1 Introduction

Let H be a real Hilbert space with inner product , and induced norm . Let C be a nonempty closed convex subset of H and let T:CC be a self-mapping on C. We denote by Fix(T) the set of fixed points of T.

We recall that a mapping T:CH is said to be k-strictly pseudocontractive if there exists a constant k[0,1) such that

T x T y 2 x y 2 +k ( I T ) x ( I T ) y 2 ,x,yC.

The mapping T is pseudocontractive if and only if

TxTy,xy x y 2 ,x,yC.

T is strongly pseudocontractive if and only if there exists a constant λ(0,1) such that

TxTy,xy(1λ) x y 2 ,x,yC.

Note that the class of k-strictly pseudocontractive mappings includes the class of nonexpansive mappings T on C (i.e., TxTyxy, x,yC) as a subclass. That is, T is nonexpansive if and only if T is 0-strictly pseudocontractive. The mapping T is also said to be pseudocontractive if k=1 and T is said to be strongly pseudocontractive if there exists a positive constant λ(0,1) such that TλI is pseudocontractive. Clearly, the class of k-strictly pseudocontractive mappings falls into the one between classes of nonexpansive mappings and pseudocontractive mappings. Also we remark that the class of strongly pseudocontractive mappings is independent of the class of k-strictly pseudocontractive mappings (see [13]). The class of pseudocontractive mappings is one of the most important classes of mappings among nonlinear mappings. Recently, many authors have been devoting the studies on the problems of finding fixed points for pseudocontractive mappings; see, for example, [49] and the references therein.

Let A be a strongly positive bounded linear operator on H. That is, there is a constant γ ¯ >0 with the property

Ax,x γ ¯ x 2 ,xH.

It is well known that iterative methods for nonexpansive mappings can be used to solve a convex minimization problem: see, e.g., [1012] and the references therein. A typical problem is that of minimizing a quadratic function over the set of fixed points of a nonexpansive mapping on a real Hilbert space H:

min x C 1 2 Ax,xx,b,
(1.1)

where C is the fixed point set of a nonexpansive mapping S on H and b is a given point in H. In [11], Xu proved that the sequence { x n } generated by the iterative method for a nonexpansive mapping S presented below with the initial guess x 0 H chosen arbitrary:

x n + 1 = α n b+(I α n A)S x n ,n0,
(1.2)

converges strongly to the unique solution of the minimization problem (1.1) provided the sequence { α n } satisfies certain conditions.

In [13], combining the Moudafi viscosity approximation method [14] with Xu’s method (1.2), Marino and Xu [13] considered the following general iterative method for a nonexpansive mapping S:

x n + 1 = α n γf x n +(I α n A)S x n ,n0,
(1.3)

where f is a contractive mapping on H with a constant α(0,1) (i.e., there exists a constant α(0,1) such that f(x)f(y)αxy, x,yH). They proved that if the sequence { α n } of control parameters satisfies appropriate conditions, then the sequence { x n } generated by (1.3) converges strongly to the unique solution of the variational inequality

( γ f A ) x ˜ , x x ˜ 0,xFix(S),

which is the optimality condition for the minimization problem

min x Fix ( S ) 1 2 Ax,xh(x),

where h is a potential function for γf (i.e., h =γf).

On the other hand, Yamada [12] introduced the following hybrid steepest-descent method for a nonexpansive mapping S for solving the variational inequality:

x n + 1 =(I ξ n μF)S x n ,n0,
(1.4)

where S:HH is a nonexpansive mapping with Fix(S); F:HH is a ρ-Lipschitzian and η-strongly monotone operator with constants ρ>0 and η>0 (i.e., FxFyρxy and FxFy,xyη x y 2 , x,yH, respectively), and 0<μ< 2 η ρ 2 , and then proved that if { ξ n } satisfies appropriate conditions, the sequence { x n } generated by (1.4) converges strongly to the unique solution of the variational inequality:

F x ˜ ,x x ˜ 0,xFix(S).

In 2010, by combining Yamada’s hybrid steepest-descent method (1.4) with Marino with Xu’s method (1.3), Tian [15] introduced the following general iterative method for a nonexpansive mapping S:

x n + 1 = α n γf x n +(I α n μF)S x n ,n0,
(1.5)

where f is a contractive mapping on H with a constant α(0,1). His results improved and complemented the corresponding results of Marino and Xu [13]. In [16], Tian also considered the following general iterative method for a nonexpansive mapping S:

x n + 1 = α n γV x n +(I α n μF)S x n ,n0,
(1.6)

where V:HH is a Lipschitzian mapping with a constant l0. In particular, the results in [16] extended the results of Tian [15] from the case of the contractive mapping f to the case of a Lipschitzian mapping V.

In 2011, Ceng et al. [17] also introduced the following iterative method for the nonexpansive mapping S:

x n + 1 = P C [ α n γ V x n + ( I α n μ F ) S x n ] ,n0,
(1.7)

where F:CH is a ρ-Lipschitzian and η-strongly monotone operator with constants ρ>0 and η>0, V:CH is an l-Lipschitzian mapping with a constant l0 and 0<μ< 2 η ρ 2 . In particular, by using appropriate control conditions on { α n }, they proved that the sequence { x n } generated by (1.7) converges strongly to a fixed point x ˜ of S, which is the unique solution of the following variational inequality related to the operator F:

μF x ˜ γV x ˜ , x ˜ p0,pFix(S).

Their results also improved the results of Tian [15] from the case of the contractive mapping f to the case of a Lipschitzian mapping V.

In 2011, Ceng et al. [18] introduced the following general composite iterative method for a nonexpansive mapping S:

{ y n = ( I α n μ F ) S x n + α n γ f x n , x n + 1 = ( I β n A ) S x n + β n y n , n 0 ,
(1.8)

which combines Xu’s method (1.2) with Tian’s method (1.5). Under appropriate control conditions on { α n } and { β n }, they proved that the sequence { x n } generated by (1.8) converges strongly to a fixed point x ˜ of S, which is the unique solution of the following variational inequality related to the operator A:

( A I ) x ˜ , x ˜ p 0,pFix(S).

Their results supplemented and developed the corresponding ones of Marino and Xu [13], Yamada [12] and Tian [15].

