. Anil Kumar
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Kalia, K.C., Singla, M. & Kumar, A. The reaction of PPh3 with Di-μ-chlorobis(arylazooximato)dipalladium(II). Transition Met Chem 7, 151–153 (1982). https://doi.org/10.1007/BF01035830

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  • DOI: https://doi.org/10.1007/BF01035830

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