Appendix A: Proof of sign relations in D=7 case
In this section we will show that no black hole bomb exists for D=7 extremal RN black hole under charged massive scalar perturbation. In this case, the black hole horizon is located at \(r_+=r_-=r_h=m^{1/4}\). The bound state condition is \(\omega <\mu \), and superradiance condition is \(\omega <e\Phi _h=c_D e=\sqrt{5/8}e\).
The denominator of the derivative of effective potential \(V'(r)\) is \(2 r^3(r^4-m)^5\). The numerator of \(V'\) is
$$\begin{aligned} n_7(r)= & {} a_5 r^{20}+a'_4 r^{18}+a_4 r^{16}+a'_3 r^{14}+a_3 r^{12}\\&+a'_2 r^{10}+a_2 r^8+a_1 r^4+a_0, \end{aligned}$$
where
$$\begin{aligned} a_5= & {} -(4\lambda _l+15),a'_4=-16m(\mu ^2+c_D e \omega -2\omega ^2),\nonumber \\ a_4= & {} m(75-4\lambda _l),\nonumber \\ a'_3= & {} 16m^2(c_D^2e^2-3c_D e \omega +2\mu ^2),\nonumber \\ a_3= & {} 10m^2(2\lambda _l-15),\nonumber \\ a'_2= & {} 16m^3(c_D^2e^2-\mu ^2),\nonumber \\ a_2= & {} 6m^3(25-2\lambda _l),a_1=-75m^4,a_0=15m^3. \end{aligned}$$
(A.1)
We can see \(a_5<0\). Given the bound state condition \(\omega <\mu \) and superradiance condition \(\omega <c_D e\), it is easy to check \(a'_4<0\). As explained in the main content of the paper, we are interested in the numerator of \(V'\). Change the variable r to \(z=r-r_h\), then the numerator of \(V'\) can be written as
$$\begin{aligned} n_7(z)=\sum _{i=0}^{20}b_i z^i. \end{aligned}$$
(A.2)
Now let’s consider the signs of the coefficients or the sign relations between adjacent coefficients in the sequence \((b_{20},b_{19},..,b_1,b_0)\).
Because \(a_5<0, a'_4<0\), it is easy to see that
$$\begin{aligned} b_{20}= & {} a_5=-(4\lambda _l+15)<0,b_{19}=a_5 C_{20}^1 r_h<0, \nonumber \\ b_{18}= & {} a_5 C_{20}^2 r_h^2+a'_4<0, b_{17}=a_5 C_{20}^3 r_h^3+a'_4 C_{18}^1r_h<0,\nonumber \\ b_{16}= & {} a_5 C_{20}^4 r_h^4+a'_4 C_{18}^2r_h^2+a_4\nonumber \\= & {} a'_4 C_{18}^2r_h^2-8m(9075+2423\lambda _l)<0,\nonumber \\ b_{15}= & {} a_5 C_{20}^5 r_h^5+a'_4 C_{18}^3r_h^3+a_4C_{16}^1 r_h\nonumber \\= & {} a'_4 C_{18}^3r_h^3-320m^{5/4}(723+194\lambda _l)<0, \nonumber \\ b_0= & {} a_5 r_h^{20}+a'_4 r_h^{18} + a_4 r_h^{16} + a'_3 r_h^{14} \nonumber \\&+ a_3 r_h^{12} + a'_2 r_h^{10} + a_2 r_h^8 + a_1 r_h^4 + a_0 \nonumber \\= & {} 32 m^{\frac{11}{2}} (\omega -c_D e)^2>0. \end{aligned}$$
(A.3)
The signs of the other coefficients can not be judged as above. These coefficients are listed as follows
$$\begin{aligned} b_{14}= & {} a_5 C_{20}^{14} r_h^6+a'_4 C_{18}^{14}r_h^4+a_4C_{16}^{14} r_h^2+a'_3, \\ b_{13}= & {} a_5 C_{20}^{13} r_h^7+a'_4 C_{18}^{13}r_h^5+a_4C_{16}^{13} r_h^3+a'_3C_{14}^{13} r_h,\\ b_{12}= & {} a_5 C_{20}^{12} r_h^8+a'_4 C_{18}^{12}r_h^6+a_4C_{16}^{12} r_h^4+a'_3C_{14}^{12} r_h^2+a_3,\\ b_{11}= & {} a_5 C_{20}^{11} r_h^9+a'_4 C_{18}^{11}r_h^7+a_4C_{16}^{11} r_h^5\\&+a'_3C_{14}^{11} r_h^3+a_3C_{12}^{11} r_h,\\ b_{10}= & {} a_5 C_{20}^{10} r_h^{10}+a'_4 C_{18}^{10}r_h^8+a_4C_{16}^{10} r_h^6\\&+a'_3C_{14}^{10} r_h^4+a_3C_{12}^{10} r_h^2+a'_2,\\ b_{9}= & {} a_5 C_{20}^{9} r_h^{11}+a'_4 C_{18}^{9}r_h^{9}+a_4C_{16}^{9} r_h^{7}+a'_3C_{14}^9 r_h^5\\&+a_3C_{12}^9 r_h^3+a'_2 C_{10}^9 r_h,\\ b_{8}= & {} a_5 C_{20}^{8} r_h^{12}+a'_4 C_{18}^{8}r_h^{10}+a_4C_{16}^{8} r_h^{8}+a'_3C_{14}^{8} r_h^{6}\\&+a_3C_{12}^{8} r_h^{4}+a'_2 C_{10}^8 r_h^2+a_2,\\ b_{7}= & {} a_5 C_{20}^{7} r_h^{13}+a'_4 C_{18}^{7}r_h^{11}+a_4C_{16}^{7} r_h^{9}+a'_3C_{14}^{7} r_h^{7}\\&+a_3C_{12}^{7} r_h^{5}+a'_2 C_{10}^7 r_h^3+a_2C_8^7 r_h,\\ b_{6}= & {} a_5 C_{20}^{6} r_h^{14}+a'_4 C_{18}^{6}r_h^{12}+a_4C_{16}^{6} r_h^{10}+a'_3C_{14}^{6} r_h^{8}\\&+a_3C_{12}^{6} r_h^{6}+a'_2 C_{10}^6 r_h^4+a_2C_8^6 r_h^2,\\ b_{5}= & {} a_5 C_{20}^{5} r_h^{15}+a'_4 C_{18}^{5}r_h^{13}+a_4C_{16}^{5} r_h^{11}+a'_3C_{14}^{5} r_h^{9}\\&+a_3C_{12}^{5} r_h^{7}+a'_2 C_{10}^5 r_h^5+a_2C_8^5 r_h^3,\\ b_{4}= & {} a_5 C_{20}^{4} r_h^{16}+a'_4 C_{18}^{4}r_h^{14}+a_4C_{16}^{4} r_h^{12}+a'_3C_{14}^{4} r_h^{10}\\&+a_3C_{12}^{4} r_h^{8}+a'_2 C_{10}^4 r_h^6+a_2C_8^4 r_h^4+a_1,\\ b_{3}= & {} a_5 C_{20}^{3} r_h^{17}+a'_4 C_{18}^{3}r_h^{15}+a_4C_{16}^{3} r_h^{13}+a'_3C_{14}^{3} r_h^{11}\\&+a_3C_{12}^{3} r_h^{9}+a'_2 C_{10}^3 r_h^7+a_2C_8^3 r_h^5+a_1C_4^3r_h,\\ b_{2}= & {} a_5 C_{20}^{2} r_h^{18}+a'_4 C_{18}^{2}r_h^{16}+a_4C_{16}^{2} r_h^{14}+a'_3C_{14}^{2} r_h^{12}\\&+a_3C_{12}^{2} r_h^{10}+a'_2 C_{10}^2 r_h^8+a_2C_8^2 r_h^6+a_1C_4^2r_h^2,\\ b_{1}= & {} a_5 C_{20}^{1} r_h^{19}+a'_4 C_{18}^{1}r_h^{17}+a_4C_{16}^{1} r_h^{15}\\&+a'_3C_{14}^{1} r_h^{13}+a_3C_{12}^{1} r_h^{11}\\&+a'_2 C_{10}^1 r_h^9+a_2C_8^1 r_h^7+a_1C_4^1r_h^3. \end{aligned}$$
Then we will normalized the above coefficients with positive factors and consider the sign relations between pairs of adjacent normalized coefficients. For adjacent coefficients \((b_{13},b_{14})\)
$$\begin{aligned}&\tilde{b}_{13}-\tilde{b}_{14}=\frac{b_{13}}{2C_{14}^{13}+C_{18}^{13}}-\frac{b_{14}}{2C_{14}^{14}+C_{18}^{14}} \nonumber \\&\quad =\frac{64m^5[2907150 + 743215 \lambda _l + 1071\sqrt{m} c_D e(c_D e -\omega ) + 4284 \sqrt{m} (\mu ^2 - \omega ^2)]}{3290119}. \end{aligned}$$
(A.4)
Given the bound state condition \(\omega <\mu \) and superradiance condition \(\omega <c_D e\), we have
$$\begin{aligned} \tilde{b}_{13}-\tilde{b}_{14}>0,~ \text {sign}(b_{13})\geqslant \text {sign}(b_{14}). \end{aligned}$$
(A.5)
Similarly, we have the following differences between adjacent coefficients
$$\begin{aligned}&\tilde{b}_{12}-\tilde{b}_{13}=\frac{b_{12}}{2C_{14}^{12}+C_{18}^{12}}-\frac{b_{13}}{2C_{14}^{13}+C_{18}^{13}}\nonumber \\&\quad =\frac{2m^5[53035800 + 13044565 \lambda _l + 74256\sqrt{m} c_D e(c_D e -\omega ) + 297024 \sqrt{m} (\mu ^2 - \omega ^2)]}{2877511}, \end{aligned}$$
(A.6)
$$\begin{aligned}&\tilde{b}_{11}-\tilde{b}_{12}=\frac{b_{11}}{2C_{14}^{11}+C_{18}^{11}}-\frac{b_{12}}{2C_{14}^{12}+C_{18}^{12}}\nonumber \\&\quad =\frac{4m^5[19169400+ 4472699 \lambda _l + 74256\sqrt{m} c_D e(c_D e -\omega ) + 297024 \sqrt{m} (\mu ^2 - \omega ^2)]}{2933749}, \end{aligned}$$
(A.7)
$$\begin{aligned}&\tilde{b}_{10}-\tilde{b}_{11}=\frac{b_{10}}{2C_{14}^{10}+C_{18}^{10}-C_{10}^{10}}-\frac{b_{11}}{2C_{14}^{11}+C_{18}^{11}}\nonumber \\&\quad =\frac{2m^5[41 (44806020 + 9870121 \lambda _l) + 15960828\sqrt{m} c_D e(c_D e -\omega ) + 63648000 \sqrt{m} (\mu ^2 - \omega ^2)]}{186193371}, \end{aligned}$$
(A.8)
$$\begin{aligned}&\tilde{b}_{9}-\tilde{b}_{10}=\frac{b_{9}}{2C_{14}^{9}+C_{18}^{9}-C_{10}^{9}}-\frac{b_{10}}{2C_{14}^{10}+C_{18}^{10}-C_{10}^{10}}\nonumber \\&\quad =\frac{16m^5[387480660 +81912199\lambda _l + 6557980\sqrt{m} c_D e(c_D e -\omega ) + 25826944 \sqrt{m} (\mu ^2 - \omega ^2)]}{401260671}, \end{aligned}$$
(A.9)
$$\begin{aligned}&\tilde{b}_{8}-\tilde{b}_{9}=\frac{b_{8}}{2C_{14}^{8}+C_{18}^{8}-C_{10}^{8}}-\frac{b_{9}}{2C_{14}^{9}+C_{18}^{9}-C_{10}^{9}}\nonumber \\&\quad =\frac{8m^5[660709500 +140835979\lambda _l + 20110948\sqrt{m} c_D e(c_D e -\omega ) + 76702912 \sqrt{m} (\mu ^2 - \omega ^2)]}{435985911}, \end{aligned}$$
(A.10)
$$\begin{aligned}&\tilde{b}_{7}-\tilde{b}_{8}=\frac{b_{7}}{2C_{14}^{7}+C_{18}^{7}-C_{10}^{7}}-\frac{b_{8}}{2C_{14}^{8}+C_{18}^{8}-C_{10}^{8}}\nonumber \\&\quad =\frac{16m^5[45585900 +10751383\lambda _l + 2460276\sqrt{m} c_D e(c_D e -\omega ) + 8783424 \sqrt{m} (\mu ^2 - \omega ^2)]}{79898433},\end{aligned}$$
(A.11)
$$\begin{aligned}&\tilde{b}_{6}-\tilde{b}_{7}=\frac{b_{6}}{2C_{14}^{6}+C_{18}^{6}-C_{10}^{6}}-\frac{b_{7}}{2C_{14}^{7}+C_{18}^{7}-C_{10}^{7}}\nonumber \\&\quad =\frac{2m^5[15225600 +4608134\lambda _l +1558011\sqrt{m} c_D e(c_D e -\omega ) + 4938024 \sqrt{m} (\mu ^2 - \omega ^2)]}{4893315},\end{aligned}$$
(A.12)
$$\begin{aligned}&\tilde{b}_{5}-\tilde{b}_{6}=\frac{b_{5}}{2C_{14}^{5}+C_{18}^{5}-C_{10}^{5}}-\frac{b_{6}}{2C_{14}^{6}+C_{18}^{6}-C_{10}^{6}}\nonumber \\&\quad =\frac{m^5[116640 +57406\lambda _l +27363\sqrt{m} c_D e(c_D e -\omega ) + 71400 \sqrt{m} (\mu ^2 - \omega ^2)]}{33495},\end{aligned}$$
(A.13)
$$\begin{aligned}&\tilde{b}_{4}-\tilde{b}_{5}=\frac{b_{4}}{2C_{14}^{4}+C_{18}^{4}-C_{10}^{4}}-\frac{b_{5}}{2C_{14}^{5}+C_{18}^{5}-C_{10}^{5}}\nonumber \\&\quad =\frac{m^5[582240 +744130\lambda _l +497889\sqrt{m} c_D e(c_D e -\omega ) + 968184 \sqrt{m} (\mu ^2 - \omega ^2)]}{467005},\end{aligned}$$
(A.14)
$$\begin{aligned}&\tilde{b}_{3}-\tilde{b}_{4}=\frac{b_{3}}{2C_{14}^{3}+C_{18}^{3}-C_{10}^{3}}-\frac{b_{4}}{2C_{14}^{4}+C_{18}^{4}-C_{10}^{4}}\nonumber \\&\quad =\frac{8m^5[19838 \lambda _l +19497\sqrt{m} c_D e(c_D e -\omega ) + 24888\sqrt{m} (\mu ^2 - \omega ^2)]}{107957}, \end{aligned}$$
(A.15)
$$\begin{aligned}&\tilde{b}_{2}-\tilde{b}_{3}=\frac{b_{2}}{2C_{14}^{2}+C_{18}^{2}-C_{10}^{2}}-\frac{b_{3}}{2C_{14}^{3}+C_{18}^{3}-C_{10}^{3}}\nonumber \\&\quad =\frac{4m^5[4112 \lambda _l +6663\sqrt{m} c_D e(c_D e -\omega ) + 4692\sqrt{m} (\mu ^2 - \omega ^2)]}{12905}, \end{aligned}$$
(A.16)
$$\begin{aligned}&\tilde{b}_{1}-\tilde{b}_{2}=\frac{b_{1}}{2C_{14}^{1}+C_{18}^{1}-C_{10}^{1}}-\frac{b_{2}}{2C_{14}^{2}+C_{18}^{2}-C_{10}^{2}} \nonumber \\&\quad =\frac{32m^5[12 \lambda _l +43\sqrt{m} c_D e(c_D e -\omega ) + 12\sqrt{m} (\mu ^2 - \omega ^2)]}{435}. \end{aligned}$$
(A.17)
Given the bound state condition \(\omega <\mu \) and superradiance condition \(\omega <c_D e\), it is easy to see that all the differences above are positive. So we have
$$\begin{aligned} \tilde{b}_{i}-\tilde{b}_{i+1}>0,~\text {sign}(b_{i})\geqslant \text {sign}(b_{i+1}),~(i=1,2,..,12).\nonumber \\ \end{aligned}$$
(A.18)
According to the results (A.3), (A.5), (A.18), we conclude that the sign change in the sequence of coefficients \((b_{20},b_{19},...,b_1,b_0)\) is always 1.
Appendix B: Proof of sign relations in D-dimensional case
In this section, we give the details of the analytical proof of the following sign relations for \(b_p\) and \(b_{p+1}\) which are respectively the coefficients of \(z^p\) and \(z^{p+1}\) in the numerator of the derivative of the effective potential,
$$\begin{aligned} \text {sign}(b_{p})\geqslant \text {sign}(b_{p+1}),~(0<p<3D-7). \end{aligned}$$
(B.1)
1.1 B.1 Coefficients of \(z^p\), \(p=3D-7,3D-8,3D-9\)
In this subsection, we prove the sign relations between pairs of adjacent coefficients in the sequence \((b_{3D-7},b_{3D-8},b_{3D-9})\).