On the another hand, in 2011, by combining Yamada’s hybrid steepest-descent method (1.4) with Marino and Xu’s method (1.3), Jung [7] considered the following explicit iterative scheme for finding fixed points of a k-strictly pseudocontractive mapping T for some 0k<1:

x n + 1 = α n γf( x n )+ β n x n + ( ( 1 β n ) I α n μ F ) P C S x n ,n0,
(1.9)

where S:CH is a mapping defined by Sx=kx+(1k)Tx; P C is the metric projection of H onto C; f:CC is a contractive mapping with a constant α(0,1); F:CC is a ρ-Lipschitzian and η-strongly monotone operator with constants ρ>0 and η>0; and 0<μ< 2 η ρ 2 . Under suitable control conditions on { α n } and { β n }, he proved that the sequence { x n } generated by (1.9) converges strongly to a fixed point x ˜ of T, which is the unique solution of the following variational inequality related to the operator F:

μF x ˜ γf x ˜ , x ˜ p0,pFix(T).

His result also improved and complemented the corresponding results of Cho et al. [5], Jung [6], Marino and Xu [13] and Tian [15].

In this paper, motivated and inspired by the above-mentioned results, we will combine Xu’s method (1.2) with Tian’s method (1.6) for a k-strictly pseudocontractive mapping T for some 0k<1 and consider the following new general composite iterative method for finding an element of Fix(T):

{ y n = α n γ V x n + ( I α n μ F ) T n x n , x n + 1 = ( I β n A ) T n x n + β n y n , n 0 ,
(1.10)

where T n :HH is a mapping defined by T n x= λ n x+(1 λ n )Tx for 0k λ n λ<1 and lim n λ n =λ; A is a strongly positive bounded linear operator on H with a constant γ ¯ (1,2); { α n }[0,1] and { β n }(0,1] satisfy appropriate conditions; V:HH is a Lipschitzian mapping with a constant l0; F:HH is a ρ-Lipschitzian and η-strongly monotone operator with constants ρ>0 and η>0; and 0<μ< 2 η ρ 2 . By using weaker control conditions than previous ones, we establish the strong convergence of the sequence generated by the proposed iterative method (1.10) to a point x ˜ in Fix(T), which is the unique solution of the variational inequality related to A:

( A I ) x ˜ , x ˜ p 0,pFix(T).

Our results complement, develop, and improve upon the corresponding ones given by Cho et al. [5] and Jung [68] for the strictly pseudocontractive mapping as well as Yamada [12], Marino and Xu [13], Tian [15] and Ceng et al. [17] and Ceng et al. [18] for the nonexpansive mapping.

2 Preliminaries and lemmas

Throughout this paper, when { x n } is a sequence in H, x n x (resp., x n x) will denote strong (resp., weak) convergence of the sequence { x n } to x.

For every point xH, there exists a unique nearest point in C, denoted by P C (x), such that

x P C ( x ) xy,yC.

P C is called the metric projection of H to C. It is well known that P C is nonexpansive and that, for xH,

z= P C xxz,yz0,yC.
(2.1)

In a Hilbert space H, we have

x y 2 = x 2 + y 2 2x,y,x,yH.
(2.2)

Lemma 2.1 In a real Hilbert space H, the following inequality holds:

x + y 2 x 2 +2y,x+y,x,yH.

Let LIM be a Banach limit. According to time and circumstances, we use LIM n ( a n ) instead of LIM(a) for every a={ a n } . The following properties are well known:

  1. (i)

    for all n1, a n c n implies LIM n ( a n ) LIM n ( c n ),

  2. (ii)

    LIM n ( a n + N )= LIM n ( a n ) for any fixed positive integer N,

  3. (iii)

    lim inf n a n LIM n ( a n ) lim sup n a n for all { a n } l .

The following lemma was given in [[19], Proposition 2].

Lemma 2.2 Let aR be a real number and let a sequence { a n } l satisfy the condition LIM n ( a n )a for all Banach limit LIM. If lim sup n ( a n + 1 a n )0, then lim sup n a n a.

We also need the following lemmas for the proof of our main results.

Lemma 2.3 ([20, 21])

Let { s n } be a sequence of non-negative real numbers satisfying

s n + 1 (1 ω n ) s n + ω n δ n + r n ,n0,

where { ω n }, { δ n }, and { r n } satisfy the following conditions:

  1. (i)

    { ω n }[0,1] and n = 0 ω n =,

  2. (ii)

    lim sup n δ n 0 or n = 0 ω n | δ n |<,

  3. (iii)

    r n 0 (n0), n = 0 r n <.

Then lim n s n =0.

Lemma 2.4 ([22] Demiclosedness principle)

Let C be a nonempty closed convex subset of a real Hilbert space H, and let S:CC be a nonexpansive mapping. Then the mapping IS is demiclosed. That is, if { x n } is a sequence in C such that x n x and (IS) x n y, then (IS) x =y.

Lemma 2.5 ([23])

Let H be a real Hilbert space and let C be a closed convex subset of H. Let T:CH be a k-strictly pseudocontractive mapping on C. Then the following hold:

  1. (i)

    The fixed point set Fix(T) is closed convex, so that the projection P Fix ( T ) is well defined.

  2. (ii)

    Fix( P C T)=Fix(T).

  3. (iii)

    If we define a mapping S:CH by Sx=λx+(1λ)Tx for all xC. then, as λ[k,1), S is a nonexpansive mapping such that Fix(T)=Fix(S).

The following lemma can easily be proven (see also [12]).

Lemma 2.6 Let H be a real Hilbert space H. Let F:HH be a ρ-Lipschitzian and η-strongly monotone operator with constants ρ>0 and η>0. Let 0<μ< 2 η ρ 2 and 0<t<ξ1. Then G:=ξItμF:HH is a contractive mapping with constant ξtτ, where τ=1 1 μ ( 2 η μ ρ 2 ) .

Lemma 2.7 ([13])

Assume that A is a strongly positive bounded linear operator on H with a coefficient γ ¯ >0 and 0<ζ A 1 . Then IζA1ζ γ ¯ .

Finally, we recall that the sequence { x n } in H is said to be weakly asymptotically regular if

w- lim n ( x n + 1 x n )=0,that is,  x n + 1 x n 0

and asymptotically regular if

lim n x n + 1 x n =0,

respectively.

