Conclusions
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1.
The complex (C5H5)2TiCl·AlC2H5Cl2 is oxidized by SnCl4 with the formation of a complex of (C5H5)2·TiCl2 with AlCl3 and SnCl2 as the basic product of this reaction.
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2.
Parallel with the oxidation of (C5H5)2TiCl by stannic chloride there is a competitive interaction of SnCl4 with organoaluminum compounds. When the mole ratio Al/Ti is increased, this reaction leads to a decrease in the effectiveness of the action of SnCl4 in the oxidation of (C5H5)2TiCl.
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3.
During the interaction with SnCl4, the complex (C2H5)2TiCl·AlC2H5Cl2 is partially converted to the complex (C5H5)2TiCl·AlCl3.
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4.
The oxidation of the complex (C5H5)2TiCl·AlC2H5Cl2 by CCl4 was studied. SiCl4 does not oxidize (C5H5)2TiCl, which is explained by the high energy of the Si-Cl bond.
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Translated from Izvestiya Akademii Nauk SSSR, Seriya Khimicheskaya, No. 11, pp. 2407–2412, November, 1971.
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Matkovskii, P.E., Larkina, T.I., Dzhaviev, T.S. et al. Oxidation of the complex (C5H5)2TiCl·AlC2H5Cl2 by stannic chloride. Russ Chem Bull 20, 2287–2291 (1971). https://doi.org/10.1007/BF00854297
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DOI: https://doi.org/10.1007/BF00854297