1.1.1 B.1.1 \(\tilde{b}_{3D-7}<\tilde{b}_{3D-8}\)
Here we will prove the following inequality
$$\begin{aligned} \tilde{b}_{3D-8}-\tilde{b}_{3D-7}>0. \end{aligned}$$
(B.2)
The difference \(\tilde{b}_{3D-8}-\tilde{b}_{3D-7}\) can be divided into four terms and we will consider term by term. First, let’s see the \(\mu ^2-\omega ^2\) term in the difference, which can be written as
$$\begin{aligned}&4(D-3)m^2r_h^{3D-7}(\mu ^2-\omega ^2)\nonumber \\&\quad \times \left[ \frac{2C_{3D-7}^{3D-8}-C_{4D-10}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}} -\frac{2C_{3D-7}^{3D-7}-C_{4D-10}^{3D-7}}{2C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}}\right] . \end{aligned}$$
(B.3)
Given the bound state condition, the factor outside the square bracket in the above is positive. The factor in the square bracket is equivalent to
$$\begin{aligned} \frac{-2C_{4D-10}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}} +\frac{2C_{4D-10}^{3D-7}}{2C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}}. \end{aligned}$$
(B.4)
With the following combinatorial identity
$$\begin{aligned} C_n^m=\frac{m+1}{n-m}C_n^{m+1}, \end{aligned}$$
(B.5)
we have
$$\begin{aligned} \frac{C_{3D-7}^{3D-8}}{C_{4D-10}^{3D-8}}=(D-2)\frac{C_{3D-7}^{3D-7}}{C_{4D-10}^{3D-7}}. \end{aligned}$$
(B.6)
Then Eq. (B.4) can be rewritten as
$$\begin{aligned} \frac{-2}{2(D-2)C_{3D-7}^{3D-7}/C_{4D-10}^{3D-7}+1} +\frac{2}{2C_{3D-7}^{3D-7}/C_{4D-10}^{3D-7}+1},\nonumber \\ \end{aligned}$$
(B.7)
which is obviously positive and then Eq. (B.3) is positive.
Second, let’s see the \((c_D e-\omega )\) term in the difference (B.2),
$$\begin{aligned}&4(D-3)m^2r_h^{3D-7}(c_D e-\omega )c_D e\nonumber \\&\quad \times \left[ \frac{C_{3D-7}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}} -\frac{C_{3D-7}^{3D-7}}{2C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}}\right] . \end{aligned}$$
(B.8)
Using the Eq. (B.6), the factor in the square bracket of the above can be rewritten as
$$\begin{aligned} \frac{(D-2)C_{3D-7}^{3D-7}}{2(D-2)C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}} -\frac{C_{3D-7}^{3D-7}}{2C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}}, \end{aligned}$$
(B.9)
which is positive and then the Eq. (B.8) is positive.
Thirdly, let’s see the \(D_1\) term in the difference (B.2),
$$\begin{aligned} D_1 m^5\left[ -\frac{C_{5D-15}^{3D-8}-5C_{4D-12}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}+ \frac{C_{5D-15}^{3D-7}-5C_{4D-12}^{3D-7}}{2C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}}\right] .\nonumber \\ \end{aligned}$$
(B.10)
Using a similar proof as (4.15), we can obtain \(C_{5D-15}^{3D-8}-5C_{4D-12}^{3D-8}>0, C_{5D-15}^{3D-7}-5C_{4D-12}^{3D-7}>0\). In order to prove the factor in the square bracket in the above expression is positive, we can equivalently to prove
$$\begin{aligned}&\frac{C_{5D-15}^{3D-8}-5C_{4D-12}^{3D-8}}{C_{5D-15}^{3D-7}-5C_{4D-12}^{3D-7}}< \frac{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}{2C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}} \nonumber \\&\quad \Leftrightarrow \frac{\frac{1}{2D-7}C_{5D-15}^{3D-7}-5\frac{1}{D-4}C_{4D-12}^{3D-7}}{C_{5D-15}^{3D-7}-5C_{4D-12}^{3D-7}}\nonumber \\&\quad < \frac{2C_{3D-7}^{3D-7}+\frac{1}{D-2}C_{4D-10}^{3D-7}}{2C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}}. \end{aligned}$$
(B.11)
Because
$$\begin{aligned}&\frac{2C_{3D-7}^{3D-7}+\frac{1}{D-2}C_{4D-10}^{3D-7}}{2C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}}>\frac{1}{D-2}> \frac{1}{2D-7} \nonumber \\&\quad > \frac{\frac{1}{2D-7}C_{5D-15}^{3D-7}-5\frac{1}{D-4}C_{4D-12}^{3D-7}}{C_{5D-15}^{3D-7}-5C_{4D-12}^{3D-7}}, \end{aligned}$$
(B.12)
we immediately obtain the expression (B.10) is positive.
Finally, let’s see the \(\lambda _l\) term in the difference (B.2),
$$\begin{aligned}&-4m^5\lambda _l\Bigg [\frac{C_{5D-15}^{3D-8}+(D-6)C_{4D-12}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}\nonumber \\&\quad -\frac{C_{5D-15}^{3D-7}+(D-6)C_{4D-12}^{3D-7}}{2C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}}\Bigg ]. \end{aligned}$$
(B.13)
The positivity of the above expression is equivalent to
$$\begin{aligned}&\frac{C_{5D-15}^{3D-8}+(D-6)C_{4D-12}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}} <\frac{C_{5D-15}^{3D-7}+(D-6)C_{4D-12}^{3D-7}}{2C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}} \end{aligned}$$
(B.14)
$$\begin{aligned}&\quad \Leftrightarrow \frac{C_{5D-15}^{3D-8}+(D-6)C_{4D-12}^{3D-8}}{C_{5D-15}^{3D-7}+(D-6)C_{4D-12}^{3D-7}} <\frac{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}{2C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}} \end{aligned}$$
(B.15)
$$\begin{aligned}&\quad \Leftrightarrow \frac{\frac{1}{2D-7}C_{5D-15}^{3D-7}+(D-6)\frac{1}{D-4}C_{4D-12}^{3D-7}}{C_{5D-15}^{3D-7}+(D-6)C_{4D-12}^{3D-7}}\nonumber \\&\quad <\frac{2C_{3D-7}^{3D-7}+\frac{1}{D-2}C_{4D-10}^{3D-7}}{2C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}}. \end{aligned}$$
(B.16)
The left side of the above inequality is
$$\begin{aligned}&\frac{\frac{1}{2D-7}C_{5D-15}^{3D-7}+(D-6)\frac{1}{D-4}C_{4D-12}^{3D-7}}{C_{5D-15}^{3D-7}+(D-6)C_{4D-12}^{3D-7}}\nonumber \\&\quad =\frac{\frac{1}{2D-7}k_D+\frac{1}{D-4}}{k_D+1}=\frac{1}{2D-7}\nonumber \\&\qquad +\frac{1}{k_D+1}\left( \frac{1}{D-4}-\frac{1}{2D-7}\right) , \end{aligned}$$
(B.17)
where
$$\begin{aligned} k_D= & {} \frac{C_{5D-15}^{3D-7}}{(D-6)C_{4D-12}^{3D-7}}=\frac{1}{D-6}\cdot \frac{5D-15}{4D-12}\cdots \nonumber \\&\quad \frac{2D-7}{D-4}>\frac{1}{D-6}\left( \frac{5}{4}\right) ^{3D-7}>22. \end{aligned}$$
(B.18)
So we have
$$\begin{aligned}&\frac{1}{2D-7}+\frac{1}{k_D+1}\left( \frac{1}{D-4}-\frac{1}{2D-7}\right) \nonumber \\&\quad < \frac{1}{2D-7}+\frac{1}{23}\left( \frac{1}{D-4}-\frac{1}{2D-7}\right) . \end{aligned}$$
(B.19)
Further, when \(D\geqslant 7\) we have
$$\begin{aligned}&\frac{1}{D-2}-\left( \frac{1}{2D-7}+\frac{1}{23}\left( \frac{1}{D-4}-\frac{1}{2D-7}\right) \right) \nonumber \\&\quad =\frac{1}{23(D-2)(D-4)(2D-7)}\nonumber \\&\qquad \times (22D^2-202D+454)>0. \end{aligned}$$
(B.20)
The left side of the inequality (B.16) is smaller than \(\frac{1}{D-2}\). One can easy to see that the right side of the inequality (B.16) satisfies
$$\begin{aligned} \frac{2C_{3D-7}^{3D-7}+\frac{1}{D-2}C_{4D-10}^{3D-7}}{2C_{3D-7}^{3D-7}+C_{4D-10}^{3D-7}}>\frac{1}{D-2}. \end{aligned}$$
(B.21)
The inequality (B.16) holds when \(D\geqslant 7\).
After showing that the four terms (B.3), (B.8), (B.10), (B.13) are all positive, the inequality (B.2) is proved when \(D\geqslant 7\). The possible signs for \(b_{3D-7},b_{3D-8}\) are \((-,-),(-,+),(+,+)\). The relation between signs of \(b_{3D-7},b_{3D-8}\) is
$$\begin{aligned} \text {sign}(b_{3D-7})\leqslant \text {sign}(b_{3D-8}). \end{aligned}$$
(B.22)
1.1.2 B.1.2 \(\tilde{b}_{3D-8}<\tilde{b}_{3D-9}\)
Here let’s prove the following inequality
$$\begin{aligned} \tilde{b}_{3D-9}-\tilde{b}_{3D-8}>0. \end{aligned}$$
(B.23)
The difference \(\tilde{b}_{3D-9}-\tilde{b}_{3D-8}\) can be divided into four terms and we will consider term by term. First, let’s see the \(\mu ^2-\omega ^2\) term in the above difference, which is
$$\begin{aligned}&4(D-3)m^2 r_h^{3D-7}(\mu ^2-\omega ^2)\nonumber \\&\quad \times \left[ \frac{2C_{3D-7}^{3D-9}-C_{4D-10}^{3D-9}}{2C_{3D-7}^{3D-9}+C_{4D-10}^{3D-9}} -\frac{2C_{3D-7}^{3D-8}-C_{4D-10}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}\right] \end{aligned}$$
(B.24)
The factor in the square bracket is equivalent to
$$\begin{aligned}&\frac{-2C_{4D-10}^{3D-9}}{2C_{3D-7}^{3D-9}+C_{4D-10}^{3D-9}} +\frac{2C_{4D-10}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}\nonumber \\&\quad =\frac{-2C_{4D-10}^{3D-8}}{(D-1)C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}} +\frac{2C_{4D-10}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}.\nonumber \\ \end{aligned}$$
(B.25)
Because \(D\geqslant 7\), the above expression is positive. Thus the \(\mu ^2-\omega ^2\) term in the difference \(\tilde{b}_{3D-9}-\tilde{b}_{3D-8}\) is positive given the bound state condition.
Second, let’s see the \((c_D e-\omega )\) term in the difference \(\tilde{b}_{3D-9}-\tilde{b}_{3D-8}\), which is
$$\begin{aligned}&4(D-3)m^2r_h^{3D-7}(c_D e-\omega )c_D e\nonumber \\&\quad \times \left[ \frac{C_{3D-7}^{3D-9}}{2C_{3D-7}^{3D-9}+C_{4D-10}^{3D-9}} -\frac{C_{3D-7}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}\right] . \end{aligned}$$
(B.26)
Define the factors in the square brackets in(B.24) and (B.26)as following
$$\begin{aligned} x_2= & {} \frac{2C_{3D-7}^{3D-9}-C_{4D-10}^{3D-9}}{2C_{3D-7}^{3D-9}+C_{4D-10}^{3D-9}} -\frac{2C_{3D-7}^{3D-8}-C_{4D-10}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}, \end{aligned}$$
(B.27)
$$\begin{aligned} y_2= & {} \frac{C_{3D-7}^{3D-9}}{2C_{3D-7}^{3D-9}+C_{4D-10}^{3D-9}} -\frac{C_{3D-7}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}. \end{aligned}$$
(B.28)
One can check that \(2 y_2-\frac{x_2}{2}=0\). We have already proved \(x_2>0\) in (B.25), so \(y_2>0\), i.e. the \((c_D e-\omega )\) term is positive.
Thirdly, let’s see the \(D_l\) term in the difference \(\tilde{b}_{3D-9}-\tilde{b}_{3D-8}\), which is
$$\begin{aligned}&-D_1 m r_h^{4D-12}\nonumber \\&\quad \times \left[ \frac{C_{5D-15}^{3D-9}-5C_{4D-12}^{3D-9}+10}{2C_{3D-7}^{3D-9}+C_{4D-10}^{3D-9}} -\frac{C_{5D-15}^{3D-8}-5C_{4D-12}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}\right] .\nonumber \\ \end{aligned}$$
(B.29)
Because
$$\begin{aligned}&\frac{C_{5D-15}^{3D-8}}{C_{4D-12}^{3D-8}}=\frac{5D-15}{4D-12}\frac{5D-16}{4D-13}\cdots \frac{2D-6}{D-3}\nonumber \\&\quad> \left( \frac{5}{4}\right) ^{3D-8}>\left( \frac{5}{4}\right) ^{10}\approx 9.3>5, \end{aligned}$$
(B.30)
we have
$$\begin{aligned} C_{5D-15}^{3D-8}-5C_{4D-12}^{3D-8}>0. \end{aligned}$$
(B.31)
Now let’s prove the factor in square bracket is negative. The factor is
$$\begin{aligned} \frac{C_{5D-15}^{3D-9}-5C_{4D-12}^{3D-9}+10}{2C_{3D-7}^{3D-9}+C_{4D-10}^{3D-9}} -\frac{C_{5D-15}^{3D-8}-5C_{4D-12}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}. \end{aligned}$$
(B.32)
According to (B.5), the first term of the factor can be written as
$$\begin{aligned}&\frac{C_{5D-15}^{3D-9}-5C_{4D-12}^{3D-9}+10}{2C_{3D-7}^{3D-9}+C_{4D-10}^{3D-9}}\nonumber \\&\quad =\frac{\frac{3D-8}{2D-6}C_{5D-15}^{3D-8}-\frac{3D-8}{D-3}5C_{4D-12}^{3D-8}+10}{\frac{3D-8}{2}2C_{3D-7}^{3D-8}+\frac{3D-8}{D-1}C_{4D-10}^{3D-8}}\nonumber \\&\quad =\frac{C_{5D-15}^{3D-8}-2*5C_{4D-12}^{3D-8}+\frac{2D-6}{3D-8}*10}{(D-3)2C_{3D-7}^{3D-8}+2\frac{D-3}{D-1}C_{4D-10}^{3D-8}}. \end{aligned}$$
(B.33)
Then the negativity of (B.32) is equivalent to
$$\begin{aligned}&\frac{C_{5D-15}^{3D-8}-2*5C_{4D-12}^{3D-8}+\frac{2D-6}{3D-8}*10}{(D-3)2C_{3D-7}^{3D-8}+2\frac{D-3}{D-1}C_{4D-10}^{3D-8}}\nonumber \\&\quad<\frac{C_{5D-15}^{3D-8}-5C_{4D-12}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}} \nonumber \\&\quad \Leftrightarrow \frac{C_{5D-15}^{3D-8}-2*5C_{4D-12}^{3D-8}+\frac{2D-6}{3D-8}*10}{C_{5D-15}^{3D-8}-5C_{4D-12}^{3D-8}}\nonumber \\&\quad <\frac{(D-3)2C_{3D-7}^{3D-8}+2\frac{D-3}{D-1}C_{4D-10}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}. \end{aligned}$$
(B.34)
For the left side of the Eq. (B.34), we have
$$\begin{aligned}&\frac{C_{5D-15}^{3D-8}-2*5C_{4D-12}^{3D-8}+\frac{2D-6}{3D-8}*10}{C_{5D-15}^{3D-8}-5C_{4D-12}^{3D-8}}\nonumber \\&\quad = 1+5*\frac{-C_{4D-12}^{3D-8}+\frac{4D-12}{3D-8}}{C_{5D-15}^{3D-8}-5C_{4D-12}^{3D-8}}<1. \end{aligned}$$
(B.35)
For the right side of the Eq. (B.34), we have
$$\begin{aligned}&\frac{(D-3)2C_{3D-7}^{3D-8}+2\frac{D-3}{D-1}C_{4D-10}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}\nonumber \\&\quad =\frac{2D-6}{D-1}\frac{(D-1)C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}} >\frac{2D-6}{D-1}.\nonumber \\ \end{aligned}$$
(B.36)
When \(D>6\), we have \(\frac{2D-6}{D-1}>1\). Then the Eq. (B.32) is negative and the \(D_1\) term, (B.29), is positive.
