Step 1: Preliminaries. We begin by proving estimates on
ψ ħ , then we perform the rescaling suggested by the form of the approximation solution. First, it follows from Lemma A.4 and [
4] that for fixed
ħ>0, (
A.1) has a unique, global solution
\(\psi^{\hbar}\in C(\mathbb{R};\varSigma)\) (
Σ is defined in Lemma A.4). In addition, if we set
$$\begin{aligned} \text{Mass: } &M^\hbar(t) = \bigl\|\psi^\hbar(t) \bigr\|_{L^2}^2, \\ \text{Energy: }& E^\hbar(t) = \frac{1}{2}\bigl\|\hbar\nabla \psi^\hbar(t)\bigr\|_{L^2}^2 + \frac{\epsilon(\hbar)}{2}\bigl\| \psi^\hbar(t)\bigr\|_{L^4}^4 + \int _{\mathbb{R}^d}V(t,x) \bigl|\psi^\hbar(t,x)\bigr|^2dx , \end{aligned}$$
then we have the
a priori estimates:
$$\begin{aligned} &\frac{d M^\hbar}{dt} =0, \\ & \frac{d E^\hbar}{dt} = \int_{\mathbb{R}^d} {\partial}_t V(t,x) \bigl|\psi^\hbar(t,x)\bigr|^2dx= \kappa(\hbar)\int _{R^d} V_a(x)\bigl|\psi^\hbar (t,x)\bigr|^2dx , \end{aligned}$$
where we have used (
2.4) for the last equality. Note that (
A.1) is not a Hamiltonian equation, unlike the one studied in [
1], where the Hamiltonian structure is crucial. The conservation of mass and the form of the initial data yield
$$ M^{\hbar}(t)= \bigl\|\psi^\hbar(t)\bigr\|_{L^2} = \bigl\| \psi^\hbar(0)\bigr\|_{L^2} =M^\hbar(0)\leq C, $$
for some
C independent of
ħ. We have
$$\begin{aligned} E^\hbar(0)&= \bigl\langle\alpha_L\varphi_L^\hbar+ \alpha_R\varphi_R^\hbar, \alpha_L H_0 \varphi_L^\hbar+ \alpha_R H_0\varphi_R^\hbar \bigr\rangle+ \frac{\epsilon(\hbar)}{2}\bigl\|\alpha_L\varphi _L^\hbar+ \alpha_R\varphi_R^\hbar \bigr\|_{L^4}^4 . \end{aligned}$$
Introduce
\(\varOmega^{\hbar}=(\lambda_{-}^{\hbar}+\lambda_{+}^{\hbar})/2\) and notice that
\(\varOmega^{\hbar}=V_{s}^{\mathrm{min}} +\mathcal{O}(\hbar )\) by Lemma A.3. Noting the identities
$$ H_0\varphi_L^\hbar= \varOmega^\hbar\varphi_L^\hbar- \omega^\hbar\varphi_R^\hbar;\qquad H_0\varphi_R^\hbar= \varOmega^\hbar \varphi_R^\hbar- \omega^\hbar \varphi_L^\hbar, $$
(A.4)
we infer from Lemma A.3 and Lemma A.4 that
$$ E^\hbar(0)= V_s^{\mathrm{min}} M^\hbar(0) + \mathcal{O}(\hbar). $$
Therefore, since
V a is bounded,