3 The main results

Throughout the rest of this paper, we always assume the following:

  • H is a real Hilbert space;

  • T:HH is a k-strictly pseudocontractive mapping with Fix(T) for some 0k<1;

  • F:HH is a ρ-Lipschitzian and η-strongly monotone operator with constants ρ>0 and η>0;

  • A:HH is a strongly positive linear bounded operator on H with a constant γ ¯ (1,2);

  • V:HH is an l-Lipschitzian mapping with a constant l0;

  • 0<μ< 2 η ρ 2 and 0γl<τ, where τ=1 1 μ ( 2 η μ ρ 2 ) ;

  • T t :HH is a mapping defined by T t x= λ t x+(1 λ t )Tx, t(0,1), for 0k λ t λ<1 and lim t 0 λ t =λ;

  • T n :HH is a mapping defined by T n x= λ n x+(1 λ n )Tx for 0k λ n λ<1 and lim n λ n =λ;

  • P Fix ( T ) is a metric projection of H onto Fix(T).

By Lemma 2.5(iii), we note that T t and T n are nonexpansive and Fix(T)=Fix( T t )=Fix( T n ).

In this section, we introduce the following general composite scheme that generates a net { x t } t ( 0 , min { 1 , 2 γ ¯ τ γ l } ) in an implicit way:

x t =(I θ t A) T t x t + θ t [ t γ V x t + ( I t μ F ) T t x t ] .
(3.1)

We prove strong convergence of { x t } as t0 to a fixed point x ˜ of T which is a solution of the following variational inequality:

( A I ) x ˜ , x ˜ p 0,pFix(T).
(3.2)

We also propose the following general composite explicit scheme, which generates a sequence in an explicit way:

{ y n = α n γ V x n + ( I α n μ F ) T n x n , x n + 1 = ( I β n A ) T n x n + β n y n , n 0 ,
(3.3)

where { α n }[0,1], { β n }(0,1] and x 0 H is an arbitrary initial guess, and establish strong convergence of this sequence to a fixed point x ˜ of T, which is also the unique solution of the variational inequality (3.2).

Now, for t(0,min{1, 2 γ ¯ τ γ l }) and θ t (0, A 1 ], consider a mapping Q t :HH defined by

Q t x=(I θ t A) T t x+ θ t [ t γ V x + ( I t μ F ) T t x ] ,xH.

It is easy to see that Q t is a contractive mapping with constant 1 θ t ( γ ¯ 1+t(τγl)). Indeed, by Lemma 2.6 and Lemma 2.7, we have

Q t x Q t y ( I θ t A ) T t x ( I θ t A ) T t y + θ t [ t γ V x + ( I t μ F ) T t x ] [ t γ V y + ( I t μ F ) T t y ] ( 1 θ t γ ¯ ) x y + θ t [ t γ V x V y + ( I t μ F ) T t x ( I t μ F ) T t y ] ( 1 θ t γ ¯ ) x y + θ t ( 1 t ( τ γ l ) ) x y = [ 1 θ t ( γ ¯ 1 + t ( τ γ l ) ) ] x y .

Since γ ¯ (1,2), τγl>0, and

0<t<min { 1 , 2 γ ¯ τ γ l } 2 γ ¯ τ γ l ,

it follows that

0< ( γ ¯ 1 + t ( τ γ l ) ) <1,

which along with 0< θ t A 1 <1 yields

0<1 θ t ( γ ¯ 1 + t ( τ γ l ) ) <1.

Hence Q t is a contractive mapping. By the Banach contraction principle, Q t has a unique fixed point, denoted x t , which uniquely solves the fixed point equation (3.1).

We summary the basic properties of { x t }, which can be proved by the same method in [18]. We include its proof for the sake of completeness.

Proposition 3.1 Let { x t } be defined via (3.1). Then

  1. (i)

    { x t } is bounded for t(0,min{1, 2 γ ¯ τ γ l });

  2. (ii)

    lim t 0 x t T t x t =0 provided lim t 0 θ t =0;

  3. (iii)

    x t :(0,min{1, 2 γ ¯ τ γ l })H is locally Lipschitzian provided θ t :(0,min{1, 2 γ ¯ τ γ l })(0, A 1 ] is locally Lipschitzian, and λ t :(0,min{1, 2 γ ¯ τ γ l })[k,λ] is locally Lipschitzian;

  4. (iv)

    x t defines a continuous path from (0,min{1, 2 γ ¯ τ γ l }) into H provided θ t :(0,min{1, 2 γ ¯ τ γ l })(0, A 1 ] is continuous, and λ t :(0,min{1, 2 γ ¯ τ γ l })[k,λ] is continuous.

Proof (1) Let pFix(T). Observing Fix(T)=Fix( T t ) by Lemma 2.5(iii), we have

x t p = ( I θ t A ) T t x t + θ t [ t γ V x t + ( I t μ F ) T t x t ] p = ( I θ t A ) T t x t ( I θ t A ) T t p + θ t [ t γ V x t + ( I t μ F ) T t x t p ] + θ t ( I A ) p ( I θ t A ) T t x t ( I θ t A ) T t p + θ t t γ V x t + ( I t μ F ) T t x t p + θ t ( I A ) p = ( I θ t A ) T t x t ( I θ t A ) T t p + θ t ( I t μ F ) T t x t ( I t μ F ) T t p + t ( γ V x t μ F p ) + θ t I A p ( 1 θ t γ ¯ ) x t p + θ t [ ( 1 t τ ) x t p + t ( γ l x t p + γ V p μ F p ) ] + θ t I A p .

So, it follows that

x t p I A p + t γ V p μ F p γ ¯ 1 + t ( τ γ l ) I A p + t γ V p μ F p γ ¯ 1 I A p + γ V p μ F p γ ¯ 1 .

Hence { x t } is bounded and so are {V x t }, {T x t }, { T t x t }, and {F T t x t }.

(ii) By the definition of { x t }, we have

x t T t x t = θ t [ ( I A ) T t x t + t ( γ V x t μ F T t x t ) ] = θ t ( I A ) T t x t + t ( γ V x t μ F T t x t ) θ t I A T t x t + t γ V x t μ F T t x t 0 as  t 0 ,

by the boundedness of {V x t } and {F T t x t } in (i).