Finally, let’s see the \(\lambda _l\) term in the difference \(\tilde{b}_{3D-9}-\tilde{b}_{3D-8}\), which is
$$\begin{aligned}&-4m\lambda _l r_h^{4D-12}\nonumber \\&\quad \times \left[ \frac{C_{5D-15}^{3D-9}+(D-6)C_{4D-12}^{3D-9}+9-2D}{2C_{3D-7}^{3D-9}+C_{4D-10}^{3D-9}} \right. \nonumber \\&\quad \left. -\frac{C_{5D-15}^{3D-8}+(D-6)C_{4D-12}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}\right] . \end{aligned}$$
(B.37)
Now let’s prove the factor in square bracket is negative. This factor is
$$\begin{aligned}&\frac{C_{5D-15}^{3D-9}+(D-6)C_{4D-12}^{3D-9}+9-2D}{2C_{3D-7}^{3D-9}+C_{4D-10}^{3D-9}}\nonumber \\&\quad -\frac{C_{5D-15}^{3D-8}+(D-6)C_{4D-12}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}. \end{aligned}$$
(B.38)
Since \(9-2D<0\), a sufficient condition for the above to be negative is
$$\begin{aligned} \frac{C_{5D-15}^{3D-9}+(D-6)C_{4D-12}^{3D-9}}{2C_{3D-7}^{3D-9}+C_{4D-10}^{3D-9}} <\frac{C_{5D-15}^{3D-8}+(D-6)C_{4D-12}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}.\nonumber \\ \end{aligned}$$
(B.39)
According to (B.5), the left side of the above can be rewritten as
$$\begin{aligned}&\frac{C_{5D-15}^{3D-9}+(D-6)C_{4D-12}^{3D-9}}{2C_{3D-7}^{3D-9}+C_{4D-10}^{3D-9}}\nonumber \\&\quad = \frac{\frac{1}{2D-6}C_{5D-15}^{3D-8}+\frac{1}{D-3}(D-6)C_{4D-12}^{3D-8}}{\frac{1}{2}2C_{3D-7}^{3D-8}+\frac{1}{D-1}C_{4D-10}^{3D-8}} \nonumber \\&\quad =\frac{C_{5D-15}^{3D-8}+2(D-6)C_{4D-12}^{3D-8}}{(D-3)2C_{3D-7}^{3D-8}+\frac{2(D-3)}{D-1}C_{4D-10}^{3D-8}}. \end{aligned}$$
(B.40)
The inequality (B.39) is equivalent to
$$\begin{aligned}&\frac{C_{5D-15}^{3D-8}+2(D-6)C_{4D-12}^{3D-8}}{(D-3)2C_{3D-7}^{3D-8}+\frac{2(D-3)}{D-1}C_{4D-10}^{3D-8}} \nonumber \\&\quad<\frac{C_{5D-15}^{3D-8}+(D-6)C_{4D-12}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}\nonumber \\&\quad \Leftrightarrow \frac{C_{5D-15}^{3D-8}+2(D-6)C_{4D-12}^{3D-8}}{C_{5D-15}^{3D-8}+(D-6)C_{4D-12}^{3D-8}} \nonumber \\&\quad<\frac{(D-3)2C_{3D-7}^{3D-8}+\frac{2(D-3)}{D-1}C_{4D-10}^{3D-8}}{2C_{3D-7}^{3D-8}+C_{4D-10}^{3D-8}}\nonumber \\&\quad \Leftrightarrow 1+\frac{D-6}{D-6+\frac{C_{5D-15}^{3D-8}}{C_{4D-12}^{3D-8}}}\nonumber \\&\qquad <\frac{2D-6}{D-1}+\frac{2(D-3)^2/(D-1)}{2+ \frac{C_{4D-10}^{3D-8}}{C_{3D-7}^{3D-8}}}. \end{aligned}$$
(B.41)
According to (B.30), when \(D>6\), we have
$$\begin{aligned}&1+\frac{D-6}{D-6+\frac{C_{5D-15}^{3D-8}}{C_{4D-12}^{3D-8}}}<1+\frac{D-6}{D+3}\nonumber \\&\quad =\frac{2D-3}{D+3}< \frac{2D-6}{D-1}. \end{aligned}$$
(B.42)
Thus, the factor (B.38) is negative and the \(\lambda _l\) term, Eq. (B.37), is positive.
After proving that all the four terms (B.24), (B.26), (B.29), (B.37) are positive, then (B.23) is proved when \(D>6\). The relation between signs of \(b_{3D-9}, b_{3D-8}\) is
$$\begin{aligned} \text {sign}(b_{3D-8})\leqslant \text {sign}(b_{3D-9}). \end{aligned}$$
(B.43)
1.2 B.2 Coefficients of \(z^p\), \( 3D-9> p>2D-4\)
In this subsection, we will consider the sign relations between pairs of adjacent coefficients in the sequence \((..,b_{p+1},b_{p},..)\) for \( 3D-9> p>2D-4\). Explicitly, we will analyze the signs of \(b_p\) and \(b_{p+1}\) by comparing \(\tilde{b}_p\) and \(\tilde{b}_{p+1}\). The expression of the coefficient \(b_p\) is
$$\begin{aligned} b_p= & {} a_5 C_{5D-15}^{p}r_h^{5D-15-p}+a'_4 C_{4D-10}^{p}r_h^{4D-10-p}\nonumber \\&+a_4C_{4D-12}^{p}r_h^{4D-12-p} +a'_3 C_{3D-7}^{p}r_h^{3D-7-p}\nonumber \\&+a_3 C_{3D-9}^p r_h^{3D-9-p}\nonumber \\= & {} r_h^{3D-9-p}(a_5 m^2 C_{5D-15}^{p}+a_4m C_{4D-12}^{p}+a_3 C_{3D-9}^p\nonumber \\&+a'_4 m r_h^2 C_{4D-10}^{p}+a'_3 r_h^2C_{3D-7}^{p})\nonumber \\= & {} r_h^{-p}(-m^5 D_1)(C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p)\nonumber \\&+r_h^{-p}(-4m^5\lambda _l)(C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}\nonumber \\&+(9-2D)C_{3D-9}^p)\nonumber \\&+r_h^{-p+2}4(D-3)m^5(C_{4D-10}^{p}+2 C_{3D-7}^p)(c_D e- \omega )\nonumber \\&\times \left( \frac{ C_{3D-7}^p c_D e}{C_{4D-10}^{p}+2 C_{3D-7}^p}-\omega \right) \nonumber \\&+r_h^{-p+2}4(D-3)m^5(\mu ^2-\omega ^2)(2C_{3D-7}^p-C_{4D-10}^p).\nonumber \\ \end{aligned}$$
(B.44)
Define a normalized coefficient \(\tilde{b}_p\) with a positive factor,
$$\begin{aligned} \tilde{b}_p=\frac{r_h^p}{C_{4D-10}^{p}+2 C_{3D-7}^p}b_p. \end{aligned}$$
(B.45)
Then we consider the following difference
$$\begin{aligned} \tilde{b}_p-\tilde{b}_{p+1}= & {} \frac{r_h^p}{C_{4D-10}^{p}+2 C_{3D-7}^{p}}b_p\nonumber \\&-\frac{r_h^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}}b_{p+1}, \end{aligned}$$
(B.46)
which can be similarly decomposed into a sum of four terms.
First, the \((\mu ^2-\omega ^2)\) term in the above difference is
$$\begin{aligned}&4(D-3)m^5r_h^2(\mu ^2-\omega ^2)\nonumber \\&\quad \times \left[ \frac{2 C_{3D-7}^p-C_{4D-10}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^p}- \frac{2 C_{3D-7}^{p+1}-C_{4D-10}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}}\right] \end{aligned}$$
(B.47)
The factor in the square bracket is equivalent to \(x_3\), which is defined as
$$\begin{aligned} x_3\equiv & {} \frac{-2C_{4D-10}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^p}+ \frac{2 C_{4D-10}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}}\nonumber \\= & {} \frac{-2C_{4D-10}^{p+1}*\frac{1}{4D-10-p}}{\frac{1}{4D-10-p}C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1} *\frac{1}{3D-7-p}}\nonumber \\&+ \frac{2 C_{4D-10}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}}\nonumber \\= & {} \frac{-2C_{4D-10}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1} *\frac{4D-10-p}{3D-7-p}}\nonumber \\&+ \frac{2 C_{4D-10}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}}. \end{aligned}$$
(B.48)
Because \(\frac{4D-10-p}{3D-7-p}>1\) , the above expression is positive. Then (B.47) is positive given the bound state condition.
Secondly, the \((c_D e-\omega )\) term in the difference (B.46) is
$$\begin{aligned}&4(D-3)m^5r_h^2(c_D e-\omega )c_D e\nonumber \\&\quad \times \left[ \frac{ C_{3D-7}^p}{C_{4D-10}^{p}+2 C_{3D-7}^p}- \frac{C_{3D-7}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}}\right] . \end{aligned}$$
(B.49)
The factor in the above square bracket can be denoted as
$$\begin{aligned} y_3\equiv \frac{ C_{3D-7}^p}{C_{4D-10}^{p}+2 C_{3D-7}^p}- \frac{C_{3D-7}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}}. \end{aligned}$$
(B.50)
One can easily check that
$$\begin{aligned} 2 y_3-x_3/2=0. \end{aligned}$$
(B.51)
And because \(x_3>0\), we then have \(y_3>0\). Together with the superradiance condition, we obtain that the \((c_D e-\omega )\) term is positive.
Thirdly, let’s see the \(\lambda _l\) term in the difference (B.46), which is
$$\begin{aligned} -4m^5\lambda _l\Bigg [\frac{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p}{C_{4D-10}^{p}+2 C_{3D-7}^{p}}\nonumber \ \frac{C_{5D-15}^{p+1}+(D-6)C_{4D-12}^{p+1}+(9-2D)C_{3D-9}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}}\Bigg ].\nonumber \\ \end{aligned}$$
(B.52)
The factor in square bracket is
$$\begin{aligned}&\frac{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}} -\frac{C_{5D-15}^{p+1}+(D-6)C_{4D-12}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}} \nonumber \\&\quad +\frac{(2D-9)C_{3D-9}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}} -\frac{(2D-9)C_{3D-9}^p}{C_{4D-10}^{p}+2 C_{3D-7}^{p}}. \end{aligned}$$
(B.53)
For the second line of the above expression, we have
$$\begin{aligned}&\frac{(2D-9)C_{3D-9}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}} -\frac{(2D-9)C_{3D-9}^p}{C_{4D-10}^{p}+2 C_{3D-7}^{p}}\nonumber \\&\quad =(2D-9)\left[ \frac{(3D-9-p)C_{3D-9}^{p}}{(4D-10-p)C_{4D-10}^{p}+(3D-7-p)2 C_{3D-7}^{p}} \right. \nonumber \\&\qquad \left. -\frac{C_{3D-9}^p}{C_{4D-10}^{p}+2 C_{3D-7}^{p}}\right] \nonumber \\&\quad =(2D-9)\left[ \frac{C_{3D-9}^{p}}{\frac{4D-10-p}{3D-9-p}C_{4D-10}^{p}+\frac{3D-7-p}{3D-9-p}2 C_{3D-7}^{p}}\right. \nonumber \\&\qquad \left. -\frac{C_{3D-9}^p}{C_{4D-10}^{p}+2 C_{3D-7}^{p}}\right] . \end{aligned}$$
(B.54)
Since \(\frac{4D-10-p}{3D-9-p}>1, \frac{3D-7-p}{3D-9-p}>1 \), the above equation is less than 0. So the second line of (B.53) is negative.
For the first line of (B.53), we will show that it is also negative, which is equivalent to
$$\begin{aligned}&\frac{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}}<\frac{C_{5D-15}^{p+1}+(D-6)C_{4D-12}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}}<\frac{C_{5D-15}^{p+1}+(D-6)C_{4D-12}^{p+1}}{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}}\nonumber \\&\quad \Leftrightarrow \frac{(4D-10-p)C_{4D-10}^{p}+(3D-7-p)2 C_{3D-7}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}}\nonumber \\&\quad <\frac{(5D-15-p)C_{5D-15}^{p}+(4D-12-p)(D-6)C_{4D-12}^{p}}{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}}\nonumber \\ \end{aligned}$$
(B.55)
For the left side of the above inequality, we have
$$\begin{aligned}&\frac{(4D-10-p)C_{4D-10}^{p}+(3D-7-p)2 C_{3D-7}^{p}}{C_{4D-10}^{p}}\nonumber \\&\quad {+2 C_{3D-7}^{p}}<4D-10-p. \end{aligned}$$
(B.56)
For the right side of the inequality (B.55), we have
$$\begin{aligned}&\frac{(5D-15-p)C_{5D-15}^{p}+(4D-12-p)(D-6)C_{4D-12}^{p}}{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}}\nonumber \\&\quad =4D-12-p+\frac{D-3}{1+(D-6)C_{4D-12}^p/C_{5D-15}^p}.\nonumber \\ \end{aligned}$$
(B.57)
Since
$$\begin{aligned}&\frac{C_{4D-12}^p}{C_{5D-15}^p}=\frac{4D-12}{5D-15}\frac{4D-13}{5D-16}\cdots \frac{4D-12-p}{5D-15-p}<\nonumber \\&\quad \left( \frac{4}{5}\right) ^p<\left( \frac{4}{5}\right) ^{2D-4}<\left( \frac{4}{5}\right) ^{8}<0.2,\nonumber \\ \end{aligned}$$
(B.58)
then for \(D>6\)
$$\begin{aligned}&4D-12-p+\frac{D-3}{1+(D-6)C_{4D-12}^p/C_{5D-15}^p}\nonumber \\&\quad>4D-12-p+\frac{D-3}{1+(D-6)0.2}\nonumber \\&\quad >4D-12-p+3=4D-9-p. \end{aligned}$$
(B.59)
Based on (B.56), (B.59), we obtain that the first line of (B.53) is also negative. So the \(\lambda _l\) term, (B.52), is positive.
Finally, let’s see the \(D_1\) term in the difference (B.46), which is
$$\begin{aligned}&-m^5 D_1\left[ \frac{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p}{C_{4D-10}^{p}+2 C_{3D-7}^p} \right. \nonumber \\&\quad \left. - \frac{C_{5D-15}^{p+1}-5C_{4D-12}^{p+1}+10C_{3D-9}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}}\right] . \end{aligned}$$
(B.60)
We will prove the difference in the above square bracket is negative and then \(D_1\) term is positive.
For \(D>6\) and \(p>2D-4>8\), we have the following inequalities
$$\begin{aligned} \frac{C_{5D-15}^{p}}{C_{3D-9}^{p}}= & {} \frac{5D-15}{3D-9}\frac{5D-16}{3D-10}..\frac{5D-14-p}{3D-8-p}\nonumber \\> & {} (\frac{5}{3})^8>10, \end{aligned}$$
(B.61)
$$\begin{aligned} \frac{C_{3D-9}^{p}}{C_{5D-15}^{p}}< & {} (3/5)^8<0.02,\end{aligned}$$
(B.62)
$$\begin{aligned} \frac{C_{5D-15}^{p}}{C_{4D-12}^{p}}= & {} \frac{5D-15}{4D-12}\frac{5D-16}{4D-13}..\frac{5D-14-p}{4D-11-p}\nonumber \\> & {} (\frac{5}{4})^8>5, \end{aligned}$$
(B.63)
so \(C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p>0\), i.e. the numerators in (B.60) are positive. Then
$$\begin{aligned}&\frac{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p}{C_{4D-10}^{p}+2 C_{3D-7}^p}\nonumber \\&\qquad - \frac{C_{5D-15}^{p+1}-5C_{4D-12}^{p+1}+10C_{3D-9}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}}<0\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}}{C_{4D-10}^{p}+2 C_{3D-7}^p}< \frac{C_{5D-15}^{p+1}-5C_{4D-12}^{p+1}+10C_{3D-9}^{p+1}}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p}\end{aligned}$$
(B.64)
$$\begin{aligned}&\quad \Leftrightarrow \frac{(4D-10-p)C_{4D-10}^{p}+(3D-7-p)2 C_{3D-7}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^p}\nonumber \\&\quad <\frac{(5D-15-p)C_{5D-15}^{p}-(4D-12-p)5C_{4D-12}^{p}+(3D-9-p)10C_{3D-9}^{p}}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p}. \end{aligned}$$
(B.65)
When \(D>6\), the left term in inequality (B.65) satisfies
$$\begin{aligned}&\frac{(4D-10-p)C_{4D-10}^{p}+(3D-7-p)2 C_{3D-7}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^p}\nonumber \\&\quad <4D-10-p. \end{aligned}$$
(B.66)
For \(D>6\), we also have \(D-3>3\). The right term in inequality (B.65) satisfies
$$\begin{aligned}&\frac{(5D-15-p)C_{5D-15}^{p}-(4D-12-p)5C_{4D-12}^{p}+(3D-9-p)10C_{3D-9}^{p}}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p}\nonumber \\&\quad =4D-12-p+\frac{(D-3)C_{5D-15}^{p}-(D-3)10C_{3D-9}^{p}}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p}\nonumber \\&\quad>4D-12-p+(D-3)\frac{C_{5D-15}^{p}-10C_{3D-9}^{p}}{C_{5D-15}^{p}+10C_{3D-9}^p}\nonumber \\&\quad =4D-12-p+(D-3)\frac{1-10C_{3D-9}^{p}/C_{5D-15}^{p}}{1+10C_{3D-9}^p/C_{5D-15}^{p}}\nonumber \\&\quad>4D-12-p+(D-3)\frac{1-10*0.02}{1+10*0.02}\nonumber \\&\quad >4D-12-p+3*\frac{2}{3}=4D-10-p. \end{aligned}$$
(B.67)
With the above inequality and (B.66), we obtain that the \(D_1\) term (B.60) is positive.