$$\begin{aligned} \bigl\|\hbar\nabla\psi^\hbar(t)\bigr\|_{L^2}^2 & \leq2 E^\hbar(t) -2 V_s^{\mathrm{min}} M^\hbar(t)+C \kappa(\hbar)tM^\hbar(t) \\ &\leq2 E^\hbar(0) -2 V_s^{\mathrm{min}} M^\hbar(0)+2\kappa(\hbar)\int_0^t \int_{R^d} V_a(x)\bigl|\psi^\hbar(t,x)\bigr|^2dx+C \kappa(\hbar)t \\ &\leq C\hbar+ C \frac{(\omega^\hbar)^2}{\hbar} t. \end{aligned}$$
Next, as in [
27], we consider the slow time
$$ \tau= \frac{\omega^\hbar t}{\hbar}\geq0, $$
and the new unknown function
$$ \varPsi^\hbar(\tau,x) = \psi^\hbar(t,x) \mathrm{e}^{i\varOmega^\hbar t/\hbar} = \psi^\hbar(t,x) \mathrm{e}^{i\varOmega^\hbar\tau /\omega^\hbar} . $$
It solves
$$ i{\partial}_\tau\varPsi^\hbar= \frac{1}{\omega^\hbar} \bigl(H_0-\varOmega^\hbar\bigr) \varPsi^\hbar+\eta\tau V_a \varPsi^\hbar+\delta \hbar^{d/2}\bigl|\varPsi^\hbar\bigr|^2\varPsi^\hbar, $$
(A.5)
and in view of the above estimates,
$$ \bigl\|\varPsi^\hbar(\tau)\bigr\|_{L^2} = \bigl\| \varPsi^\hbar(0)\bigr\|_{L^2}=\mathcal{O}(1);\quad\bigl\|\nabla \varPsi^\hbar(\tau)\bigr\|_{L^2}^2 \leq C \biggl( \frac{1}{\hbar} + \frac{\omega^\hbar}{\hbar^2}\tau\biggr). $$
(A.6)
We decompose
Ψ ħ as
$$ \varPsi^\hbar= \varphi^\hbar+ \psi_c^\hbar,\quad\psi_c^\hbar= \varPi_c^\hbar\varPsi^\hbar, $$
(A.7)
so we can write
φ ħ as
$$ \varphi^\hbar(\tau,x) = {\mathtt{a}}^\hbar_L( \tau)\varphi_L^\hbar(x) + {\mathtt{a}}^\hbar _R(\tau)\varphi_R^\hbar(x) , $$
for some complex-valued coefficients
\({\mathtt{a}}^{\hbar}_{L}\) and
\({\mathtt{a}}^{\hbar}_{R}\). Projecting (
A.5), and using (
A.4), we find:
$$\begin{aligned} i\dot{\mathtt{a}}^\hbar_L & = -{\mathtt{a}}^\hbar _R +\eta\tau\int_{\mathbb{R}^d}V_a \varPsi ^\hbar\varphi_L^\hbar+ \delta \hbar^{d/2} \int_{\mathbb{R}^d} \bigl|\varPsi^\hbar\bigr|^2 \varPsi^\hbar\varphi_L^\hbar, \\ i\dot{\mathtt{a}}^\hbar_R & = -{\mathtt{a}}^\hbar _L +\eta\tau\int_{\mathbb{R}^d}V_a \varPsi ^\hbar\varphi_R^\hbar+ \delta \hbar^{d/2} \int_{\mathbb{R}^d} \bigl|\varPsi^\hbar\bigr|^2 \varPsi^\hbar\varphi_R^\hbar, \\ i{\partial}_\tau\psi_c^\hbar& = \frac{1}{\omega^\hbar} \bigl(H_0-\varOmega^\hbar\bigr) \psi_c^\hbar+\eta\tau\varPi^\hbar_c \bigl(V_a \varPsi^\hbar\bigr)+\delta \hbar^{d/2}\varPi_c^\hbar\bigl(\bigl| \varPsi^\hbar\bigr|^2 \varPsi^\hbar\bigr). \end{aligned}$$
The proof of Proposition A.6 consists in showing that
\({\mathtt{a}}^{\hbar}_{L/R}\) are close to
a L/R , and that
\(\psi ^{\hbar}_{c}\) is small. This is achieved in two more steps.
