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The role of the reactor surface in the liquid-phase oxidation of hexafluoropropylene

  • Physical Chemistry
  • Published:
Bulletin of the Academy of Sciences of the USSR, Division of chemical science Aims and scope

Conclusions

  1. 1.

    A study has been made of the effect of the reactor surface (stainless steel and Teflon) on the oxidation of hexfluoropropylene. In the Teflon reactor, the hexafluoropropylene reacts with surface peroxide radicals, the result being that ester and peroxide groups are introduced into the polymeric Teflon molecules. Stainless steel catalyzes the formation of hexafluoroacetone and various oligomeric products: CF3O(CF2O)n·CF2OCF2COF, and CF3O(CF2O)m· CF2OCOF.

  2. 2.

    The increase in yields of carbonylfluoride and trifluoroacetylfluoride which accompanies passage to the metal reactor is due to metal catalysis of the decomposition of alkoxy- and alkylperoxy radicals at the C-C bond.

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Literature cited

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Authors and Affiliations

  1. Institute of Chemical Physics, Academy of Sciences of the USSR, Moscow

    S. V. Kartsov, P. I. Valov, L. F. Sokolov & S. V. Sokolov

Authors
  1. S. V. Kartsov
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  2. P. I. Valov
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  3. L. F. Sokolov
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  4. S. V. Sokolov
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Additional information

Translated from Izvestiya Akademii Nauk SSSR, Seriya Khimicheskaya, No. 10, pp. 2268–2272, October, 1978.

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Kartsov, S.V., Valov, P.I., Sokolov, L.F. et al. The role of the reactor surface in the liquid-phase oxidation of hexafluoropropylene. Russ Chem Bull 27, 2006–2010 (1978). https://doi.org/10.1007/BF00946515

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  • DOI: https://doi.org/10.1007/BF00946515

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