So in this case, all four terms in the difference (B.46) are shown to be positive, we then obtain that
$$\begin{aligned} \text {sign}(b_p)\geqslant \text {sign}(b_{p+1}). \end{aligned}$$
(B.68)
1.3 B.3 Coefficients of \(z^p\), \( p=2D-3, 2D-4\)
The two coefficients of \(z^p\) for \( p=2D-3, 2D-4\) are listed as follows
$$\begin{aligned} b_{2D-3}= & {} a_5 C_{5D-15}^{2D-3}r_h^{3D-12}+a'_4 C_{4D-10}^{2D-3}r_h^{2D-7}\nonumber \\&+a_4C_{4D-12}^{2D-3}r_h^{2D-9} \nonumber \\&+a'_3 C_{3D-7}^{2D-3}r_h^{D-4}+a_3 C_{3D-9}^{2D-3} r_h^{D-6}\nonumber \\= & {} r_h^{-3}(-m^3 D_1)(C_{5D-15}^{2D-3}-5C_{4D-12}^{2D-3}+10C_{3D-9}^{2D-3})\nonumber \\&+r_h^{-3}(-4m^3\lambda _l)(C_{5D-15}^{2D-3}\nonumber \\&+(D-6)C_{4D-12}^{2D-3}+(9-2D)C_{3D-9}^{2D-3})\nonumber \\&+r_h^{-1}4(D-3)m^3(C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3})(c_D e- \omega )\nonumber \\&\quad \times \left( \frac{ C_{3D-7}^{2D-3} c_D e}{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}-\omega \right) \nonumber \\&+ r_h^{-1}4(D-3)m^3(\mu ^2-\omega ^2)(2C_{3D-7}^{2D-3}-C_{4D-10}^{2D-3}). \end{aligned}$$
(B.69)
$$\begin{aligned} b_{2D-4}= & {} a_5 C_{5D-15}^{2D-4}r_h^{3D-11}+a'_4 C_{4D-10}^{2D-4}r_h^{2D-6}\nonumber \\&+a_4C_{4D-12}^{2D-4}r_h^{2D-8} \nonumber \\&+a'_3 C_{3D-7}^{2D-4}r_h^{D-3}+a_3 C_{3D-9}^{2D-4} r_h^{D-5}+a'_2 C_{2D-4}^{2D-4}\nonumber \\= & {} r_h^{-2}(-m^3 D_1)(C_{5D-15}^{2D-4}-5C_{4D-12}^{2D-4}+10C_{3D-9}^{2D-4})\nonumber \\&+r_h^{-2}(-4m^3\lambda _l)(C_{5D-15}^{2D-4}+(D-6)C_{4D-12}^{2D-4}\nonumber \\&+(9-2D)C_{3D-9}^{2D-4})\nonumber \\&+4(D-3)m^3(C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1)(c_D e- \omega )\nonumber \\&\quad \times \left( \frac{ (C_{3D-7}^{2D-4}+1) c_D e}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}-\omega \right) \nonumber \\&+4(D-3)m^3(\mu ^2-\omega ^2)(2C_{3D-7}^{2D-4}-C_{4D-10}^{2D-4}-1).\nonumber \\ \end{aligned}$$
(B.70)
Define two normalized new coefficients with positive factors,
$$\begin{aligned} \tilde{b}_{2D-3}= & {} \frac{b_{2D-3}r_h^3}{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}},\nonumber \\ \tilde{b}_{2D-4}= & {} \frac{b_{2D-4}r_h^2}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}. \end{aligned}$$
(B.71)
Now, we consider the difference between \(\tilde{b}_{2D-3}\) and \(\tilde{b}_{2D-4}\)
$$\begin{aligned}&\tilde{b}_{2D-4}-\tilde{b}_{2D-3}=\frac{b_{2D-4}r_h^2}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1} \nonumber \\&\quad -\frac{b_{2D-3}r_h^3}{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}. \end{aligned}$$
(B.72)
The difference can be decomposed into four terms and we will analyze term by term.
First, let’s see the \((\mu ^2-\omega ^2)\) term in (B.72), which is
$$\begin{aligned}&4(D-3)m^3 r_h^2(\mu ^2-\omega ^2)\left[ \frac{2C_{3D-7}^{2D-4}-C_{4D-10}^{2D-4}-1}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\right. \nonumber \\&\quad \left. -\frac{2C_{3D-7}^{2D-3}-C_{4D-10}^{2D-3}}{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}\right] \end{aligned}$$
(B.73)
The positivity of the factor in the square bracket is equivalent to
$$\begin{aligned}&\frac{-2C_{4D-10}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1} +\frac{2C_{4D-10}^{2D-3}}{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}>0\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{2D-3}}{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}\nonumber \\&\quad>\frac{C_{4D-10}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&\quad \Leftrightarrow \frac{(2D-6)C_{4D-10}^{2D-4}}{(2D-6)C_{4D-10}^{2D-4}+(D-3)2 C_{3D-7}^{2D-4}}\nonumber \\&\quad> \frac{C_{4D-10}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-C_{3D-7}^{2D-4}}\nonumber \\&\quad >\frac{C_{4D-10}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}. \end{aligned}$$
(B.74)
The above inequality holds since \(C_{3D-7}^{2D-4}>1\). So the \((\mu ^2-\omega ^2)\) term is positive given the bound state condition.
Secondly, let’s see the \((c_D e-\omega )\) term in (B.72), which is
$$\begin{aligned}&4(D-3)m^3 r_h^2(c_D e-\omega )c_D e\nonumber \\&\quad \times \left[ \frac{ C_{3D-7}^{2D-4}+1}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1} -\frac{ C_{3D-7}^{2D-3}}{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}\right] \nonumber \\ \end{aligned}$$
(B.75)
Define the factor in the square bracket as
$$\begin{aligned} x_1\equiv \frac{ C_{3D-7}^{2D-4}+1}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1} -\frac{ C_{3D-7}^{2D-3}}{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}.\nonumber \\ \end{aligned}$$
(B.76)
In Eq. (B.74), we prove that
$$\begin{aligned} y_1\equiv \frac{C_{4D-10}^{2D-3}}{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}-\frac{C_{4D-10}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}>0.\nonumber \\ \end{aligned}$$
(B.77)
Then we find that
$$\begin{aligned} y_1-2x_1=-\frac{3}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}<0. \end{aligned}$$
(B.78)
So \(x_1>0\) and the \((c_D e-\omega )\) term is positive given the superradiance condition.
Thirdly, let’s see the \(\lambda _l\) term in (B.72), which will be shown to be positive,
$$\begin{aligned} -4m^3\lambda _l\Bigg [\frac{C_{5D-15}^{2D-4}+(D-6)C_{4D-12}^{2D-4}+(9-2D)C_{3D-9}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\ -\frac{C_{5D-15}^{2D-3}+(D-6)C_{4D-12}^{2D-3}+(9-2D)C_{3D-9}^{2D-3}}{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}\Bigg ].\nonumber \\ \end{aligned}$$
(B.79)
The negativity of the factor in the square bracket is equivalent to
$$\begin{aligned}&\frac{C_{5D-15}^{2D-4}+(D-6)C_{4D-12}^{2D-4}+(9-2D)C_{3D-9}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&\quad<\frac{C_{5D-15}^{2D-3}+(D-6)C_{4D-12}^{2D-3}+(9-2D)C_{3D-9}^{2D-3}}{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&\quad <\frac{C_{5D-15}^{2D-3}+(D-6)C_{4D-12}^{2D-3}+(9-2D)C_{3D-9}^{2D-3}}{C_{5D-15}^{2D-4}+(D-6)C_{4D-12}^{2D-4}+(9-2D)C_{3D-9}^{2D-4}}.\nonumber \\ \end{aligned}$$
(B.80)
We then consider the left and right terms of the above inequality separately. For the left term of the above inequality, we have
$$\begin{aligned}&\frac{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1} \nonumber \\&\quad = \frac{(2D-6)C_{4D-10}^{2D-4}+(D-3)2 C_{3D-7}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&\quad =2D-6-\frac{(2D-6)(C_{3D-7}^{2D-4}-1)}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}<2D-6.\nonumber \\ \end{aligned}$$
(B.81)
For the right term in (B.80), we have
$$\begin{aligned}&\frac{C_{5D-15}^{2D-3}+(D-6)C_{4D-12}^{2D-3}+(9-2D)C_{3D-9}^{2D-3}}{C_{5D-15}^{2D-4}+(D-6)C_{4D-12}^{2D-4}+(9-2D)C_{3D-9}^{2D-4}}\nonumber \\&\quad =\frac{(3D-11)C_{5D-15}^{2D-4}+(2D-8)(D-6)C_{4D-12}^{2D-4}+(D-5)(9-2D)C_{3D-9}^{2D-3}}{C_{5D-15}^{2D-4}+(D-6)C_{4D-12}^{2D-4}+(9-2D)C_{3D-9}^{2D-4}}\nonumber \\&\quad =2D-8+\frac{(D-3)C_{5D-15}^{2D-4}+(3-D)(9-2D)C_{3D-9}^{2D-3}}{C_{5D-15}^{2D-4}+(D-6)C_{4D-12}^{2D-4}+(9-2D)C_{3D-9}^{2D-4}}\nonumber \\&\quad>2D-8+\frac{(D-3)C_{5D-15}^{2D-4}}{C_{5D-15}^{2D-4}+(D-6)C_{4D-12}^{2D-4}}\nonumber \\&\quad>2D-8+\frac{(D-3)}{1+(D-6)(4/5)^8}>2D-5. \end{aligned}$$
(B.82)
So we obtain that the right term is greater than the left term in (B.80) and the \(\lambda _l\) term in difference (B.72) is positive.
Finally, let’s see the \(D_1\) term in the difference (B.72), which will be shown to be positive,
$$\begin{aligned}&-m^3D_1\left[ \frac{C_{5D-15}^{2D-4}-5C_{4D-12}^{2D-4}+10C_{3D-9}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1} \right. \nonumber \\&\quad \left. -\frac{C_{5D-15}^{2D-3}-5C_{4D-12}^{2D-3}+10C_{3D-9}^{2D-3}}{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}\right] . \end{aligned}$$
(B.83)
The positivity of the above term is equivalent to the following inequality
$$\begin{aligned}&\frac{C_{5D-15}^{2D-4}-5C_{4D-12}^{2D-4}+10C_{3D-9}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&\quad<\frac{C_{5D-15}^{2D-3}-5C_{4D-12}^{2D-3}+10C_{3D-9}^{2D-3}}{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{2D-3}+2 C_{3D-7}^{2D-3}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&\quad<\frac{C_{5D-15}^{2D-3}-5C_{4D-12}^{2D-3}+10C_{3D-9}^{2D-3}}{C_{5D-15}^{2D-4}-5C_{4D-12}^{2D-4}+10C_{3D-9}^{2D-4}}\nonumber \\&\quad \Leftrightarrow \frac{(2D-6)C_{4D-10}^{2D-4}+(D-3)2 C_{3D-7}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&<\frac{(3D-11)C_{5D-15}^{2D-4}-(2D-8)5C_{4D-12}^{2D-4}+(D-5)10C_{3D-9}^{2D-4}}{C_{5D-15}^{2D-4}-5C_{4D-12}^{2D-4}+10C_{3D-9}^{2D-4}}.\nonumber \\ \end{aligned}$$
(B.84)
For the left term of the above inequality, we have
$$\begin{aligned}&\frac{(2D-6)C_{4D-10}^{2D-4}+(D-3)2 C_{3D-7}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&\quad =(2D-6)\frac{C_{4D-10}^{2D-4}+ C_{3D-7}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}<2D-6. \end{aligned}$$
(B.85)
For the right term of (B.84), we have
$$\begin{aligned}&\frac{(3D-11)C_{5D-15}^{2D-4}-(2D-8)5C_{4D-12}^{2D-4}+(D-5)10C_{3D-9}^{2D-4}}{C_{5D-15}^{2D-4}-5C_{4D-12}^{2D-4}+10C_{3D-9}^{2D-4}}\nonumber \\&\quad =2D-8+(D-3)\frac{C_{5D-15}^{2D-4}-10C_{3D-9}^{2D-4}}{C_{5D-15}^{2D-4}-5C_{4D-12}^{2D-4}+10C_{3D-9}^{2D-4}}\nonumber \\&\quad>2D-8+(D-3)\frac{C_{5D-15}^{2D-4}-10C_{3D-9}^{2D-4}}{C_{5D-15}^{2D-4}+10C_{3D-9}^{2D-4}}\nonumber \\&\quad =2D-8+(D-3)\frac{1-10y}{1+10y}>2D-6. \end{aligned}$$
(B.86)
In the last line of the above equation, we use the fact that \(D>6\) and
$$\begin{aligned} y=\frac{C_{3D-9}^{2D-4}}{C_{5D-15}^{2D-4}}<(3/5)^{2D-4}<(3/5)^8<0.017. \end{aligned}$$
(B.87)
So the right term of (B.84) is greater than the left term of (B.84) and the \(D_1\) term in the difference (B.72) is positive.
Then according to the positivity of the four terms in the difference (B.72), we obtain
$$\begin{aligned} \text {sign}(b_{2D-4})\geqslant \text {sign}(b_{2D-3}). \end{aligned}$$
(B.88)
1.4 B.4 Coefficients of \(z^p\), \( p=2D-4, 2D-5, 2D-6\)
In this subsection, we will consider the sign relations between the coefficients of \(z^p\), \( p=2D-4, 2D-5, 2D-6\). \(b_{2D-4}\) is already given in the last subsection. The left two coefficients are
$$\begin{aligned} b_{2D-5}= & {} a_5 C_{5D-15}^{2D-5}r_h^{3D-10}+a'_4 C_{4D-10}^{2D-5}r_h^{2D-5}+a_4C_{4D-12}^{2D-5}r_h^{2D-7} \nonumber \\&+a'_3 C_{3D-7}^{2D-5}r_h^{D-2}+a_3 C_{3D-9}^{2D-5} r_h^{D-4}+a'_2 C_{2D-4}^{2D-5}r_h^{1}\nonumber \\= & {} r_h^{-1}(-m^3 D_1)(C_{5D-15}^{2D-5}-5C_{4D-12}^{2D-5}+10C_{3D-9}^{2D-5})\nonumber \\&+r_h^{-1}(-4m^3\lambda _l)(C_{5D-15}^{2D-5}+(D-6)C_{4D-12}^{2D-5}\nonumber \\&+(9-2D)C_{3D-9}^{2D-5})\nonumber \\&+4r_h(D-3)m^3(C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5})(c_D e- \omega )\nonumber \\&\times \left( \frac{ (C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}) c_D e}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}-\omega \right) \nonumber \\&+4r_h(D-3)m^3(\mu ^2-\omega ^2)(2C_{3D-7}^{2D-5}\nonumber \\&-C_{4D-10}^{2D-5}-C_{2D-4}^{2D-5}), \end{aligned}$$
(B.89)
$$\begin{aligned} b_{2D-6}= & {} a_5 C_{5D-15}^{2D-6}r_h^{3D-9}+a'_4 C_{4D-10}^{2D-6}r_h^{2D-4}+a_4C_{4D-12}^{2D-6}r_h^{2D-6} \nonumber \\&+a'_3 C_{3D-7}^{2D-6}r_h^{D-1}+a_3 C_{3D-9}^{2D-6} r_h^{D-3}+a'_2 C_{2D-4}^{2D-6}r_h^{2} \nonumber \\&+a_2C_{2D-6}^{2D-6}\nonumber \\= & {} (-m^3 D_1)(C_{5D-15}^{2D-6}-5C_{4D-12}^{2D-6}+10C_{3D-9}^{2D-6}-10)\nonumber \\&+(-4m^3\lambda _l)(C_{5D-15}^{2D-6}+(D-6)C_{4D-12}^{2D-6}\nonumber \\&+(9-2D)C_{3D-9}^{2D-6}+D-4)\nonumber \\&+4r_h^2(D-3)m^3(C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6})(c_D e- \omega )\nonumber \\&\times \left( \frac{ (C_{3D-7}^{2D-6}+C_{2D-4}^{2D-6}) c_D e}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}-\omega \right) \nonumber \\&+4r_h^2(D-3)m^3(\mu ^2-\omega ^2)(2C_{3D-7}^{2D-6}\nonumber \\&-C_{4D-10}^{2D-6}-C_{2D-4}^{2D-6}). \end{aligned}$$
(B.90)
1.4.1 B.4.1 \(\tilde{b}_{2D-4}<\tilde{b}_{2D-5}\)
Consider the difference between two normalized coefficients, \(\tilde{b}_{2D-4},\tilde{b}_{2D-5}\),
$$\begin{aligned}&\tilde{b}_{2D-5}-\tilde{b}_{2D-4}\nonumber \\&\quad =\frac{r_h}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}b_{2D-5}-\tilde{b}_{2D-4}.\nonumber \\ \end{aligned}$$
(B.91)
This difference can be decomposed into four terms and we will analyze term by term.
First, let’s consider the \((\mu ^2-\omega ^2)\) term in the difference (B.91), which is
$$\begin{aligned}&4(D-3)m^3r_h^2(\mu ^2-\omega ^2)\left[ \frac{2C_{3D-7}^{2D-5}-C_{4D-10}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}} x\right. \nonumber \\&\quad \left. -\frac{2C_{3D-7}^{2D-4}-C_{4D-10}^{2D-4}-1}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\right] . \end{aligned}$$
(B.92)
This term will prove to be positive. The positivity of the factor in the square bracket is equivalent to
$$\begin{aligned}&\frac{2C_{3D-7}^{2D-5}-C_{4D-10}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad >\frac{2C_{3D-7}^{2D-4}-C_{4D-10}^{2D-4}-1}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&\quad \Leftrightarrow \frac{-2C_{3D-7}^{2D-5}+C_{4D-10}^{2D-5}+C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad<\frac{-2C_{3D-7}^{2D-4}+C_{4D-10}^{2D-4}+1}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad<\frac{C_{4D-10}^{2D-4}-2C_{3D-7}^{2D-4}+1}{C_{4D-10}^{2D-5}-2C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}\nonumber \\&\quad \Leftrightarrow \frac{(2D-5)C_{4D-10}^{2D-5}+(D-2)2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad <\frac{(2D-5)C_{4D-10}^{2D-5}-(D-2)2C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}-2C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}.\nonumber \\ \end{aligned}$$
(B.93)
The left and right terms of the above inequality can be reduced as follows
$$\begin{aligned}&\frac{(2D-5)C_{4D-10}^{2D-5}+(D-2)2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad =D-2+(D-3)\frac{C_{4D-10}^{2D-5}+C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}, \end{aligned}$$
(B.94)
$$\begin{aligned}&\frac{(2D-5)C_{4D-10}^{2D-5}-(D-2)2C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}-2C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}\nonumber \\&\quad =D-2+(D-3)\frac{C_{4D-10}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}-2C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}.\nonumber \\ \end{aligned}$$
(B.95)
Now we can get the difference between the above two terms, which is obviously positive,
$$\begin{aligned}&(D-3)\frac{4C_{4D-10}^{2D-5}(C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5})}{(C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5})(C_{4D-10}^{2D-5}-2C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5})}\nonumber \\&\quad >0.\nonumber \\ \end{aligned}$$
(B.96)
So the \((\mu ^2-\omega ^2)\) term in the difference (B.91) is positive.
