UV dose-dependent increase in the hoechst fluorescence intensity of both normal and BrdU-DNA

Summary

If the DNA nucleoside thymidine is replaced by bromodeoxyuridine, the fluorescence of the nuclei of Hoechst-stained cells is quenched. The decrease of fluorescence intensity determined by flow cytometry and fluorometry is neutralized independent of the degree of BrdU substitution by an UV-exposure with a dose of 5–10 kJ/m² to the unfiltered spectrum of a 100 W mercury high-pressure lamp. This dose is equivalent to that obtained in fluorescence microscopy after exposure for about 1 s. We suppose that this approximate matching of the intensities both of normal and BrdU-substituted cells is caused by the splitting-off of bromine from BrdU in the DNA resulting in no further quenching. However, the fluorescence intensity of normal Hoechst-stained DNA also is increased by a previous exposure to UV light. We explain the time pattern of the Hoechst fluorescence in the course of an exposure with constant dose rate, by the superimposition of the well-known bleaching by an additional increase of the fluorescence intensity. Our results suggest that the UV-exposure of Hoechst dye creates a brightly fluorescing photoproduct which differs spectroscopically from the original dye. This product is stable in the dark and seems to fluorochrome DNA only if it is formed when the Hoechst dye is bound to DNA, thus increasing the nuclear fluorescence. Phosphorescence was not found.