  1. (iii)

    Let t, t 0 (0,min{1, 2 γ ¯ τ γ l }), Noting that

    T t x t T t 0 x t 0 T t x t T t x t 0 + T t x t 0 T t 0 x t 0 x t x t 0 + | λ t λ t 0 | x t 0 T x t 0 ,

we calculate

x t x t 0 = ( I θ t A ) T t x t + θ t [ t γ V x t + ( I t μ F ) T t x t ] ( I θ t 0 A ) T t 0 x t 0 θ t 0 [ t 0 γ V x t 0 + ( I t 0 μ F ) T t 0 x t 0 ] ( I θ t A ) T t x t ( I θ t 0 A ) T t x t + ( I θ t 0 A ) T t x t ( I θ t 0 A ) T t 0 x t 0 + | θ t θ t 0 | t γ V x t + ( I t μ F ) T t x t + θ t 0 [ t γ V x t + ( I t μ F ) T t x t ] [ t 0 γ V x t 0 + ( I t 0 μ F ) T t 0 x t 0 ] | θ t θ t 0 | A T t x t + ( 1 θ t 0 γ ¯ ) T t x t T t 0 x t 0 + | θ t θ t 0 | t γ V x t + ( I t μ F ) T t x t + θ t 0 ( t t 0 ) γ V x t + t 0 γ ( V x t V x t 0 ) ( t t 0 ) μ F T t x t + ( I t 0 μ F ) T t x t ( I t 0 μ F ) T t 0 x t 0 | θ t θ t 0 | A T t x t + ( 1 θ t 0 γ ¯ ) [ x t x t 0 + | λ t λ t 0 | x t 0 T x t 0 ] + | θ t θ t 0 | [ T t x t + t ( γ V x t + μ F T t x t ) ] + θ t 0 [ ( γ V x t + μ F T t x t ) | t t 0 | + t 0 γ l x t x t 0 + ( 1 t 0 τ ) T t x t T t 0 x t 0 ] | θ t θ t 0 | A T t x t + ( 1 θ t 0 γ ¯ ) ( x t x t 0 + | λ t λ t 0 | x t 0 T x t 0 ) + | θ t θ t 0 | ( T t x t + γ V x t + μ F T t x t ) + θ t 0 ( γ V x t + μ F T t x t ) | t t 0 | + θ t 0 t 0 γ l x t x t 0 + θ t 0 ( 1 t 0 τ ) ( x t x t 0 + | λ t λ t 0 | x t 0 T x t 0 ) .

This implies that

x t x t 0 A T t x t + T t x t + γ V x t + μ F T t x t θ t 0 ( γ ¯ 1 + t 0 ( τ γ l ) ) | θ t θ t 0 | + γ V x t + μ F T t x t γ ¯ 1 + t 0 ( τ γ l ) | t t 0 | + [ 1 θ t 0 ( γ ¯ 1 + t 0 τ ) ] x t 0 T x t 0 θ t 0 ( γ ¯ 1 + t 0 ( τ γ l ) ) | λ t λ t 0 | .

Since θ t :(0,min{1, 2 γ ¯ τ γ l })(0, A 1 ] is locally Lipschitzian, and λ t :(0,min{1, 2 γ ¯ τ γ l })[k,λ] is locally Lipschitzian, x t is also locally Lipschitzian.

  1. (iv)

    From the last inequality in (iii), the result follows immediately. □

We prove the following theorem for strong convergence of the net { x t } as t0, which guarantees the existence of solutions of the variational inequality (3.2).

Theorem 3.1 Let the net { x t } be defined via (3.1). If lim t 0 θ t =0, then x t converges strongly to a fixed point x ˜ of T as t0, which solves the variational inequality (3.2). Equivalently, we have P Fix ( T ) (2IA) x ˜ = x ˜ .

Proof We first show the uniqueness of a solution of the variational inequality (3.2), which is indeed a consequence of the strong monotonicity of AI. In fact, since A is a strongly positive bounded linear operator with a coefficient γ ¯ (1,2), we know that AI is strongly monotone with a coefficient γ ¯ 1(0,1). Suppose that x ˜ Fix(T) and x ˆ Fix(T) both are solutions to (3.2). Then we have

( A I ) x ˜ , x ˜ x ˆ 0
(3.4)

and

( A I ) x ˆ , x ˆ x ˜ 0.
(3.5)

Adding up (3.4) and (3.5) yields

( A I ) x ˜ ( A I ) x ˆ , x ˜ x ˆ 0.

The strong monotonicity of AI implies that x ˜ = x ˆ and the uniqueness is proved.

Next, we prove that x t x ˜ as t0. Observing Fix(T)=Fix( T t ) by Lemma 2.5(iii), from (3.1), we write, for given pFix(T),

x t p = ( I θ t A ) T t x t ( I θ t A ) T t p + θ t [ t γ V x t + ( I t μ F ) T t x t p ] + θ t ( I A ) p = ( I θ t A ) ( T t x t T t p ) + θ t [ t ( γ V x t μ F p ) + ( I t μ F ) T t x t ( I t μ F ) p ] + θ t ( I A ) p ,

to derive

x t p 2 = ( I θ t A ) ( T t x t T t p ) , x t p + θ t [ t γ V x t μ F p , x t p + ( I t μ F ) T t x t ( I t μ F ) p , x t p ] + θ t ( I A ) p , x t p ( 1 θ t γ ¯ ) x t p 2 + θ t [ ( 1 t τ ) x t p 2 + t γ l x t p 2 + t γ V p μ F p , x t p ] + θ t ( I A ) p , x t p = [ 1 θ t ( γ ¯ 1 + t ( τ γ l ) ) ] x t p 2 + θ t ( t γ V p μ F p , x t p + ( I A ) p , x t p ) .