Secondly, let’s see the \((c_D e-\omega )\) term in the difference (B.91), which is
$$\begin{aligned}&4(D-3)m^3r_h^2(c_D e-\omega )c_D e[\frac{C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad -\frac{ C_{3D-7}^{2D-4}+1}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}]. \end{aligned}$$
(B.97)
We will prove its positivity in the following. Given the superradiant condition, the factor \(4(D-3)m^3r_h^2(c_D e-\omega )c_D e\) is positive. We just need to prove
$$\begin{aligned}&\frac{C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}>\frac{ C_{3D-7}^{2D-4}+1}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}>\frac{ C_{3D-7}^{2D-4}+1}{C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}\nonumber \\&\quad \Leftrightarrow \frac{(2D-5)C_{4D-10}^{2D-5}+(D-2)2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad >\frac{ (D-2)C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}{C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}. \end{aligned}$$
(B.98)
It is obvious that the right term of the above inequality is less than \(D-2\). For the left term of the above inequality, we have
$$\begin{aligned}&\frac{(2D-5)C_{4D-10}^{2D-5}+(D-2)2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad =D-2+(D-3)\frac{C_{4D-10}^{2D-5}+C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad >D-2. \end{aligned}$$
(B.99)
So the \((c_D e-\omega )\) term in the difference (B.91) is positive.
Thirdly, let’s see the \(\lambda _l\) term in the difference (B.91), which is
$$\begin{aligned} -4m^3\lambda _l\Bigg [\frac{C_{5D-15}^{2D-5}+(D-6)C_{4D-12}^{2D-5}+(9-2D)C_{3D-9}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\ -\frac{C_{5D-15}^{2D-4}+(D-6)C_{4D-12}^{2D-4}+(9-2D)C_{3D-9}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\Bigg ].\nonumber \\ \end{aligned}$$
(B.100)
It will be shown to be positive. The positivity of this above term is equivalent to the negativity of the factor in the square bracket, i.e.
$$\begin{aligned}&\frac{C_{5D-15}^{2D-5}+(D-6)C_{4D-12}^{2D-5}+(9-2D)C_{3D-9}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad<\frac{C_{5D-15}^{2D-4}+(D-6)C_{4D-12}^{2D-4}+(9-2D)C_{3D-9}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad<\frac{C_{5D-15}^{2D-4}+(D-6)C_{4D-12}^{2D-4}+(9-2D)C_{3D-9}^{2D-4}}{C_{5D-15}^{2D-5}+(D-6)C_{4D-12}^{2D-5}+(9-2D)C_{3D-9}^{2D-5}}\nonumber \\&\quad \Leftrightarrow \frac{(2D-5)C_{4D-10}^{2D-5}+(D-2)2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad <\frac{(3D-10)C_{5D-15}^{2D-5}+(2D-7)(D-6)C_{4D-12}^{2D-5}+(D-4)(9-2D)C_{3D-9}^{2D-5}}{C_{5D-15}^{2D-5}+(D-6)C_{4D-12}^{2D-5}+(9-2D)C_{3D-9}^{2D-5}}. \end{aligned}$$
(B.101)
For the left term of the above inequality (B.101), we have
$$\begin{aligned}&\frac{(2D-5)C_{4D-10}^{2D-5}+(D-2)2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad =2D-5+\frac{(6-2D) (C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5})}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}<2D-5.\nonumber \\ \end{aligned}$$
(B.102)
For the right term of the inequality (B.101), when \(D>6\), we have
$$\begin{aligned}&\frac{(3D-10)C_{5D-15}^{2D-5}+(2D-7)(D-6)C_{4D-12}^{2D-5}+(D-4)(9-2D)C_{3D-9}^{2D-5}}{C_{5D-15}^{2D-5}+(D-6)C_{4D-12}^{2D-5}+(9-2D)C_{3D-9}^{2D-5}}\nonumber \\&\quad =2D-7+\frac{(D-3)C_{5D-15}^{2D-5}+(3-D)(9-2D)C_{3D-9}^{2D-5}}{C_{5D-15}^{2D-5}+(D-6)C_{4D-12}^{2D-5}+(9-2D)C_{3D-9}^{2D-5}}\nonumber \\&\quad>2D-7+\frac{(D-3)C_{5D-15}^{2D-5}}{C_{5D-15}^{2D-5}+(D-6)C_{4D-12}^{2D-5}}\nonumber \\&\quad =2D-7+\frac{D-3}{1+(D-6)C_{4D-12}^{2D-5}/C_{5D-15}^{2D-5}}\nonumber \\&\quad>2D-7+\frac{D-3}{1+(D-6)(4/5)^{2D-5}}\nonumber \\&\quad >2D-7+3=2D-4. \end{aligned}$$
(B.103)
So we prove that the right term is greater than the left term in the inequality (B.101) and the \(\lambda _l\) term in the difference (B.91) is positive.
Finally, let’s see the \(D_1\) term in the difference (B.91), which is
$$\begin{aligned}&-m^3D_1[\frac{C_{5D-15}^{2D-5}-5C_{4D-12}^{2D-5}+10C_{3D-9}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad -\frac{C_{5D-15}^{2D-4}-5C_{4D-12}^{2D-4}+10C_{3D-9}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}]. \end{aligned}$$
(B.104)
The positivity of the above term is equivalent to the negativity of the factor in the square bracket, i.e.
$$\begin{aligned}&\frac{C_{5D-15}^{2D-5}-5C_{4D-12}^{2D-5}+10C_{3D-9}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad<\frac{C_{5D-15}^{2D-4}-5C_{4D-12}^{2D-4}+10C_{3D-9}^{2D-4}}{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{2D-4}+2 C_{3D-7}^{2D-4}-1}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad<\frac{C_{5D-15}^{2D-4}-5C_{4D-12}^{2D-4}+10C_{3D-9}^{2D-4}}{C_{5D-15}^{2D-5}-5C_{4D-12}^{2D-5}+10C_{3D-9}^{2D-5}}\nonumber \\&\quad \Leftrightarrow \frac{(2D-5)C_{4D-10}^{2D-5}+(D-2)2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad <\frac{(3D-10)C_{5D-15}^{2D-5}-(2D-7)5C_{4D-12}^{2D-5}+(D-4)10C_{3D-9}^{2D-5}}{C_{5D-15}^{2D-5}-5C_{4D-12}^{2D-5}+10C_{3D-9}^{2D-5}}.\nonumber \\ \end{aligned}$$
(B.105)
For the left term of the above inequality (B.105), we have
$$\begin{aligned}&\frac{(2D-5)C_{4D-10}^{2D-5}+(D-2)2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad =2D-5+\frac{(6-2D)(C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5})}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}<2D-5.\nonumber \\ \end{aligned}$$
(B.106)
For the right term of the inequality (B.105), we have
$$\begin{aligned}&\frac{(3D-10)C_{5D-15}^{2D-5}-(2D-7)5C_{4D-12}^{2D-5}+(D-4)10C_{3D-9}^{2D-5}}{C_{5D-15}^{2D-5}-5C_{4D-12}^{2D-5}+10C_{3D-9}^{2D-5}}\nonumber \\&\quad =2D-7+\frac{(D-3)(C_{5D-15}^{2D-5}-10C_{3D-9}^{2D-5})}{C_{5D-15}^{2D-5}-5C_{4D-12}^{2D-5}+10C_{3D-9}^{2D-5}}\nonumber \\&\quad>2D-7+\frac{(D-3)(C_{5D-15}^{2D-5}-10C_{3D-9}^{2D-5})}{C_{5D-15}^{2D-5}+10C_{3D-9}^{2D-5}}\nonumber \\&\quad>2D-7+(D-3)\frac{1-10C_{3D-9}^{2D-5}/C_{5D-15}^{2D-5}}{1+10C_{3D-9}^{2D-5}/C_{5D-15}^{2D-5}}\nonumber \\&\quad>2D-7+(D-3)\frac{1-10(3/5)^{2D-5}}{1+10(3/5)^{2D-5}}\nonumber \\&\quad >2D-7+3=2D-4. \end{aligned}$$
(B.107)
So we prove that the right term is greater than the left term in the inequality (B.105).
According to the positivity of the four terms in the difference (B.91), we obtain
$$\begin{aligned} \text {sign}(b_{2D-5})\geqslant \text {sign}(b_{2D-4}). \end{aligned}$$
(B.108)
1.4.2 B.4.2 \(\tilde{b}_{2D-5}<\tilde{b}_{2D-6}\)
Now, consider the difference between two normalized coefficients, \(\tilde{b}_{2D-6},\tilde{b}_{2D-5}\),
$$\begin{aligned} \tilde{b}_{2D-6}-\tilde{b}_{2D-5}=\frac{b_{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}-\tilde{b}_{2D-5}\nonumber \\ \end{aligned}$$
(B.109)
The difference can be decomposed into four terms and we will analyze term by term.
First, let’s see the \((\mu ^2-\omega ^2)\) term in the difference (B.109),which is
$$\begin{aligned} 4(D-3)m^3 r_h^2(\mu ^2-\omega ^2)\Bigg [\frac{2C_{3D-7}^{2D-6}-C_{4D-10}^{2D-6}-C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\ -\frac{2C_{3D-7}^{2D-5}-C_{4D-10}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\Bigg ].\nonumber \\ \end{aligned}$$
(B.110)
The positivity of this term is equivalent to the positivity of the factor in the square bracket, i.e.
$$\begin{aligned}&\frac{2C_{3D-7}^{2D-6}-C_{4D-10}^{2D-6}-C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad >\frac{2C_{3D-7}^{2D-5}-C_{4D-10}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad \Leftrightarrow \frac{-2C_{3D-7}^{2D-6}+C_{4D-10}^{2D-6}+C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad<\frac{-2C_{3D-7}^{2D-5}+C_{4D-10}^{2D-5}+C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad<\frac{C_{4D-10}^{2D-5}-2C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-6}-2C_{3D-7}^{2D-6}+C_{2D-4}^{2D-6}}\nonumber \\&\quad \Leftrightarrow \frac{(2D-4)C_{4D-10}^{2D-6}+(D-1)2 C_{3D-7}^{2D-4}-2C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad <\frac{(2D-4)C_{4D-10}^{2D-6}-(D-1)2C_{3D-7}^{2D-6}+2C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}-2C_{3D-7}^{2D-6}+C_{2D-4}^{2D-6}}.\nonumber \\ \end{aligned}$$
(B.111)
For the left term of the above inequality, we have
$$\begin{aligned}&\frac{(2D-4)C_{4D-10}^{2D-6}+(D-1)2 C_{3D-7}^{2D-4}-2C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad =D-1+\frac{(D-3)C_{4D-10}^{2D-6}+(D-3)C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}.\nonumber \\ \end{aligned}$$
(B.112)
For the right term of the inequality (B.111), we have
$$\begin{aligned}&\frac{(2D-4)C_{4D-10}^{2D-6}-(D-1)2C_{3D-7}^{2D-6}+2C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}-2C_{3D-7}^{2D-6}+C_{2D-4}^{2D-6}}\nonumber \\&\quad =D-1+\frac{(D-3)C_{4D-10}^{2D-6}-(D-3)C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}-2C_{3D-7}^{2D-6}+C_{2D-4}^{2D-6}}.\nonumber \\ \end{aligned}$$
(B.113)
Then the difference between the right term and the left term of the inequality (B.111) is
$$\begin{aligned} \frac{4(D-3)C_{4D-10}^{2D-6}(C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6})}{(C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6})(C_{4D-10}^{2D-6}-2C_{3D-7}^{2D-6}+C_{2D-4}^{2D-6})},\nonumber \\ \end{aligned}$$
(B.114)
which is obviously positive. So the \((\mu ^2-\omega ^2)\) term in the difference (B.109) is positive.
Secondly, let’s see the \((c_D e-\omega )\) term in the difference (B.109),which is
$$\begin{aligned}&4(D-3)m^3r_h^2(c_D e-\omega )c_D e[\frac{C_{3D-7}^{2D-6}+C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad -\frac{C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}]. \end{aligned}$$
(B.115)
The positivity of the above term is equivalent to the positivity of the factor in the square bracket, i.e.
$$\begin{aligned}&\frac{C_{3D-7}^{2D-6}+C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}>\frac{C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}>\frac{C_{3D-7}^{2D-5}+C_{2D-4}^{2D-5}}{C_{3D-7}^{2D-6}+C_{2D-4}^{2D-6}}\nonumber \\&\quad \Leftrightarrow \frac{(2D-4)C_{4D-10}^{2D-6}+(D-1)2 C_{3D-7}^{2D-6}-2C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad >\frac{(D-1)C_{3D-7}^{2D-6}+2C_{2D-4}^{2D-6}}{C_{3D-7}^{2D-6}+C_{2D-4}^{2D-6}}. \end{aligned}$$
(B.116)
For the right term of the above inequality, when \(D>6\), it is easy to see that
$$\begin{aligned} \frac{(D-1)C_{3D-7}^{2D-6}+2C_{2D-4}^{2D-6}}{C_{3D-7}^{2D-6}+C_{2D-4}^{2D-6}}<D-1. \end{aligned}$$
(B.117)
For the left term of the inequality (B.116), we have
$$\begin{aligned}&\frac{(2D-4)C_{4D-10}^{2D-6}+(D-1)2 C_{3D-7}^{2D-6}-2C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad =D-1+\frac{(D-3)C_{4D-10}^{2D-6}+(D-3)C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}>D-1.\nonumber \\ \end{aligned}$$
(B.118)
So the left term is greater than the right term of the inequality (B.116). The \((c_D e-\omega )\) term in the difference (B.109) is positive.
Thirdly, let’s see the \(\lambda _l\) term in the difference (B.109), which is
$$\begin{aligned}&-4m^3\lambda _l\Bigg [\frac{C_{5D-15}^{2D-6}+(D-6)C_{4D-12}^{2D-6}+(9-2D)C_{3D-9}^{2D-6}+D-4}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad -\frac{C_{5D-15}^{2D-5}+(D-6)C_{4D-12}^{2D-5}+(9-2D)C_{3D-9}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\Bigg ]. \end{aligned}$$
(B.119)
The positivity of the above term is equivalent to the negativity of the factor in the square bracket, i.e.
$$\begin{aligned}&\frac{C_{5D-15}^{2D-6}+(D-6)C_{4D-12}^{2D-6}+(9-2D)C_{3D-9}^{2D-6}+D-4}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad<\frac{C_{5D-15}^{2D-5}+(D-6)C_{4D-12}^{2D-5}+(9-2D)C_{3D-9}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad<\frac{C_{5D-15}^{2D-5}+(D-6)C_{4D-12}^{2D-5}+(9-2D)C_{3D-9}^{2D-5}}{C_{5D-15}^{2D-6}+(D-6)C_{4D-12}^{2D-6}+(9-2D)C_{3D-9}^{2D-6}+D-4}\nonumber \\&\quad \Leftrightarrow \frac{(2D-4)C_{4D-10}^{2D-6}+(D-1)2 C_{3D-7}^{2D-6}-2C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad <\frac{(3D-9)C_{5D-15}^{2D-6}+(2D-6)(D-6)C_{4D-12}^{2D-6}+(D-3)(9-2D)C_{3D-9}^{2D-6}}{C_{5D-15}^{2D-6}+(D-6)C_{4D-12}^{2D-6}+(9-2D)C_{3D-9}^{2D-6}+D-4}.\nonumber \\ \end{aligned}$$
(B.120)
For the left term of the above inequality, we have
$$\begin{aligned}&\frac{(2D-4)C_{4D-10}^{2D-6}+(D-1)2 C_{3D-7}^{2D-6}-2C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad =2D-4+\frac{(6-2D)(C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6})}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}<2D-4.\nonumber \\ \end{aligned}$$
(B.121)
For the right term of the inequality (B.120), we have
$$\begin{aligned}&\frac{(3D-9)C_{5D-15}^{2D-6}+(2D-6)(D-6)C_{4D-12}^{2D-6}+(D-3)(9-2D)C_{3D-9}^{2D-6}}{C_{5D-15}^{2D-6}+(D-6)C_{4D-12}^{2D-6}+(9-2D)C_{3D-9}^{2D-6}+D-4}\nonumber \\&\quad =2D-6+\frac{(D-3)C_{5D-15}^{2D-6}+(D-3)(2D-9)C_{3D-9}^{2D-6}-(2D-6)(D-4)}{C_{5D-15}^{2D-6}+(D-6)C_{4D-12}^{2D-6}+(9-2D)C_{3D-9}^{2D-6}+D-4}\nonumber \\&\quad>2D-6+\frac{(D-3)C_{5D-15}^{2D-6}}{C_{5D-15}^{2D-6}+(D-6)C_{4D-12}^{2D-6}}\nonumber \\&\quad>2D-6+\frac{D-3}{1+(D-6)(4/5)^{2D-6}}\nonumber \\&\quad >2D-6+3=2D-3. \end{aligned}$$
(B.122)
So the right term is greater than the left term of the inequality (B.120). The \(\lambda _l\) term in the difference (B.109) is positive.