Step 2. A priori estimates on \(\mathtt {a}^{\hbar}_{R}\),
\({\mathtt{a}}^{\hbar}_{L}\) and \(\psi^{\hbar}_{c}\) . By definition, we have
\({\mathtt{a}}^{\hbar}_{L}=\int_{\mathbb {R}^{d}}\varPsi ^{\hbar}\varphi _{L}^{\hbar}\), so Cauchy–Schwarz inequality yields
$$ \bigl\|\varphi^\hbar(\tau)\bigr\|^2_{L^2}= \bigl|{ \mathtt{a}}^\hbar_L(\tau)\bigr|^2+ \bigl|{ \mathtt{a}}^\hbar_R(\tau)\bigr|^2\leq \bigl(M^\hbar\bigr)^2 \bigl(\bigl\|\varphi_L^\hbar \bigr\|_{L^2}^2 + \bigl\|\varphi_R^\hbar \bigr\|_{L^2}^2 \bigr)\leq2 \bigl(M^\hbar \bigr)^2. $$
Decompose the nonlinearity acting on
Ψ ħ as
$$ \bigl|\varPsi^\hbar\bigr|^2 \varPsi^\hbar= \bigl| \varphi^\hbar\bigr|^2\varphi^\hbar+ \mathtt{R}^\hbar. $$
Using the
a priori estimates on
a ħ and Lemma A.4, we have
$$ \bigl\|\bigl|\varphi^\hbar\bigr|^2\varphi^\hbar\bigr \|_{L^2}\leq\bigl\|\varphi^\hbar\bigr\|_{L^\infty}^2 \bigl\|\varphi^\hbar\bigr\|_{L^2}\leq C \bigl(\bigl\|\varphi _L^\hbar \bigr\|_{L^\infty}^2 + \bigl\|\varphi^\hbar_R\bigr\| _{L^\infty}^2 \bigr)\leq C\hbar^{-d/2}. $$
Since we have the pointwise estimate
$$ \bigl|\mathtt{R}^\hbar\bigr|\leq C \bigl( \bigl|\varphi^\hbar \bigr|^2 \bigl|\psi^\hbar_c\bigr| + \bigl|\psi^\hbar _c\bigr|^3 \bigr), $$
we infer
$$ \bigl\|\mathtt{R}^\hbar\bigr\|_{L^2}\leq C \bigl( \hbar^{-d/2} \bigl\|\psi^\hbar_c\bigr\|_{L^2} + \bigl\|\psi^\hbar_c\bigr\|^3_{L^6} \bigr), $$
and Gagliardo–Nirenberg inequality yields (
d≤2)
$$ \bigl\|\psi^\hbar_c\bigr\|^3_{L^6(\mathbb{R}^d)} \leq C \bigl\| \psi^\hbar_c\bigr\|_{L^2(\mathbb{R}^d)}^{3-d}\bigl\|\nabla \psi^\hbar_c\bigr\|_{L^2(\mathbb{R}^d)}^{d}. $$
Since
d≤2, we can factor out
\(\|\psi^{\hbar}_{c}\|_{L^{2}(\mathbb {R}^{d})}\), and (
A.6) gives
$$ \bigl\|\psi^\hbar_c\bigr\|^3_{L^6(\mathbb{R}^d)} \leq C \bigl\| \psi^\hbar_c\bigr\|_{L^2(\mathbb{R}^d)}\hbar^{-d/2} \biggl(1 + \biggl(\frac {\omega^\hbar \tau}{\hbar} \biggr)^{d/2} \biggr). $$
Therefore,
$$ \bigl\|\mathtt{R}^\hbar\bigr\|_{L^2}\leq C \hbar^{-d/2} \biggl(1 + \biggl(\frac{\omega^\hbar \tau}{\hbar} \biggr)^{d/2} \biggr)\bigl\|\psi^\hbar_c\bigr\|_{L^2}, $$
(A.8)
and |
Ψ ħ |
2 Ψ ħ satisfies a similar estimate. We infer