Therefore,

x t p 2 1 γ ¯ 1 + t ( τ γ l ) ( t γ V p μ F p , x t p + ( I A ) p , x t p ) .
(3.6)

Since { x t } is bounded as t0 (by Proposition 3.1(i)), we see that if { t n } is a subsequence in (0,min{1, 2 γ ¯ τ γ l }) such that t n 0 and x t n x , then from (3.6), we obtain x t n x . We show that x Fix(T). To this end, define S:HH by Sx=λx+(1λ)Tx, xH, for 0kλ<1. Then S is nonexpansive with Fix(S)=Fix(T) by Lemma 2.5(iii). Noticing that

S x t n x t n S x t n T t n x t n + T t n x t n x t n = ( λ λ t n ) x t n T x t n + T t n x t n x t n = λ λ t n 1 λ t n x t n T t n x t n + T t n x t n x t n = 1 + λ 2 λ t n 1 λ t n x t n T t n x t n ,

by Proposition 3.1(ii) and λ t n λ as t n 0, we have lim n (IS) x t n =0. Thus it follows from Lemma 2.4 that x Fix(S). By Lemma 2.5(iii), we get x Fix(T).

Finally, we prove that x is a solution of the variational inequality (3.2). Since

x t =(I θ t A) T t x t + θ t [ t γ V x t + ( I t μ F ) T t x t ] ,

we have

x t T t x t = θ t (IA) T t x t + θ t t(γV x t μF T t x t ).

Since T t is nonexpansive, I T t is monotone. So, from the monotonicity of I T t , it follows that, for pFix(T)=Fix( T t ),

0 ( I T t ) x t ( I T t ) p , x t p = ( I T t ) x t , x t p = θ t ( I A ) T t x t , x t p + θ t t γ V x t μ F T t x t , x t p = θ t ( I A ) x t , x t p + θ t ( I A ) ( T t I ) x t , x t p + θ t t γ V x t μ F T t x t , x t p .

This implies that

( A I ) x t , x t p ( I A ) ( T t I ) x t , x t p +tγV x t μF T t x t , x t p.
(3.7)

Now, replacing t in (3.7) with t n and letting n, noticing the boundedness of {γV x t n μF T t n x t n } and the fact that (IA)( T t n I) x t n 0 as n by Proposition 3.1(ii), we obtain

( A I ) x , x p 0.

That is, x Fix(T) is a solution of the variational inequality (3.2); hence x = x ˜ by uniqueness. In summary, we have shown that each cluster point of { x t } (at t0) equals x ˜ . Therefore x t x ˜ as t0.

The variational inequality (3.2) can be rewritten as

( 2 I A ) x ˜ x ˜ , x ˜ p 0,pFix(T).

Recalling Lemma 2.5(i) and (2.1), this is equivalent to the fixed point equation

P Fix ( T ) (2IA) x ˜ )= x ˜ .

 □

Taking F=I, μ=1 and γ=1 in Theorem 3.1, we get

Corollary 3.1 Let { x t } be defined by

x t =(I θ t A) T t x t + θ t [ t V x t + ( 1 t ) T t x t ] .

If lim t 0 θ t =0, then { x t } converges strongly as t0 to a fixed point x ˜ of T, which is the unique solution of variational inequality (3.2).

First, we prove the following result in order to establish strong convergence of the sequence { x n } generated by the general composite explicit scheme (3.3).

Theorem 3.2 Let { x n } be the sequence generated by the explicit scheme (3.3), where { α n } and { β n } satisfy the following condition:

(C1) { α n }[0,1] and { β n }(0,1], α n 0 and β n 0 as n.

Let LIM be a Banach limit. Then

LIM n ( ( A I ) x ˜ , x ˜ x n ) 0,

where x ˜ = lim t 0 + x t with x t being defined by

x t =(I θ t A)S x t + θ t [ t γ V x t + ( I t μ F ) S x t ] ,
(3.8)

where S:HH is defined by Sx=λx+(1λ)Tx for 0kλ<1.

Proof First, note that from the condition (C1), without loss of generality, we assume that 0< β n A 1 for all n0.

Let { x t } be the net generated by (3.8). Since S is a nonexpansive mapping on H, by Theorem 3.1 with T t =S and Lemma 2.5, there exists lim t 0 x t Fix(S)=Fix(T). Denote it by x ˜ . Moreover, x ˜ is the unique solution of the variational inequality (3.2). From Proposition 3.1(i) with T t =S, we know that { x t } is bounded, so are {V x t } and {FS x t }.

First of all, let us show that { x n } is bounded. To this end, take pFix(T)=Fix( T n ), Then it follows that

y n p = α n γ V x n + ( I α n μ F ) T n x n p = α n ( γ V x n μ F p ) + ( I α n μ F ) T n x n ( I α n μ F ) T n p ( 1 α n ( τ γ l ) ) x n p + α n γ V p μ F p ,

and hence

x n + 1 p = ( I β n A ) T n x n + β n y n p = ( I β n A ) T n x n ( I β n A ) T n p + β n ( y n p ) + β n ( I A ) p ( I β n A ) T n x n ( I β n A ) T n p + β n y n p + β n I A p ( 1 β n γ ¯ ) x n p + β n [ ( 1 α n ( τ γ l ) ) x n p + α n γ V p μ F p ] + β n I A p ( 1 β n ( γ ¯ 1 ) ) x n p + β n ( γ V p μ F p + I A p ) = ( 1 β n ( γ ¯ 1 ) ) x n p + β n ( γ ¯ 1 ) γ V p μ F p + I A p γ ¯ 1 max { x n p , γ V p μ F p + I A p γ ¯ 1 } .

By induction

x n pmax { x 0 p , γ V p μ F p + I A p γ ¯ 1 } ,n0.

This implies that { x n } is bounded and so are {T x n }, { T n x n }, {F T n x n }, {V x n }, and { y n }. As a consequence, with the control condition (C1), we get

x n + 1 T n x n = β n y n A T n x n 0(n),

and

S x t x n + 1 S x t S x n + S x n T n x n + T n x n x n + 1 x t x n + | λ λ n | x n T x n + T n x n x n + 1 = x t x n + e n ,
(3.9)

where e n =|λ λ n | x n T x n + x n + 1 T n x n 0 as n. Also observing that A is strongly positive, we have

A x t A x n , x t x n = A ( x t x n ) , x t x n γ ¯ x t x n 2 .
(3.10)

Now, by (3.8), we have

x t x n + 1 = ( I θ t A ) S x t + θ t [ t γ V x t + ( I t μ F ) S x t ] x n + 1 = ( I θ n A ) S x t ( I θ t A ) x n + 1 + θ t [ t γ V x t + ( I t μ F ) S x t A x n + 1 ] .