Finally, let see the \(D_1\) term in the difference (B.109),which is
$$\begin{aligned}&-m^3D_1\Bigg [\frac{C_{5D-15}^{2D-6}-5C_{4D-12}^{2D-6}+10C_{3D-9}^{2D-6}-10}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad -\frac{C_{5D-15}^{2D-5}-5C_{4D-12}^{2D-5}+10C_{3D-9}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\Bigg ]. \end{aligned}$$
(B.123)
The positivity of the above term is equivalent to the negativity of the factor in the square bracket, i.e.
$$\begin{aligned}&\frac{C_{5D-15}^{2D-6}-5C_{4D-12}^{2D-6}+10C_{3D-9}^{2D-6}-10}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad<\frac{C_{5D-15}^{2D-5}-5C_{4D-12}^{2D-5}+10C_{3D-9}^{2D-5}}{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{2D-5}+2 C_{3D-7}^{2D-5}-C_{2D-4}^{2D-5}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad<\frac{C_{5D-15}^{2D-5}-5C_{4D-12}^{2D-5}+10C_{3D-9}^{2D-5}}{C_{5D-15}^{2D-6}-5C_{4D-12}^{2D-6}+10C_{3D-9}^{2D-6}-10}\nonumber \\&\quad \Leftrightarrow \frac{(2D-4)C_{4D-10}^{2D-6}+(D-1)2 C_{3D-7}^{2D-6}-2C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \\&\quad <\frac{(3D-9)C_{5D-15}^{2D-6}-(2D-6)5C_{4D-12}^{2D-6}+(D-3)10C_{3D-9}^{2D-6}}{C_{5D-15}^{2D-6}-5C_{4D-12}^{2D-6}+10C_{3D-9}^{2D-6}-10}. .\nonumber \\ \end{aligned}$$
(B.124)
For the left term of the above inequality, we have
$$\begin{aligned}&\frac{(2D-4)C_{4D-10}^{2D-6}+(D-1)2 C_{3D-7}^{2D-6}-2C_{2D-4}^{2D-6}}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}\nonumber \nonumber \\&\quad =2D-4+\frac{(6-2D) (C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6})}{C_{4D-10}^{2D-6}+2 C_{3D-7}^{2D-6}-C_{2D-4}^{2D-6}}<2D-4.\nonumber \\ \end{aligned}$$
(B.125)
For the right term of the inequality (B.124), we have
$$\begin{aligned}&\frac{(3D-9)C_{5D-15}^{2D-6}-(2D-6)5C_{4D-12}^{2D-6}+(D-3)10C_{3D-9}^{2D-6}}{C_{5D-15}^{2D-6}-5C_{4D-12}^{2D-6}+10C_{3D-9}^{2D-6}-10}\nonumber \\&\quad =2D-6+\frac{(D-3)C_{5D-15}^{2D-6}+(3-D)10C_{3D-9}^{2D-6}+10(2D-6)}{C_{5D-15}^{2D-6}-5C_{4D-12}^{2D-6}+10C_{3D-9}^{2D-6}-10}\nonumber \\&\quad>2D-6+(D-3)\frac{C_{5D-15}^{2D-6}-10C_{3D-9}^{2D-6}}{C_{5D-15}^{2D-6}+10C_{3D-9}^{2D-6}}\nonumber \\&\quad>2D-6+(D-3)\frac{1-10(3/5)^{2D-6}}{1+10(3/5)^{2D-6}}>2D-4. \end{aligned}$$
(B.126)
So the right term is greater than the left term of the inequality (B.124). The \(D_1\) term in the difference (B.109) is positive.
Based on the positivity of the four terms in the difference (B.109), we obtain
$$\begin{aligned} \text {sign}(b_{2D-6})\geqslant \text {sign}(b_{2D-5}). \end{aligned}$$
(B.127)
1.5 B.5 Coefficients of \(z^p\), \( 2D-6> p>D-3\)
Since \(D>6(\geqslant 7)\), we have \(p\geqslant D-2\geqslant 5\) in this case. For \( C_{5D-15}^{p}, C_{4D-12}^{p}, C_{3D-9}^{p} \), we have the following inequalities
$$\begin{aligned}&\frac{C_{3D-9}^{p}}{C_{5D-15}^{p}}<(3/5)^p<(3/5)^5\Rightarrow C_{5D-15}^{p}\nonumber \\&\quad>(5/3)^5C_{3D-9}^{p}>12 C_{3D-9}^{p},\nonumber \\&\frac{C_{3D-9}^{p}}{C_{4D-12}^{p}}<(3/4)^p<(3/4)^5\Rightarrow C_{4D-12}^{p}\nonumber \\&\quad>(4/3)^5C_{3D-9}^{p}>4 C_{3D-9}^{p}. \end{aligned}$$
(B.128)
The coefficient of \(z^p\) when \( 2D-6> p>D-3\) is
$$\begin{aligned} b_{p}= & {} a_5 C_{5D-15}^{p}r_h^{5D-15-p}+a'_4 C_{4D-10}^{p}r_h^{4D-10-p}\nonumber \\&+a_4C_{4D-12}^{p}r_h^{4D-12-p}+a'_3 C_{3D-7}^{p}r_h^{3D-7-p} \nonumber \\&+a_3 C_{3D-9}^{p} r_h^{3D-9-p}+a'_2 C_{2D-4}^{p}r_h^{2D-4-p} \nonumber \\&+a_2C_{2D-6}^{p}r_h^{2D-6-p}\nonumber \\= & {} r_h^{-p}(-m^5 D_1)(C_{5D-15}^{p}-5C_{4D-12}^{p}\nonumber \\&+10C_{3D-9}^p-10C_{2D-6}^{p})+r_h^{-p}(-4m^5\lambda _l)(C_{5D-15}^{p}\nonumber \\&+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p\nonumber \\&+(D-4)C_{2D-6}^{p})\nonumber \\&+r_h^{-p+2}4(D-3)m^5(C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p})\nonumber \\&\times (c_D e- \omega )\nonumber \\&\times \left( \frac{(C_{3D-7}^{p}+C_{2D-4}^{p}) c_D e}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}-\omega \right) \nonumber \\&+r_h^{-p+2}4(D-3)m^5(\mu ^2-\omega ^2)(2C_{3D-7}^{p}\nonumber \\&-C_{4D-10}^{p}-C_{2D-4}^{p}). \end{aligned}$$
(B.129)
Now we consider the difference between two normalized coefficients, \(\tilde{b}_{p},\tilde{b}_{p+1}\),
$$\begin{aligned}&\tilde{b}_{p}-\tilde{b}_{p+1}=\frac{r_h^p}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}b_{p} \nonumber \\&\quad -\frac{r_h^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}b_{p+1} \end{aligned}$$
(B.130)
The difference can be decomposed into four terms and we will analyze term by term.
First, let’s see the \((\mu ^2-\omega ^2)\) term in the difference (B.130), which is
$$\begin{aligned}&4(D-3)m^5r_h^2(\mu ^2-\omega ^2)\Bigg [\frac{2C_{3D-7}^{p}-C_{4D-10}^{p}-C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad -\frac{2C_{3D-7}^{p+1}-C_{4D-10}^{p+1}-C_{2D-4}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\Bigg ]. \end{aligned}$$
(B.131)
The positivity of the above term is equivalent to the positivity of the factor in the square bracket, i.e.
$$\begin{aligned}&\frac{2C_{3D-7}^{p}-C_{4D-10}^{p}-C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad >\frac{2C_{3D-7}^{p+1}-C_{4D-10}^{p+1}-C_{2D-4}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad<\frac{C_{4D-10}^{p+1}-2C_{3D-7}^{p+1}+C_{2D-4}^{p+1}}{C_{4D-10}^{p}-2C_{3D-7}^{p}+C_{2D-4}^{p}}\nonumber \\&\quad \Leftrightarrow \frac{(4D-p-10)C_{4D-10}^{p}+(3D-p-7)2 C_{3D-7}^{p}-(2D-p-4)C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&<\frac{(4D-p-10)C_{4D-10}^{p}-(3D-p-7)2C_{3D-7}^{p}+(2D-p-4)C_{2D-4}^{p}}{C_{4D-10}^{p}-2C_{3D-7}^{p}+C_{2D-4}^{p}} \end{aligned}$$
(B.132)
After a straightforward calculation, the difference of the right and left terms of the above inequality is
$$\begin{aligned}&\frac{4(D-3)C_{4D-10}^{p}( C_{3D-7}^{p}-C_{2D-4}^{p})}{(C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p})(C_{4D-10}^{p}-2C_{3D-7}^{p}+C_{2D-4}^{p})}\nonumber \\&\quad >0. \end{aligned}$$
So the \((\mu ^2-\omega ^2)\) term in the difference (B.130) is positive.
Secondly, let’s see the \((c_D e-\omega )\) term in the difference (B.130), which is
$$\begin{aligned}&4(D-3)m^5r_h^2(c_D e-\omega )c_D e\Bigg [\frac{C_{3D-7}^{p}+C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad -\frac{C_{3D-7}^{p+1}+C_{2D-4}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\Bigg ] \end{aligned}$$
(B.133)
The positivity of the above term is equivalent to the positivity of the factor in the square bracket, i.e.
$$\begin{aligned}&\frac{C_{3D-7}^{p}+C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}> \frac{C_{3D-7}^{p+1}+C_{2D-4}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\nonumber \\&\quad \Leftrightarrow \frac{(4D-p-10)C_{4D-10}^{p}+(3D-p-7)2 C_{3D-7}^{p}-(2D-p-4)C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad >\frac{(3D-p-7)C_{3D-7}^{p}+(2D-p-4)C_{2D-4}^{p}}{C_{3D-7}^{p}+C_{2D-4}^{p}}. \end{aligned}$$
(B.134)
For the right term of the above inequality, it is easy to see that
$$\begin{aligned}&\frac{(3D-p-7)C_{3D-7}^{p}+(2D-p-4)C_{2D-4}^{p}}{C_{3D-7}^{p}+C_{2D-4}^{p}}\nonumber \\&\quad <3D-p-7. \end{aligned}$$
(B.135)
For the left term of the inequality (B.134), we have
$$\begin{aligned}&\frac{(4D-p-10)C_{4D-10}^{p}+(3D-p-7)2 C_{3D-7}^{p}-(2D-p-4)C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad =3D-p-7+\frac{(D-3)(C_{4D-10}^{p}+C_{2D-4}^{p})}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad >3D-p-7. \end{aligned}$$
(B.136)
So the left term is greater than the right term of the inequality (B.134). The \((c_D e-\omega )\) term in the difference (B.130) is positive.
Thirdly, let’s see the \(\lambda _l\) term in the difference (B.130), which is
$$\begin{aligned}&-4m^5\lambda _l\Bigg [\frac{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad -\frac{C_{5D-15}^{p+1}+(D-6)C_{4D-12}^{p+1}+(9-2D)C_{3D-9}^{p+1}+(D-4)C_{2D-6}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\Bigg ]. \end{aligned}$$
(B.137)
The positivity of the above term is equivalent to the negativity of the factor in the square bracket, i.e.
$$\begin{aligned}&\frac{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad<\frac{C_{5D-15}^{p+1}+(D-6)C_{4D-12}^{p+1}+(9-2D)C_{3D-9}^{p+1}+(D-4)C_{2D-6}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad<\frac{C_{5D-15}^{p+1}+(D-6)C_{4D-12}^{p+1}+(9-2D)C_{3D-9}^{p+1}+(D-4)C_{2D-6}^{p+1}}{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p}}\nonumber \\&\quad \Leftrightarrow \frac{(4D-p-10)C_{4D-10}^{p}+(3D-p-7)2 C_{3D-7}^{p}-(2D-p-4)C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad <\frac{a_5C_{5D-15}^{p}+a_4(D-6)C_{4D-12}^{p}+a_3(9-2D)C_{3D-9}^{p}+a_2(D-4)C_{2D-6}^{p}}{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p}}. \end{aligned}$$
(B.138)
In the above inequality, \(a_i=(D-3)i-p\). For the left term of the above inequality, we have
$$\begin{aligned}&\frac{(4D-p-10)C_{4D-10}^{p}+(3D-p-7)2 C_{3D-7}^{p}-(2D-p-4)C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad =4D-p-10+\frac{(6-2D)( C_{3D-7}^{p}-C_{2D-4}^{p})}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}<4D-p-10. \end{aligned}$$
(B.139)
For the right term of the inequality (B.138), we have
$$\begin{aligned}&\frac{a_5C_{5D-15}^{p}+a_4(D-6)C_{4D-12}^{p}+a_3(9-2D)C_{3D-9}^{p}+a_2(D-4)C_{2D-6}^{p}}{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p}}\nonumber \\&\quad =a_4+\frac{(D-3)C_{5D-15}^{p}+(3-D)(9-2D)C_{3D-9}^{p}+2(3-D)(D-4)C_{2D-6}^{p}}{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p}}\nonumber \\&\quad>4D-p-12\nonumber \\&\qquad +\frac{(D-3)C_{5D-15}^{p}}{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}}\nonumber \\&\quad>4D-p-12\nonumber \\&\qquad +\frac{D-3}{1+(D-6)(4/5)^{4}}>4D-p-10. \end{aligned}$$
(B.140)
So the right term is greater than the left term of the inequality (B.138). The \(\lambda _l\) term in the difference (B.130) is positive.
Finally, let’s see the \(D_1\) term in the difference (B.130), which is
$$\begin{aligned}&-m^5D_1\Bigg [\frac{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad -\frac{C_{5D-15}^{p+1}-5C_{4D-12}^{p+1}+10C_{3D-9}^{p+1}-10C_{2D-6}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\Bigg ].\nonumber \\ \end{aligned}$$
(B.141)
The positivity of the above term is equivalent to the negativity of the factor in the square bracket, i.e.
$$\begin{aligned}&\frac{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad<\frac{C_{5D-15}^{p+1}-5C_{4D-12}^{p+1}+10C_{3D-9}^{p+1}-10C_{2D-6}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\nonumber \\&\frac{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad<\frac{C_{5D-15}^{p+1}-5C_{4D-12}^{p+1}+10C_{3D-9}^{p+1}-10C_{2D-6}^{p+1}}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}}\nonumber \\&\quad \Leftrightarrow \frac{(4D-p-10)C_{4D-10}^{p}+(3D-p-7)2 C_{3D-7}^{p}-(2D-p-4)C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad <\frac{a_5C_{5D-15}^{p}-a_45C_{4D-12}^{p}+a_310C_{3D-9}^{p}-a_210C_{2D-6}^{p}}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}} \end{aligned}$$
(B.142)
For the left term of the above inequality, we have
$$\begin{aligned}&\frac{(4D-p-10)C_{4D-10}^{p}+(3D-p-7)2 C_{3D-7}^{p}-(2D-p-4)C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad =4D-p-10 +\frac{(6-2D) (C_{3D-7}^{p}-C_{2D-4}^{p})}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad <4D-p-10. \end{aligned}$$
(B.143)
For the right term of the inequality (B.142), we have
$$\begin{aligned}&\frac{a_5C_{5D-15}^{p}-a_45C_{4D-12}^{p}+a_310C_{3D-9}^{p}-a_210C_{2D-6}^{p}}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}}\nonumber \\&\quad =a_4+\frac{(D-3)C_{5D-15}^{p}+(3-D)10C_{3D-9}^{p}-(6-2D)10C_{2D-6}^{p}}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}}\nonumber \\&\quad =4D-p-12+\frac{(D-3)(C_{5D-15}^{p}-10C_{3D-9}^{p}+20C_{2D-6}^{p})}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}}\nonumber \\&\quad>4D-p-12+(D-3)/2>4D-p-10. \end{aligned}$$
(B.144)
In the above proof, it is based on the following results,
$$\begin{aligned}&\frac{C_{5D-15}^{p}-10C_{3D-9}^{p}+20C_{2D-6}^{p}}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}}>1/2\nonumber \\&\quad \Leftrightarrow 2(C_{5D-15}^{p}-10C_{3D-9}^{p}+20C_{2D-6}^{p})\nonumber \\&\quad>C_{5D-15}^{p}-5C_{4D-12}^{p}\nonumber \\&\qquad +10C_{3D-9}^p-10C_{2D-6}^{p}\nonumber \\&\quad \Leftrightarrow C_{5D-15}^{p}+5C_{4D-12}^{p}-30C_{3D-9}^{p}+50C_{2D-6}^{p}>0,\nonumber \\ \end{aligned}$$
(B.145)
and
$$\begin{aligned}&C_{5D-15}^{p}+5C_{4D-12}^{p}-30C_{3D-9}^{p}+50C_{2D-6}^{p}\nonumber \\&\quad>12C_{3D-9}^{p}+5*4C_{3D-9}^{p}-30C_{3D-9}^{p}+50C_{2D-6}^{p}\nonumber \\&\quad =2C_{3D-9}^{p}+50C_{2D-6}^{p}>0, \end{aligned}$$
(B.146)
where the inequalities (B.128) are used. So the right term is greater than the left term of the inequality (B.142). The \(D_1\) term in the difference (B.130) is positive.
