Summary
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1.
in the reaction of 1,1,3-tri-(β-chloroethoxy)propane with two moles of sodium methylate, two atoms of chlorine are replaced by methoxy groups, forming 1,1-di-(β-methoxyethoxy)-3-(β-chloroethoxy)propane.
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2.
The reaction of 1,1,3-tri-(β-chloroethoxy)propane with alcoholates of n-butyl and tert-butyl alcohols leads to splitting out of two molecules of HCl and the production of 1,1-divinyloxy-3-(β-chloroethoxy)propane. Under the action of excess sodium methylate on 1,1,3-tri-(β-chloroethoxy)propane, two products are formed: 1,1,3-tri-(methoxyethoxy) propane and the 1,1-dimethoxyethyl acetal of acrolein.
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Literature cited
M. F. Shostakovskii, T. T. Minakova, and F. P. Sidel'kovskaya, Izd. AN SSSR, Otd. khim. n.,1964, No. 12.
M. F. Shostakovskii and N. A. Gershtein, Izd. AN SSSR, Otd. khim. n.,1953, 716.
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Translated from Izvestiya Akademii Nauk SSSR, Seriya Khimicheskaya No. 11, pp. 2106–2108, November, 1964
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Shostakovskii, M.F., Sidel'kovskaya, F.P. & Minakova, T.T. Reaction of 1,1,3 -TRI-(β-chloroethoxy)propane with some sodium alcoholates. Russ Chem Bull 13, 2009–2011 (1964). https://doi.org/10.1007/BF00844510
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DOI: https://doi.org/10.1007/BF00844510