Applying Lemma 2.1, we have

x t x n + 1 2 ( I θ t A ) S x t ( I θ t A ) x n + 1 2 + 2 θ t S x t t ( μ F S x t γ V x t ) A x n + 1 , x t x n + 1 ( 1 θ t γ ¯ ) 2 S x t x n + 1 2 + 2 θ t S x t x t , x t x n + 1 2 θ t t μ F S x t γ V x t , x t x n + 1 + 2 θ t x t A x n + 1 , x t x n + 1 .
(3.11)

Using (3.9) and (3.10) in (3.11), we obtain

x t x n + 1 2 ( 1 θ t γ ¯ ) 2 S x t x n + 1 2 + 2 θ t S x t x t , x t x n + 1 + 2 θ t t γ V x t μ F S x t , x t x n + 1 + 2 θ t x t A x n + 1 , x t x n + 1 ( 1 θ t γ ¯ ) 2 ( x t x n + e n ) 2 + 2 θ t S x t x t x t x n + 1 + 2 θ t t γ V x t μ F S x t x t x n + 1 + 2 θ t x t A x n + 1 , x t x n + 1 = ( θ t 2 γ ¯ 2 θ t ) γ ¯ x t x n 2 + x t x n 2 + ( 1 θ t γ ¯ ) 2 ( 2 x t x n e n + e n 2 ) + 2 θ t S x t x t x t x n + 1 + 2 θ t t γ V x t μ F S x t x t x n + 1 + 2 θ t x t A x n + 1 , x t x n + 1 ( θ t 2 γ ¯ 2 θ t ) A x t A x n , x t x n + x t x n 2 + ( 1 θ t γ ¯ ) 2 ( 2 x t x n e n + e n 2 ) + 2 θ t S x t x t x t x n + 1 + 2 θ t t γ V x t μ F S x t x t x n + 1 + 2 θ t x t A x n + 1 , x t x n + 1 = θ t 2 γ ¯ A x t A x n , x t x n + x t x n 2 + ( 1 θ t γ ¯ ) 2 ( 2 x t x n e n + e n 2 ) + 2 θ t S x t x t x t x n + 1 + 2 θ t t γ V x t μ F ( S x t ) x t x n + 1 + 2 θ t [ x t A x n + 1 , x t x n + 1 A x t A x n , x t x n ] = θ t 2 γ ¯ A ( x t x n ) , x t x n + x t x n 2 + ( 1 θ t γ ¯ ) 2 ( 2 x t x n e n + e n 2 ) + 2 θ t S x t x t x t x n + 1 + 2 θ t t γ V x t μ F S x t x t x n + 1 + 2 θ t [ ( I A ) x t , x t x n + 1 + A ( x t x n + 1 ) , x t x n + 1 A ( x t x n ) , x t x n ] .
(3.12)

Applying the Banach limit LIM to (3.12), together with lim n e n =0, we have

LIM n ( x t x n + 1 2 ) θ t 2 γ ¯ LIM n ( A ( x t x n ) , x t x n ) + LIM n ( x t x n 2 ) + 2 θ t S x t x t LIM n ( x t x n + 1 ) + 2 θ t t γ V x t μ F S x t LIM n ( x t x n + 1 ) + 2 θ t [ LIM n ( ( I A ) x t , x t x n + 1 ) + LIM n ( A ( x t x n + 1 ) , x t x n + 1 ) LIM n ( A ( x t x n ) , x t x n ) ] .
(3.13)

Using the property LIM n ( a n )= LIM n ( a n + 1 ) of the Banach limit in (3.13), we obtain

LIM n ( ( A I ) x t , x t x n ) = LIM n ( ( A I ) x t , x t x n + 1 ) θ t γ ¯ 2 LIM n ( A ( x t x n ) , x t x n ) + 1 2 θ t [ LIM n ( x t x n 2 ) LIM n ( x t x n + 1 2 ) ] + S x t x t LIM n ( x t x n ) + t γ V x t μ F S x t LIM n ( x t x n ) + LIM n ( A ( x t x n + 1 ) , x t x n + 1 ) LIM n ( A ( x t x n ) , x t x n ) = θ t γ ¯ 2 LIM n ( A ( x t x n ) , x t x n ) + S x t x t LIM n ( x t x n ) + t γ V x t μ F S x t LIM n ( x t x n ) .
(3.14)

Since

θ t A ( x t x n ) , x t x n θ t A x t x n 2 θ t K 0 ( as  t 0 ) ,
(3.15)

where A x t x n 2 K,

S x t x t 0,andtγV x t μFS x t 0(as t0),
(3.16)

we conclude from (3.14)-(3.16) that

LIM n ( ( A I ) x ˜ , x ˜ x n ) lim sup t 0 LIM n ( ( A I ) x t , x t x n ) lim sup t 0 θ t γ ¯ 2 LIM n ( A ( x t x n ) , x t x n ) + lim sup t 0 S x t x t LIM n ( x t x n ) + lim sup t 0 t γ V x t μ F S x t LIM n ( x t x n ) = 0 .

This completes the proof. □

Now, using Theorem 3.2, we establish strong convergence of the sequence { x n } generated by the general composite explicit scheme (3.3) to a fixed point x ˜ of T, which is also the unique solution of the variational inequality (3.2).

Theorem 3.3 Let { x n } be the sequence generated by the explicit scheme (3.3), where { α n } and { β n } satisfy the following conditions:

(C1) { α n }[0,1] and { β n }(0,1], α n 0 and β n 0 as n;

(C2) n = 0 β n =.

If { x n } is weakly asymptotically regular, then { x n } converges strongly to x ˜ Fix(T), which is the unique solution of the variational inequality (3.2).

Proof First, note that from the condition (C1), without loss of generality, we assume that α n τ<1 and 2 β n ( γ ¯ 1 ) 1 β n <1 for all n0.

Let x t be defined by (3.8), that is,

x t =(I θ t A)S x t + θ t [ S x t t ( μ F ( S x t ) γ V x t ) ]

for t(0,min{1, 2 γ ¯ τ γ l }), where Sx=λx+(1λ)Tx for 0kλ<1, and lim t 0 x t := x ˜ Fix(S)=Fix(T) (by using Theorem 3.1 and Lemma 2.5(iii)). Then x ˜ is the unique solution of the variational inequality (3.2).