Based on the positivity of the four terms in the difference (B.130), we obtain that when \(2D-6>p>D-3\),
$$\begin{aligned} \text {sign}(b_{p})\geqslant \text {sign}(b_{p+1}). \end{aligned}$$
(B.147)
1.6 B.6 Coefficients of \(z^p\), \( p=D-2, D-3\)
In this subsection, we consider the coefficients of \(z^p\), \( p=D-2, D-3\), which are
$$\begin{aligned} b_{D-2}= & {} a_5 C_{5D-15}^{D-2}r_h^{4D-13}+a'_4 C_{4D-10}^{D-2}r_h^{3D-8}\nonumber \\&+a_4C_{4D-12}^{D-2}r_h^{3D-10} \nonumber \\&+a'_3 C_{3D-7}^{D-2}r_h^{2D-5}+a_3 C_{3D-9}^{D-2} r_h^{2D-7} \nonumber \\&+a'_2 C_{2D-4}^{D-2}r_h^{D-2}+a_2C_{2D-6}^{D-2}r_h^{D-4}\nonumber \\= & {} r_h^{-D+2}(-m^5 D_1)(C_{5D-15}^{D-2}-5C_{4D-12}^{D-2}\nonumber \\&+10C_{3D-9}^{D-2}-10C_{2D-6}^{D-2})\nonumber \\&+r_h^{-D+2}(-4m^5\lambda _l)(C_{5D-15}^{D-2}+(D-6)C_{4D-12}^{D-2}\nonumber \\&+(9-2D)C_{3D-9}^{D-2}+(D-4)C_{2D-6}^{D-2})\nonumber \\&+r_h^{-D+4}4(D-3)m^5(C_{4D-10}^{D-2}+2 C_{3D-7}^{D-2}\nonumber \\&-C_{2D-4}^{D-2})(c_D e- \omega )\nonumber \\&\times \left( \frac{(C_{3D-7}^{D-2}+C_{2D-4}^{D-2}) c_D e}{C_{4D-10}^{D-2}+2 C_{3D-7}^{D-2}-C_{2D-4}^{D-2}}-\omega \right) \nonumber \\&+r_h^{-D+4}4(D-3)m^5(\mu ^2-\omega ^2)\nonumber \\&\times \left( 2C_{3D-7}^{D-2}-C_{4D-10}^{D-2}-C_{2D-4}^{D-2}\right) , \end{aligned}$$
(B.148)
$$\begin{aligned} b_{D-3}= & {} a_5 C_{5D-15}^{D-3}r_h^{4D-12}+a'_4 C_{4D-10}^{D-3}r_h^{3D-7}\nonumber \\&+a_4C_{4D-12}^{D-3}r_h^{3D-9}+a'_3 C_{3D-7}^{D-3}r_h^{2D-4} \nonumber \\&+a_3 C_{3D-9}^{D-3} r_h^{2D-6}+a'_2 C_{2D-4}^{D-3}r_h^{D-1} \nonumber \\&+a_2C_{2D-6}^{D-3}r_h^{D-3}+a_1C_{D-3}^{D-3}\nonumber \\&= (-m^4 D_1)(C_{5D-15}^{D-3}-5C_{4D-12}^{D-3}\nonumber \\&+10C_{3D-9}^{D-3}-10C_{2D-6}^{D-3}+5)\nonumber \\&+(-4m^4\lambda _l)(C_{5D-15}^{D-3}+(D-6)C_{4D-12}^{D-3}\nonumber \\&+(9-2D)C_{3D-9}^{D-3}+(D-4)C_{2D-6}^{D-3})\nonumber \\&+r_h^{2}4(D-3)m^4(C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}\nonumber \\&-C_{2D-4}^{D-3})(c_D e- \omega )\nonumber \\&\times \left( \frac{(C_{3D-7}^{D-3}+C_{2D-4}^{D-3}) c_D e}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}-\omega \right) \nonumber \\&+r_h^{2}4(D-3)m^4(\mu ^2-\omega ^2)(2C_{3D-7}^{D-3}\nonumber \\&-C_{4D-10}^{D-3}-C_{2D-4}^{D-3}). \end{aligned}$$
(B.149)
Now we consider the difference between two normalized coefficients, \(\tilde{b}_{D-3},\tilde{b}_{D-2}\),
$$\begin{aligned}&\tilde{b}_{D-3}-\tilde{b}_{D-2}=\frac{ b_{D-3}}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}} \nonumber \\&\quad -\frac{r_h b_{D-2}}{C_{4D-10}^{D-2}+2 C_{3D-7}^{D-2}-C_{2D-4}^{D-2}}. \end{aligned}$$
(B.150)
The difference can be decomposed into four terms and we will analyze term by term.
First, let’s see the \((\mu ^2-\omega ^2)\) term in the difference (B.150), which is
$$\begin{aligned}&r_h^{2}4(D-3)m^4(\mu ^2-\omega ^2)\Bigg [\frac{2C_{3D-7}^{D-3}-C_{4D-10}^{D-3}-C_{2D-4}^{D-3}}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}\nonumber \\&\quad -\frac{2C_{3D-7}^{D-2}-C_{4D-10}^{D-2}-C_{2D-4}^{D-2}}{C_{4D-10}^{D-2}+2 C_{3D-7}^{D-2}-C_{2D-4}^{D-2}}\Bigg ] \end{aligned}$$
(B.151)
The second line in the above square bracket can be rewritten as
$$\begin{aligned}&\frac{2C_{3D-7}^{D-2}-C_{4D-10}^{D-2}-C_{2D-4}^{D-2}}{C_{4D-10}^{D-2}+2 C_{3D-7}^{D-2}-C_{2D-4}^{D-2}}\\&\quad = \frac{(2D-4)2C_{3D-7}^{D-3}-(3D-7)C_{4D-10}^{D-3}-(D-1)C_{2D-4}^{D-3}}{(3D-7)C_{4D-10}^{D-3}+(2D-4)2 C_{3D-7}^{D-3}-(D-1)C_{2D-4}^{D-3}}. \end{aligned}$$
A straightforward calculation of the factor in the square bracket in (B.151) is
$$\begin{aligned} \frac{4(D-3)C_{4D-10}^{D-3}(C_{3D-7}^{D-3}-C_{2D-4}^{D-3})}{(C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3})((3D-7)C_{4D-10}^{D-3}+(2D-4)2 C_{3D-7}^{D-3}-(D-1)C_{2D-4}^{D-3})} >0. \end{aligned}$$
So the \((\mu ^2-\omega ^2)\) term in the difference (B.150) is positive given the bound state condition.
Secondly, let’s see the \((c_D e-\omega )\) term in the difference (B.150),which is
$$\begin{aligned}&r_h^{2}4(D-3)m^4(c_D e- \omega )c_D e\Bigg [\frac{C_{3D-7}^{D-3}+C_{2D-4}^{D-3}}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}\nonumber \\&\quad -\frac{C_{3D-7}^{D-2}+C_{2D-4}^{D-2}}{C_{4D-10}^{D-2}+2 C_{3D-7}^{D-2}-C_{2D-4}^{D-2}}\Bigg ] \end{aligned}$$
(B.152)
The second line in the above square bracket can be rewritten as
$$\begin{aligned}&\frac{C_{3D-7}^{D-2}+C_{2D-4}^{D-2}}{C_{4D-10}^{D-2}+2 C_{3D-7}^{D-2}-C_{2D-4}^{D-2}}\nonumber \\&\quad = \frac{(2D-4)C_{3D-7}^{D-3}+(D-1)C_{2D-4}^{D-3}}{(3D-7)C_{4D-10}^{D-3}+(2D-4)2 C_{3D-7}^{D-3}-(D-1)C_{2D-4}^{D-3}}. \end{aligned}$$
A straightforward calculation of the factor in the square bracket in (B.152) is
$$\begin{aligned} \frac{(D-3)(C_{4D-10}^{D-3}C_{3D-7}^{D-3}+2C_{4D-10}^{D-3}C_{2D-4}^{D-3}+3C_{3D-7}^{D-3}C_{2D-4}^{D-3})}{(C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3})((3D-7)C_{4D-10}^{D-3}+(2D-4)2 C_{3D-7}^{D-3}-(D-1)C_{2D-4}^{D-3})}>0. \end{aligned}$$
So the \((c_D e-\omega )\) term in the difference (B.150) is positive given the superradiance condition.
Thirdly, let’s see the \(\lambda _l\) term in the difference (B.150),which is
$$\begin{aligned}&-4m^4\lambda _l\Bigg [\frac{C_{5D-15}^{D-3}+(D-6)C_{4D-12}^{D-3}+(9-2D)C_{3D-9}^{D-3}+(D-4)C_{2D-6}^{D-3}}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}\nonumber \\&\quad -\frac{C_{5D-15}^{D-2}+(D-6)C_{4D-12}^{D-2}+(9-2D)C_{3D-9}^{D-2}+(D-4)C_{2D-6}^{D-2}}{C_{4D-10}^{D-2}+2 C_{3D-7}^{D-2}-C_{2D-4}^{D-2}}\Bigg ] \end{aligned}$$
(B.153)
The positivity of the above inequality is equivalent to the negativity of the factor in the square bracket, i.e.
$$\begin{aligned}&\frac{C_{5D-15}^{D-3}+(D-6)C_{4D-12}^{D-3}+(9-2D)C_{3D-9}^{D-3}+(D-4)C_{2D-6}^{D-3}}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}\nonumber \\&\quad<\frac{C_{5D-15}^{D-2}+(D-6)C_{4D-12}^{D-2}+(9-2D)C_{3D-9}^{D-2}+(D-4)C_{2D-6}^{D-2}}{C_{4D-10}^{D-2}+2 C_{3D-7}^{D-2}-C_{2D-4}^{D-2}}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{D-2}+2 C_{3D-7}^{D-2}-C_{2D-4}^{D-2}}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}\nonumber \\&\quad<\frac{C_{5D-15}^{D-2}+(D-6)C_{4D-12}^{D-2}+(9-2D)C_{3D-9}^{D-2}+(D-4)C_{2D-6}^{D-2}}{C_{5D-15}^{D-3}+(D-6)C_{4D-12}^{D-3}+(9-2D)C_{3D-9}^{D-3}+(D-4)C_{2D-6}^{D-3}} \nonumber \\&\quad \Leftrightarrow \frac{(3D-7)C_{4D-10}^{D-3}+(2D-4)2 C_{3D-7}^{D-3}-(D-1)C_{2D-4}^{D-3}}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}\nonumber \\&\quad <\frac{a_4C_{5D-15}^{D-3}+a_3(D-6)C_{4D-12}^{D-3}+a_2(9-2D)C_{3D-9}^{D-3}+a_1(D-4)C_{2D-6}^{D-3}}{C_{5D-15}^{D-3}+(D-6)C_{4D-12}^{D-3}+(9-2D)C_{3D-9}^{D-3}+(D-4)C_{2D-6}^{D-3}}, \end{aligned}$$
(B.154)
where \(a_i=i(D-3)\). For the left term of the above inequality, we have
$$\begin{aligned}&\frac{(3D-7)C_{4D-10}^{D-3}+(2D-4)2 C_{3D-7}^{D-3}-(D-1)C_{2D-4}^{D-3}}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}\nonumber \\&\quad =3D-7+\frac{(6-2D)( C_{3D-7}^{D-3}-C_{2D-4}^{D-3})}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}<3D-7.\nonumber \\ \end{aligned}$$
(B.155)
For the right term of the inequality (B.154), we have
$$\begin{aligned}&\frac{a_4C_{5D-15}^{D-3}+a_3(D-6)C_{4D-12}^{D-3}+a_2(9-2D)C_{3D-9}^{D-3}+a_1(D-4)C_{2D-6}^{D-3}}{C_{5D-15}^{D-3}+(D-6)C_{4D-12}^{D-3}+(9-2D)C_{3D-9}^{D-3}+(D-4)C_{2D-6}^{D-3}} =3D-7\nonumber \\&\qquad +\frac{(D-5)C_{5D-15}^{D-3}-2(D-6)C_{4D-12}^{D-3}+(1-D)(9-2D)C_{3D-9}^{D-3}+(4-2D)(D-4)C_{2D-6}^{D-3}}{C_{5D-15}^{D-3}+(D-6)C_{4D-12}^{D-3}+(9-2D)C_{3D-9}^{D-3}+(D-4)C_{2D-6}^{D-3}} >3D-7. \end{aligned}$$
(B.156)
In the above, we use the following result
$$\begin{aligned}&(D-5)C_{5D-15}^{D-3}-2(D-6)C_{4D-12}^{D-3}+(1-D)\nonumber \\&\quad (9-2D)C_{3D-9}^{D-3}+(4-2D)(D-4)C_{2D-6}^{D-3}\\&\quad =(D-5)C_{5D-15}^{D-3}-2(D-6)C_{4D-12}^{D-3}+(D-7)\nonumber \\&\quad C_{3D-9}^{D-3}+(2D-4)(D-4)(C_{3D-9}^{D-3}-C_{2D-6}^{D-3})\\&\quad>C_{5D-15}^{D-3}(D-5-(2D-12)(4/5)^{D-3})\nonumber \\&\qquad +(D-7)C_{3D-9}^{D-3}\nonumber \\&\qquad +(2D-4)(D-4)(C_{3D-9}^{D-3}-C_{2D-6}^{D-3})\\&\quad >0. \end{aligned}$$
So the right term is greater than the left term of the inequality (B.154). The \(\lambda _l\) term in the difference (B.150) is positive.
Finally, let’s see the \(D_1\) term in the difference (B.150), which is
$$\begin{aligned}&-m^4D_1\Bigg [\frac{C_{5D-15}^{D-3}-5C_{4D-12}^{D-3}+10C_{3D-9}^{D-3}-10C_{2D-6}^{D-3}+5}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}\nonumber \\&\quad -\frac{C_{5D-15}^{D-2}-5C_{4D-12}^{D-2}+10C_{3D-9}^{D-2}-10C_{2D-6}^{D-2}}{C_{4D-10}^{D-2}+2 C_{3D-7}^{D-2}-C_{2D-4}^{D-2}}\Bigg ]\nonumber \\ \end{aligned}$$
(B.157)
For \(D=7\), one can check directly that the above term is positive. In the next, we discuss \(D\geqslant 8\) cases.
The positivity of the \(D_1\) term is equivalent to the negativity of the factor in square bracket, i.e.
$$\begin{aligned}&\frac{C_{5D-15}^{D-3}-5C_{4D-12}^{D-3}+10C_{3D-9}^{D-3}-10C_{2D-6}^{D-3}+5}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}<\frac{C_{5D-15}^{D-2}-5C_{4D-12}^{D-2}+10C_{3D-9}^{D-2}-10C_{2D-6}^{D-2}}{C_{4D-10}^{D-2}+2 C_{3D-7}^{D-2}-C_{2D-4}^{D-2}}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{D-2}+2 C_{3D-7}^{D-2}-C_{2D-4}^{D-2}}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}<\frac{C_{5D-15}^{D-2}-5C_{4D-12}^{D-2}+10C_{3D-9}^{D-2}-10C_{2D-6}^{D-2}}{C_{5D-15}^{D-3}-5C_{4D-12}^{D-3}+10C_{3D-9}^{D-3}-10C_{2D-6}^{D-3}+5}\nonumber \\&\quad \Leftrightarrow \frac{(3D-7)C_{4D-10}^{D-3}+(2D-4)2 C_{3D-7}^{D-3}-(D-1)C_{2D-4}^{D-3}}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}\nonumber \\&\quad <\frac{(4D-12)C_{5D-15}^{D-3}-(3D-9) 5C_{4D-12}^{D-3}+(2D-6)10C_{3D-9}^{D-3}-(D-3)10C_{2D-6}^{D-3}}{C_{5D-15}^{D-3}-5C_{4D-12}^{D-3}+10C_{3D-9}^{D-3}-10C_{2D-6}^{D-3}+5}. \end{aligned}$$
(B.158)
For the left term of the above inequality, we have
$$\begin{aligned}&\frac{(3D-7)C_{4D-10}^{D-3}+(2D-4)2 C_{3D-7}^{D-3}-(D-1)C_{2D-4}^{D-3}}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}\nonumber \\&\quad =3D-7+\frac{(6-2D)( C_{3D-7}^{D-3}-C_{2D-4}^{D-3})}{C_{4D-10}^{D-3}+2 C_{3D-7}^{D-3}-C_{2D-4}^{D-3}}<3D-7.\nonumber \\ \end{aligned}$$
(B.159)
For the right term of the inequality (B.158), we have
$$\begin{aligned}&\frac{(4D-12)C_{5D-15}^{D-3}-(3D-9) 5C_{4D-12}^{D-3}+(2D-6)10C_{3D-9}^{D-3}-(D-3)10C_{2D-6}^{D-3}}{C_{5D-15}^{D-3}}\nonumber \\&\qquad -5C_{4D-12}^{D-3}+10C_{3D-9}^{D-3}-10C_{2D-6}^{D-3}+{5}\nonumber \\&\quad =3D-7 +\frac{(D-5)C_{5D-15}^{D-3}+10C_{4D-12}^{D-3}-(D-1)10C_{3D-9}^{D-3}+(2D-4)10C_{2D-6}^{D-3}-5(3D-7)}{C_{5D-15}^{D-3}}\nonumber \\&\qquad -5C_{4D-12}^{D-3}+10C_{3D-9}^{D-3}-10C_{2D-6}^{D-3}+{5} >3D-7. \end{aligned}$$
(B.160)
In the last line of the above equation, we use the positivity of the following term
$$\begin{aligned} \frac{(D-5)C_{5D-15}^{D-3}+10C_{4D-12}^{D-3}-(D-1)10C_{3D-9}^{D-3}+(2D-4)10C_{2D-6}^{D-3}-5(3D-7)}{C_{5D-15}^{D-3}-5C_{4D-12}^{D-3}+10C_{3D-9}^{D-3}-10C_{2D-6}^{D-3}+5}. \end{aligned}$$
(B.161)
The positivity of the denominator of the above term can be checked directly for \(D=8,9,10\) and for \(D>10\), since \(C_{5D-15}^{D-3}/C_{4D-12}^{D-3}>(5/4)^{D-3}>5\), the denominator is positive. For the numerator of the above term, we have
$$\begin{aligned}&[(D-5)C_{5D-15}^{D-3}+10C_{4D-12}^{D-3}-(D-1)10C_{3D-9}^{D-3}]\\&\qquad +[(2D-4)10C_{2D-6}^{D-3}-5(3D-7)]\\&\quad >[(D-5)(\frac{5}{3})^{D-3}+10(4/3)^{D-3}-10(D-1)]C_{3D-9}^{D-3}\\&\qquad +[(2D-4)10C_{2D-6}^{D-3}-5(3D-7)]. \end{aligned}$$
The factor in the first square bracket is positive when \(D>7\) and the term in the second square bracket is obviously positive, then the numerator is also positive.