$$ \bigl|\dot{\mathtt{a}}^\hbar_L(\tau) \bigr|+ \bigl| \dot{\mathtt{a}}^\hbar_R(\tau)\bigr|\leq C (1+\tau) +C \biggl(1 + \biggl(\frac{\omega^\hbar\tau}{\hbar} \biggr)^{d/2} \biggr) . $$
Since
d≤2 and
\(\omega^{\hbar}=\mathcal{O}(\mathrm{e}^{-c/\hbar })\), we can simplify the above estimate:
$$ \bigl|\dot{\mathtt{a}}^\hbar_L(\tau)\bigr|+ \bigl| \dot{\mathtt{a}}^\hbar_R(\tau) \bigr|\leq C (1+\tau), \quad\forall\tau\geq0. $$
From this we infer
$$ \bigl\|{\partial}_\tau\varphi^\hbar \bigr\|_{L^2} \leq\bigl|\dot{\mathtt{a}}^\hbar_L( \tau) \bigr|\bigl\|\varphi_L^\hbar\bigr\|_{L^2} + \bigl| \dot{\mathtt{a}}^\hbar_R(\tau) \bigr|\bigl\| \varphi_R^\hbar\bigr\|_{L^2} \leq C(1+\tau), $$
(A.9)
and, again from Lemma A.4,
$$ \bigl\|{\partial}_\tau\bigl(\bigl| \varphi^\hbar\bigr|^2\varphi^\hbar\bigr) \bigr\|_{L^2} \leq3\bigl\|\varphi^\hbar\bigr\|_{L^\infty}^2 \bigl\|{\partial}_\tau\varphi^\hbar\bigr\|_{L^2} \leq C\hbar^{-d/2}(1+\tau). $$
(A.10)
Step 3. Stability estimates. In view of (
A.7), we first prove that
\(\psi^{\hbar}_{c}\) is small. Since
\(\psi^{\hbar}_{c\mid\tau=0}=0\), Duhamel’s formula yields
$$\begin{aligned} \psi^\hbar_c(\tau) &= -i\eta\int _0^\tau\mathrm{e}^{-i(H_0-\varOmega^\hbar)(\tau-s)/\omega^\hbar} \bigl(s \varPi^\hbar_c \bigl( V_a \varPsi^\hbar\bigr) (s) \bigr)ds \\ &\quad-i \delta\hbar^{d/2}\int_0^\tau \mathrm{e}^{-i(H_0-\varOmega^\hbar)(\tau-s)/\omega^\hbar} \varPi ^\hbar_c \bigl( \bigl| \varPsi^\hbar\bigr|^2 \varPsi^\hbar\bigr) (s)ds. \end{aligned}$$
(A.11)
Each term is treated in a similar fashion: when
Ψ ħ is replaced by
φ ħ , we perform an integration by parts, and for the remaining term, we use directly the
a priori estimates. For the first part of (
A.11), we write
$$ \varPi^\hbar_c \bigl( V_a \varPsi^\hbar\bigr)= \varPi^\hbar_c \bigl( V_a \varphi^\hbar\bigr) + \varPi^\hbar_c \bigl( V_a \psi^\hbar_c \bigr), $$
and set
$$\begin{aligned} I^\hbar_1(\tau) & = \int_0^\tau \mathrm{e}^{-i(H_0-\varOmega^\hbar)(\tau-s)/\omega^\hbar} \bigl (s \varPi^\hbar_c \bigl( V_a \varphi^\hbar\bigr) (s) \bigr)ds, \\ I^\hbar_2(\tau) & = \int_0^\tau \mathrm{e}^{-i(H_0-\varOmega^\hbar)(\tau-s)/\omega^\hbar} \bigl (s \varPi^\hbar_c \bigl( V_a \psi^\hbar_c \bigr) (s) \bigr)ds. \end{aligned}$$
Integrating by parts,