We divide the proof into several steps as follows.

Step 1. We see that

x n pmax { x 0 p , γ V p μ F p + I A p γ ¯ 1 } ,n0,

for all pFix(T) as in the proof of Theorem 3.2. Hence { x n } is bounded and so are {T x n }, { T n x n }, {F T n x n }, {V x n }, and { y n }.

Step 2. We show that lim sup n (IA) x ˜ , x n x ˜ 0. To this end, put

a n := ( A I ) x ˜ , x ˜ x n ,n0.

Then Theorem 3.2 implies that LIM n ( a n )0 for any Banach limit LIM. Since { x n } is bounded, there exists a subsequence { x n j } of { x n } such that

lim sup n ( a n + 1 a n )= lim j ( a n j + 1 a n j )

and x n j vH. This implies that x n j + 1 v since { x n } is weakly asymptotically regular. Therefore, we have

w lim j ( x ˜ x n j + 1 )=w lim j ( x ˜ x n j )=( x ˜ v),

and so

lim sup n ( a n + 1 a n )= lim j ( A I ) x ˜ , ( x ˜ x n j + 1 ) ( x ˜ x n j ) =0.

Then Lemma 2.2 implies that lim sup n a n 0, that is,

lim sup n ( I A ) x ˜ , x n x ˜ = lim sup n ( A I ) x ˜ , x ˜ x n 0.

Step 3. We show that lim n x n x ˜ =0. By using (3.3) and T n x ˜ = x ˜ , we have

y n x ˜ =(I α n μF) T n x n (I α n μF) T n x ˜ + α n (γV x n μF x ˜ ),

and

x n + 1 x ˜ =(I β n A)( T n x n T n x ˜ )+ β n ( y n x ˜ )+ β n (IA) x ˜ .

Applying Lemma 2.1, Lemma 2.6 and Lemma 2.7, we obtain

y n x ˜ 2 = ( I μ α n F ) T n x n ( I μ α n F ) T n x ˜ + α n ( γ V x n μ F x ˜ ) 2 ( I μ α n F ) T n x n ( I μ α n F ) T n x ˜ 2 + 2 α n γ V x n μ F x ˜ , y n x ˜ ( 1 α n τ ) 2 x n x ˜ 2 + 2 α n γ V x n μ F x ˜ y n x ˜ x n x ˜ 2 + 2 α n γ V x n μ F x ˜ y n x ˜ ,

and hence

x n + 1 x ˜ 2 = ( I β n A ) ( T n x n T n x ˜ ) + β n ( y n x ˜ ) + β n ( I A ) x ˜ 2 ( I β n A ) ( T n x n T n x ˜ ) 2 + 2 β n y n x ˜ , x n + 1 x ˜ + 2 β n ( I A ) x ˜ , x n + 1 x ˜ ( 1 β n γ ¯ ) 2 x n x ˜ 2 + 2 β n y n x ˜ x n + 1 x ˜ + 2 β n ( I A ) x ˜ , x n + 1 x ˜ ( 1 β n γ ¯ ) 2 x n x ˜ 2 + β n ( y n x ˜ 2 + x n + 1 x ˜ 2 ) + 2 β n ( I A ) x ˜ , x n + 1 x ˜ ( 1 β n γ ¯ ) 2 x n x ˜ 2 + β n [ x n x ˜ 2 + 2 α n γ V x n μ F x ˜ y n x ˜ ] + β n x n + 1 x ˜ 2 + 2 β n ( I A ) x ˜ , x n + 1 x ˜ = [ ( 1 β n γ ¯ ) 2 + β n ] x n x ˜ 2 + 2 α n β n γ V x n μ F x ˜ y n x ˜ + β n x n + 1 x ˜ 2 + 2 β n ( I A ) x ˜ , x n + 1 x ˜ .
(3.17)

It then follows from (3.17) that

x n + 1 x ˜ 2 ( 1 β n γ ¯ ) 2 + β n 1 β n x n x ˜ 2 + β n 1 β n [ 2 α n γ V x n μ F x ˜ y n x ˜ + 2 ( I A ) x ˜ , x n + 1 x ˜ ] = ( 1 2 β n ( γ ¯ 1 ) 1 β n ) x n x ˜ 2 + 2 β n ( γ ¯ 1 ) 1 β n 1 2 ( γ ¯ 1 ) [ 2 α n γ V x n μ F x ˜ y n x ˜ + β n γ ¯ 2 x n x ˜ 2 + 2 ( I A ) x ˜ , x n + 1 x ˜ ] = ( 1 ω n ) x n x ˜ 2 + ω n δ n ,

where

ω n = 2 β n ( γ ¯ 1 ) 1 β n and δ n = 1 2 ( γ ¯ 1 ) [ 2 α n γ V x n μ F x ˜ y n x ˜ + β n γ ¯ 2 x n x ˜ 2 + 2 ( I A ) x ˜ , x n + 1 x ˜ ] .

It can easily be seen from Step 2 and conditions (C1) and (C2) that ω n 0, n = 0 ω n = and lim sup n δ n 0. From Lemma 2.3 with r n =0, we conclude that lim n x n x ˜ =0. This completes the proof. □

Corollary 3.2 Let { x n } be the sequence generated by the explicit scheme (3.3). Assume that the sequence { α n } and { β n } satisfy the conditions (C1) and (C2) in Theorem  3.3. If { x n } is asymptotically regular, then { x n } converges strongly to x ˜ Fix(T), which is the unique solution of the variational inequality (3.2).

Putting μ=1, F=I and γ=1 in Theorem 3.3, we obtain the following.

Corollary 3.3 Let { x n } be generated by the following iterative scheme:

{ y n = α n V x n + ( 1 α n ) T n x n , x n + 1 = ( I β n A ) T n x n + β n y n , n 0 .

Assume that the sequence { α n } and { β n } satisfy the conditions (C1) and (C2) in Theorem  3.3. If { x n } is weakly asymptotically regular, then { x n } converges strongly to x ˜ Fix(T), which is the unique solution of the variational inequality (3.2).

Putting α n =0, n0 in Corollary 3.3, we get the following.

Corollary 3.4 Let { x n } be generated by the following iterative scheme:

x n + 1 =(I β n A) T n x n + β n T n x n ,n0.

Assume that the sequence { β n } satisfies the conditions (C1) and (C2) in Theorem  3.3 with α n =0, n0. If { x n } is weakly asymptotically regular, then { x n } converges strongly to x ˜ Fix(T), which is the unique solution of the variational inequality (3.2).

Remark 3.1 If { α n }, { β n } in Corollary 3.2 and { λ n } in T n satisfy conditions (C2) and

(C3) n = 0 | α n + 1 α n |< and n = 0 | β n + 1 β n |<; or

(C4) n = 0 | α n + 1 α n |< and lim n β n β n + 1 =1 or, equivalently, lim n α n α n + 1 α n + 1 =0 and lim n β n β n + 1 β n + 1 =0; or,

(C5) n = 0 | α n + 1 α n |< and | β n + 1 β n |o( β n + 1 )+ σ n , n = 0 σ n < (the perturbed control condition);

(C6) n = 0 | λ n + 1 λ n |<,

then the sequence { x n } generated by (3.3) is asymptotically regular. Now we give only the proof in the case when { α n }, { β n }, and { λ n } satisfy the conditions (C2), (C5), and (C6). By Step 1 in the proof of Theorem 3.3, there exists a constant M>0 such that, for all n0,

x n T x n M,μF T n x n +γV x n M,andA T n x n + y n M.

Next, we notice that

T n x n T n 1 x n 1 T n x n T n x n 1 + T n x n 1 T n 1 x n 1 x n x n 1 + | λ n λ n 1 | x n 1 T x n 1 x n x n 1 + | λ n λ n 1 | M .

So we obtain, for all n0,

y n y n 1 = α n γ ( V x n V x n 1 ) + γ ( α n α n 1 ) V x n 1 + ( I α n μ F ) T n x n ( I α n μ F ) T n 1 x n 1 + μ ( α n α n 1 ) F T n 1 x n 1 ( 1 α n ( τ γ l ) ) T n x n T n 1 x n 1 + | α n α n 1 | ( γ V x n 1 + μ F T n 1 x n 1 ) ( 1 α n ( τ γ l ) ) ( x n x n 1 + | λ n λ n 1 | M ) + | α n α n 1 | M ,

and hence

x n + 1 x n = ( I β n A ) T n x n + β n y n ( I β n 1 A ) T n 1 x n 1 β n 1 y n 1 ( I β n A ) ( T n x n T n 1 x n 1 ) + | β n β n 1 | A T n 1 x n 1 + β n y n y n 1 + | β n β n 1 | y n 1 ( 1 β n γ ¯ ) T n x n T n 1 x n 1 + β n ( 1 α n ( τ γ l ) ) ( x n x n 1 + | λ n λ n 1 | M ) + β n | α n α n 1 | M + | β n β n 1 | ( A T n 1 x n 1 + y n 1 ) ( 1 β n γ ¯ ) ( x n x n 1 + | λ n λ n 1 | M ) + β n [ ( 1 α n ( τ γ l ) ) ( x n x n 1 + | λ n λ n 1 | M ) + | α n α n 1 | M ] + | β n β n 1 | M ( 1 β n γ ¯ ) x n x n 1 + | λ n λ n 1 | M + β n x n x n 1 + | λ n λ n 1 | M + | α n α n 1 | M + | β n β n 1 | M = ( 1 β n ( γ ¯ 1 ) ) x n x n 1 + | β n β n 1 | M + 2 | λ n λ n 1 | M + | α n α n 1 | M ( 1 β n ( γ ¯ 1 ) ) x n x n 1 + ( o ( β n ) + σ n 1 ) M + | α n α n 1 | M + 2 | λ n λ n 1 | M .
(3.18)

By taking s n + 1 = x n + 1 x n , ω n = β n ( γ ¯ 1), ω n δ n =Mo( β n ) and r n =(| α n α n 1 |+ σ n 1 +2| λ n λ n 1 |)M, from (3.18) we have

s n + 1 (1 ω n ) s n + ω n δ n + r n .

Hence, by the conditions (C2), (C5), (C6), and Lemma 2.3, we obtain

lim n x n + 1 x n =0.

In view of this observation, we have the following.

Corollary 3.5 Let { x n } be the sequence generated by the explicit scheme (3.3), where the sequences { α n }, { β n }, and { λ n } satisfy the conditions (C1), (C2), (C5), and (C6) (or the conditions (C1), (C2), (C3) and (C6), or the conditions (C1), (C2), (C4), and (C6)). Then { x n } converges strongly to x ˜ Fix(T), which is the unique solution of the variational inequality (3.2).

Remark 3.2 (1) Our results improve and extend the corresponding results of Ceng et al. [18] in the following respects:

  1. (a)

    The nonexpansive mapping S:HH in [18] is extended to the case of a k-strictly pseudocontractive mapping T:HH.

  2. (b)

    The contractive mapping f in [18] with constant α(0,1) is extended to the case of a Lipschitzian mapping V with constant l0.

  3. (c)

    The range 0<γα<τ=μ(η μ ρ 2 2 ) in [18] is extended to the case of range 0<γl<τ=1 1 μ ( 2 η μ ρ 2 ) . (For this fact, see Remark 3.1 of [17].)

(2) We point out that the condition (C3) n = 0 | α n + 1 α n |< and n = 0 | β n + 1 β n |< in [[18], Theorem 3.2] is relaxed to the case of the weak asymptotic regularity on { x n } in Theorem 3.3.

(3) The condition (C5) on { β n } in Corollary 3.5 is independent of condition (C3) or (C4) in Remark 3.1, which was imposed in Theorem 3.2 of Ceng et al. [18]. For this fact, see [24, 25].

(4) Our results also complement and develop the corresponding ones given by Cho et al. [5] and Jung [68] for the strictly pseudocontractive mapping as well as Yamada [12], Marino and Xu [13], Tian [15] and Ceng et al. [17] for the nonexpansive mapping.

(5) For several iterative schemes based on hybrid steepest-descent method for generalized mixed equilibrium problems, variational inequality problems, and fixed point problems for strictly pseudocontractive mappings, we can also refer to [2632] and the references therein.