$$\begin{aligned} I^\hbar_1(\tau) & = -i\omega^\hbar \mathrm{e}^{-i(H_0-\varOmega^\hbar)(\tau-s)/\omega^\hbar} \bigl (H_0-\varOmega^\hbar \bigr)^{-1}\varPi^\hbar_c \bigl(s V_a \varphi^\hbar\bigr) (s) \bigr|_0^\tau \\ &\quad+i\omega^\hbar\int_0^\tau \mathrm{e}^{-i(H_0-\varOmega^\hbar)(\tau-s)/\omega^\hbar} \bigl (H_0-\varOmega^\hbar \bigr)^{-1} \bigl(\varPi^\hbar_c \bigl( V_a \varphi^\hbar\bigr)+ s \varPi^\hbar_c \bigl( V_a {\partial}_\tau\varphi^\hbar\bigr) \bigr) (s)ds . \end{aligned}$$
From Lemma A.3, there exists
C independent of
ħ∈(0,
ħ ∗] such that
$$ \bigl\|\hbar\bigl(H_0-\varOmega^\hbar \bigr)^{-1}\varPi^\hbar_c \bigr\| _{L^2\to L^2}\leq C. $$
We infer, using (
A.9),
$$ \bigl|I^\hbar_1(\tau) \bigr|\leq C\frac{\omega^\hbar}{\hbar} \bigl(\tau+ \tau^3 \bigr). $$
For
\(I^{\hbar}_{2}\), we have directly
$$ \bigl|I^\hbar_2(\tau) \bigr|\leq C\int_0^\tau s\bigl\|\psi_c^\hbar(s)\bigr\|_{L^2}ds. $$
For the nonlinear term in Duhamel’s formula (the second term of (
A.11)), we also write
$$\varPi^\hbar_c\bigl(\bigl|\varPsi^\hbar\bigr|^2 \varPsi^\hbar\bigr)= \varPi^\hbar_c\bigl(\bigl| \varphi^\hbar\bigr|^2\varphi^\hbar\bigr)+ \varPi^\hbar_c\mathtt{R}^\hbar, $$
and set
$$\begin{aligned} I^\hbar_3(\tau) & =\hbar^{d/2} \int _0^\tau\mathrm{e}^{-i(H_0-\varOmega^\hbar)(\tau-s)/\omega^\hbar} \varPi^\hbar_c \bigl( \bigl|\varphi^\hbar\bigr|^2 \varphi^\hbar\bigr) (s)ds, \\ I^\hbar_4(\tau) & = \hbar^{d/2}\int _0^\tau\mathrm{e}^{-i(H_0-\varOmega^\hbar)(\tau-s)/\omega^\hbar} \varPi^\hbar_c \mathtt{R}^\hbar(s)ds. \end{aligned}$$
We have, directly from (
A.8),
$$ \bigl|I^\hbar_4(\tau)\bigr|\leq C\int_0^\tau \biggl(1 + \biggl(\frac{\omega^\hbar s}{\hbar} \biggr)^{d/2} \biggr)\bigl\| \psi_c^\hbar(s)\bigr\|_{L^2}ds, $$
and performing an integration by parts for
\(I_{3}^{\hbar}\), using (
A.10), we have
$$ \bigl|I^\hbar_3(\tau) \bigr|\leq C\frac{\omega^\hbar}{\hbar} \bigl(1+ \tau^2 \bigr). $$
Since
d≤2 and
ω ħ decays exponentially, we come up with:
$$ \bigl\|\psi_c^\hbar(\tau)\bigr\|_{L^2}\leq C \biggl( \frac{\omega^\hbar }{\hbar} \bigl(1+\tau^3 \bigr) + \int_0^\tau(1+s) \bigl\|\psi_c^\hbar(s)\bigr\| _{L^2}ds \biggr). $$
Gronwall lemma yields
$$ \bigl\|\psi_c^\hbar(\tau)\bigr\|_{L^2} \leq C \frac{\omega^\hbar}{\hbar}\bigl(1+\tau^3\bigr)\mathrm {e}^{C(\tau+\tau^2)}. $$
Recalling again that
ω ħ decays exponentially, we can write that for all
c 0<
Γ (the Agmon distance between the two wells),
$$ \bigl\|\psi_c^\hbar(\tau)\bigr\|_{L^2} \leq C \bigl(1+ \tau^3\bigr)\mathrm{e}^{C(\tau+\tau^2)-c_0/\hbar}. $$
This is small as
ħ→0, provided that
τ 2≪1/
ħ. More precisely, there exist
c 1,
c 2>0 independent of
ħ such that
$$ \bigl\|\psi_c^\hbar(\tau)\bigr\|_{L^2} \leq C \mathrm{e}^{-c_1/\hbar},\quad0\leq\tau\leq\frac {c_2}{\sqrt{\hbar}}. $$
(A.12)
To conclude the proof of the proposition, set
$$ \mathtt{w}^\hbar_L={\mathtt{a}}^\hbar _L-a_L;\qquad\mathtt{w}^\hbar _R= {\mathtt{a}}^\hbar_R-a_R. $$
Subtracting the equation for
a L from the equation for
\(\mathtt {a}^{\hbar}_{L}\), we have
$$\begin{aligned} i\dot{\mathtt{w}}_L^\hbar&= -\mathtt{w}^\hbar _R +\eta\tau\int_{\mathbb{R}^d}V_a \bigl( \varPsi^\hbar- a_L\varphi^\hbar_L \bigr)\varphi_L^\hbar \\ &\quad+\delta\hbar^{d/2}\int_{\mathbb{R}^d} \bigl(\bigl| \varPsi^\hbar\bigr|^2\varPsi^\hbar -|a_L|^2a_L \bigl|\varphi_L^\hbar\bigr|^2 \varphi_L^\hbar\bigr)\varphi_L^\hbar. \end{aligned}$$
We have
$$ \int_{\mathbb{R}^d}V_a \bigl(\varPsi^\hbar- a_L\varphi^\hbar_L \bigr) \varphi_L^\hbar= \int_{\mathbb{R}^d}V_a \bigl({\mathtt{a}}^\hbar_R \varphi^\hbar_R + \psi_c^\hbar+\mathtt{w}^\hbar _L \varphi^\hbar_L \bigr) \varphi_L^\hbar, $$
therefore, since the product
\(\varphi_{L}^{\hbar}\varphi_{R}^{\hbar}\) decays exponentially in
ħ,
$$ \biggl|\int_{\mathbb{R}^d}V_a \bigl( \varPsi^\hbar- a_L\varphi^\hbar_L \bigr)\varphi_L^\hbar\biggr|\leq C \bigl( \mathrm{e}^{-c/\hbar} + \bigl\|\psi^\hbar_c \bigr\|_{L^2} + \bigl|\mathtt{w}^\hbar_L\bigr| \bigr). $$
A similar estimate can be established for the other source term in the equation for
\(\mathtt{w}^{\hbar}_{L}\). The equation for
\(\mathtt {w}^{\hbar}_{R}\) is handled in the same fashion, and using (
A.12), we end up with:
$$ \bigl|\dot{\mathtt{w}}_L^\hbar(\tau)\bigr| + \bigl|\dot{ \mathtt{w}}_R^\hbar(\tau)\bigr|\leq C \bigl( \bigl| \mathtt{w}^\hbar_L(\tau)\bigr| +\bigl|\mathtt{w}^\hbar _R(\tau)\bigr| + \mathrm{e}^{-c/\hbar} \bigr), \quad0\leq\tau \leq \frac{c_2}{\sqrt{\hbar}}. $$
Gronwall lemma and (
A.12) then yield Proposition A.6. □