So the right term is greater than the left term in the inequality (B.158) and the \(D_1\) term in the difference (B.150) is positive.
Based on the positivity of the four terms in the difference (B.150), we obtain that
$$\begin{aligned} \text {sign}(b_{D-3})\geqslant \text {sign}(b_{D-2}). \end{aligned}$$
(B.162)
1.7 B.7 Coefficients of \(z^p\), \( D-3> p >0 \)
When \( D-3> p >0 \), the coefficient of \(z^p\) is
$$\begin{aligned} b_{p}= & {} a_5 C_{5D-15}^{p}r_h^{5D-15-p}+a'_4 C_{4D-10}^{p}r_h^{4D-10-p}\nonumber \\&+a_4C_{4D-12}^{p}r_h^{4D-12-p} \nonumber \\&+a'_3 C_{3D-7}^{p}r_h^{3D-7-p}+a_3 C_{3D-9}^{p} r_h^{3D-9-p}\nonumber \\&+a'_2 C_{2D-4}^{p}r_h^{2D-4-p} \nonumber \\&+a_2C_{2D-6}^{p}r_h^{2D-6-p}+a_1C_{D-3}^{p}r_h^{D-3-p}\nonumber \\= & {} r_h^{-p}(-m^5 D_1)(C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p\nonumber \\&-10C_{2D-6}^{p}+5C_{D-3}^{p})\nonumber \\&+r_h^{-p}(-4m^5\lambda _l)(C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}\nonumber \\&+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p})\nonumber \\&+r_h^{-p+2}4(D-3)m^5(C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p})\nonumber \\&\times (c_D e- \omega )\nonumber \\&\times \left( \frac{(C_{3D-7}^{p}+C_{2D-4}^{p}) c_D e}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}-\omega \right) \nonumber \\&+r_h^{-p+2}4(D-3)m^5(\mu ^2-\omega ^2)(2C_{3D-7}^{p}\nonumber \\&-C_{4D-10}^{p}-C_{2D-4}^{p}). \end{aligned}$$
(B.163)
Now we consider the difference between two normalized coefficients, \(\tilde{b}_{p},\tilde{b}_{p+1}\),
$$\begin{aligned}&\tilde{b}_p-\tilde{b}_{p+1}=\frac{r_h^p b_p}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad -\frac{r_h^{p+1} b_{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}} \end{aligned}$$
(B.164)
The difference can be decomposed into four terms and we will analyze term by term.
First, let’s see the \((\mu ^2-\omega ^2)\) term in the difference (B.164), which is
$$\begin{aligned}&r_h^{2}4(D-3)m^5(\mu ^2-\omega ^2)\Bigg [\frac{2C_{3D-7}^{p}-C_{4D-10}^{p}-C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad -\frac{2C_{3D-7}^{p+1}-C_{4D-10}^{p+1}-C_{2D-4}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\Bigg ] \end{aligned}$$
(B.165)
The positivity of the above term is equivalent to the positivity of the factor in the square bracket. After a straightforward calculation of this factor, we obtain
$$\begin{aligned}&\frac{2C_{3D-7}^{p}-C_{4D-10}^{p}-C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}} -\frac{2C_{3D-7}^{p+1}-C_{4D-10}^{p+1}-C_{2D-4}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\nonumber \\&\quad =\frac{4(D-3)C_{4D-10}^{p}(C_{3D-7}^{p}-C_{2D-4}^{p})}{(C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p})(a'_4C_{4D-10}^{p}+a'_3 2 C_{3D-7}^{p}-a'_2 C_{2D-4}^{p})}\nonumber \\&\quad >0,\nonumber \\ \end{aligned}$$
(B.166)
where \(a'_4=4D-p-10, a'_3=3D-p-7, a'_2=2D-p-4\). So the \((\mu ^2-\omega ^2)\) term in the difference (B.164) is positive given the bound state condition.
Secondly, let’s see the \((c_D e-\omega )\) term in the difference (B.164), which is
$$\begin{aligned}&r_h^{2}4(D-3)m^5(c_D e- \omega )c_D e\Bigg [\frac{C_{3D-7}^{p}+C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad -\frac{C_{3D-7}^{p+1}+C_{2D-4}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\Bigg ] \end{aligned}$$
(B.167)
The positivity of the above term is equivalent to the positivity of the factor in the square bracket. After a straightforward calculation of this factor, we obtain
$$\begin{aligned}&\frac{C_{3D-7}^{p}+C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}} -\frac{C_{3D-7}^{p+1}+C_{2D-4}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\nonumber \\&\quad =\frac{(D-3)(C_{4D-10}^{p}C_{3D-7}^{p}+2C_{4D-10}^{p}C_{2D-4}^{p}+3C_{3D-7}^{p}C_{2D-4}^{p})}{(C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p})(a'_4C_{4D-10}^{p}+a'_3 2 C_{3D-7}^{p}-a'_2 C_{2D-4}^{p})}\nonumber \\&\quad >0.\nonumber \\ \end{aligned}$$
(B.168)
So the \((c_D e-\omega )\) term in the difference (B.164) is positive given the superradiance condition.
Thirdly, let’s see the \(\lambda _l\) term in the difference (B.164), which is
$$\begin{aligned}&-4m^5\lambda _l\Bigg [\frac{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad -\frac{C_{5D-15}^{p+1}+(D-6)C_{4D-12}^{p+1}+(9-2D)C_{3D-9}^{p+1}+(D-4)C_{2D-6}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\Bigg ]\nonumber \\ \end{aligned}$$
(B.169)
The positivity of the above term is equivalent to the negativity of the factor in the square bracket, i.e.
$$\begin{aligned}&\frac{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad<\frac{C_{5D-15}^{p+1}+(D-6)C_{4D-12}^{p+1}+(9-2D)C_{3D-9}^{p+1}+(D-4)C_{2D-6}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad<\frac{C_{5D-15}^{p+1}+(D-6)C_{4D-12}^{p+1}+(9-2D)C_{3D-9}^{p+1}+(D-4)C_{2D-6}^{p+1}}{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p}}\nonumber \\&\quad \Leftrightarrow \frac{(4D-p-10)C_{4D-10}^{p}+(3D-p-7)2 C_{3D-7}^{p}-(2D-p-4)C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad <\frac{a_5C_{5D-15}^{p}+a_4(D-6)C_{4D-12}^{p}+a_3(9-2D)C_{3D-9}^{p}+a_2(D-4)C_{2D-6}^{p}}{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p}}. \end{aligned}$$
(B.170)
In the above inequality, \(a_i=(D-3)i-p\). For the left term of the above inequality, we have
$$\begin{aligned}&\frac{(4D-p-10)C_{4D-10}^{p}+(3D-p-7)2 C_{3D-7}^{p}-(2D-p-4)C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad =4D-p-10+\frac{(6-2D)( C_{3D-7}^{p}-C_{2D-4}^{p})}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}<4D-p-10. \end{aligned}$$
(B.171)
For the right term of the inequality (B.170), we have
$$\begin{aligned}&\frac{a_5C_{5D-15}^{p}+a_4(D-6)C_{4D-12}^{p}+a_3(9-2D)C_{3D-9}^{p}+a_2(D-4)C_{2D-6}^{p}}{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p}}\nonumber \\&\quad =a_4+\frac{(D-3)C_{5D-15}^{p}+(3-D)(9-2D)C_{3D-9}^{p}+2(3-D)(D-4)C_{2D-6}^{p}}{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p}}\nonumber \\&\quad =4D-p-10\nonumber \\&\qquad +\frac{(D-5)C_{5D-15}^{p}-2(D-6)C_{4D-12}^{p}+(D-1)(2D-9)C_{3D-9}^{p}-(2D-4)(D-4)C_{2D-6}^{p}}{C_{5D-15}^{p}+(D-6)C_{4D-12}^{p}+(9-2D)C_{3D-9}^p+(D-4)C_{2D-6}^{p}}\nonumber \\&\quad >4D-p-10. \end{aligned}$$
(B.172)
In the last line of the above inequality, we need the following result
$$\begin{aligned}&(D-5)C_{5D-15}^{p}-2(D-6)C_{4D-12}^{p}+(D-1)\nonumber \\&\quad (2D-9)C_{3D-9}^{p}\nonumber \\&\qquad -(2D-4)(D-4)C_{2D-6}^{p}>0\nonumber \\&\quad \Leftrightarrow (D-5)C_{5D-15}^{p}-2(D-6)C_{4D-12}^{p}+(D-7)C_{3D-9}^{p}\nonumber \\&\qquad +(2D-4)(D-4)(C_{3D-9}^{p}-C_{2D-6}^{p})>0\nonumber \\&\quad \Leftrightarrow (D-5)(C_{5D-15}^{p}-C_{4D-12}^{p})+(D-7)\nonumber \\&\quad (C_{3D-9}^{p}-C_{4D-12}^{p})+(2D-4)\nonumber \\&\quad (D-4)(C_{3D-9}^{p}-C_{2D-6}^{p})>0\nonumber \\&\quad \Leftrightarrow (D-5)(C_{5D-15}^{p}+C_{3D-9}^{p}-2C_{4D-12}^{p})\nonumber \\&\qquad +2(C_{4D-12}^{p}-C_{3D-9}^{p})+(2D-4)(D-4)\nonumber \\&\quad (C_{3D-9}^{p}-C_{2D-6}^{p})>0. \end{aligned}$$
(B.173)
It is easy to see that if the first line of the above inequality (B.173) is non-negative and then the above inequality holds. The first line can be rewritten as
$$\begin{aligned}&(D-5)(C_{5D-15}^{p}+C_{3D-9}^{p}-2C_{4D-12}^{p})\nonumber \\&\quad =(D-5)C_{4D-12}^{p} \left( \frac{C_{5D-15}^{p}}{C_{4D-12}^{p}}+\frac{C_{3D-9}^{p}}{C_{4D-12}^{p}}-2\right) . \end{aligned}$$
(B.174)
It is easy to check that when \(p>3\)
$$\begin{aligned} \frac{C_{5D-15}^{p}}{C_{4D-12}^{p}}>(5/4)^p>2. \end{aligned}$$
(B.175)
And when \(p=1\),
$$\begin{aligned} \frac{C_{5D-15}^{1}}{C_{4D-12}^{1}}+\frac{C_{3D-9}^{1}}{C_{4D-12}^{1}}-2=0. \end{aligned}$$
(B.176)
When \(p=2\),
$$\begin{aligned}&\frac{C_{5D-15}^{2}}{C_{4D-12}^{2}}+\frac{C_{3D-9}^{2}}{C_{4D-12}^{2}}-2 =\frac{5}{4}\cdot \nonumber \\&\quad \frac{5D-16}{4D-13}+\frac{3}{4}\cdot \frac{3D-10}{4D-13}-2. \end{aligned}$$
(B.177)
It is easy to check the above expression is positive when \(D>6\). Similar result holds for \(p=3\). Then the inequality (B.173) holds.
And the right term is greater than the left term of the inequality (B.170). The \(\lambda _l\) term in the difference (B.164) is positive.
Finally, let’s see the \(D_1\) term in the difference (B.164), which is
$$\begin{aligned}&-m^5D_1\Bigg [\frac{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}+5C_{D-3}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad -\frac{C_{5D-15}^{p+1}-5C_{4D-12}^{p+1}+10C_{3D-9}^{p+1}-10C_{2D-6}^{p+1}+5C_{D-3}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\Bigg ].\nonumber \\ \end{aligned}$$
(B.178)
One can check that when \(1\leqslant p\leqslant 4\),
$$\begin{aligned}&C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p\nonumber \\&\quad -10C_{2D-6}^{p}+5C_{D-3}^{p}=0. \end{aligned}$$
(B.179)
and when \(p\geqslant 5\) and \(D>6\)
$$\begin{aligned}&C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p\nonumber \\&\quad -10C_{2D-6}^{p}+5C_{D-3}^{p}>0. \end{aligned}$$
(B.180)
For the above inequality, one can check it directly when \(p=5,6,7\). When \(p\geqslant 8\), \(C_{5D-15}^{p}/C_{4D-12}^{p}>(5/4)^8>5\) and the above inequality holds.
Then the \(D_1\) term is non-negative for \(1\leqslant p\leqslant 4\). In the next, we only discuss the \(p>4\) cases. The positivity of the \(D_1\) term is equivalent to the negativity of the factor in the square bracket, i.e.
$$\begin{aligned}&\frac{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}+5C_{D-3}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad<\frac{C_{5D-15}^{p+1}-5C_{4D-12}^{p+1}+10C_{3D-9}^{p+1}-10C_{2D-6}^{p+1}+5C_{D-3}^{p+1}}{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}\nonumber \\&\quad \Leftrightarrow \frac{C_{4D-10}^{p+1}+2 C_{3D-7}^{p+1}-C_{2D-4}^{p+1}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad<\frac{C_{5D-15}^{p+1}-5C_{4D-12}^{p+1}+10C_{3D-9}^{p+1}-10C_{2D-6}^{p+1}+5C_{D-3}^{p+1}}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}+5C_{D-3}^{p}}\nonumber \\&\quad \Leftrightarrow \frac{(4D-p-10)C_{4D-10}^{p}+(3D-p-7)2 C_{3D-7}^{p}-(2D-p-4)C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad <\frac{a_5C_{5D-15}^{p}-a_4 5C_{4D-12}^{p}+a_3 10C_{3D-9}^{p}-a_2 10C_{2D-6}^{p}+a_1 5C_{D-3}^{p}}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}+5C_{D-3}^{p}}, \end{aligned}$$
(B.181)
where \(a_i=(D-3)i-p\).
For the left term of the above inequality, we have
$$\begin{aligned}&\frac{(4D-p-10)C_{4D-10}^{p}+(3D-p-7)2 C_{3D-7}^{p}-(2D-p-4)C_{2D-4}^{p}}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}\nonumber \\&\quad =4D-p-10+\frac{(6-2D)( C_{3D-7}^{p}-C_{2D-4}^{p})}{C_{4D-10}^{p}+2 C_{3D-7}^{p}-C_{2D-4}^{p}}<4D-p-10. \end{aligned}$$
(B.182)
For the right term of the inequality (B.181), we have
$$\begin{aligned}&\frac{a_5C_{5D-15}^{p}-a_4 5C_{4D-12}^{p}+a_3 10C_{3D-9}^{p}-a_2 10C_{2D-6}^{p}+a_1 5C_{D-3}^{p}}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}+5C_{D-3}^{p}}\nonumber \\&\quad =4D-p-10\nonumber \\&\qquad +\frac{(D-5)C_{5D-15}^{p}+10C_{4D-12}^{p}-10(D-1)C_{3D-9}^{p}+20(D-2)C_{2D-6}^{p}-5(3D-7)C_{D-3}^{p}}{C_{5D-15}^{p}-5C_{4D-12}^{p}+10C_{3D-9}^p-10C_{2D-6}^{p}+5C_{D-3}^{p}}\nonumber \\&\quad > 4D-p-10. \end{aligned}$$
(B.183)
In the last line of the above equation, we use the result that when \(p>4\)
$$\begin{aligned}&(D-5)C_{5D-15}^{p}+10C_{4D-12}^{p}-10(D-1)C_{3D-9}^{p}\nonumber \\&\quad +20(D-2)C_{2D-6}^{p}-5(3D-7)C_{D-3}^{p} > 0. \end{aligned}$$
(B.184)
The above inequality can be shown as follows
$$\begin{aligned}&(D-5)C_{5D-15}^{p}+10C_{4D-12}^{p}-10(D-1)C_{3D-9}^{p}\\&\qquad +20(D-2)C_{2D-6}^{p}-5(3D-7)C_{D-3}^{p}\\&>C_{3D-9}^{p}[(D-5)(5/3)^p+10(4/3)^p-10(D-1)]\\&\qquad +[20(D-2)C_{2D-6}^{p}-5(3D-7)C_{D-3}^{p}]. \end{aligned}$$
When \(p\geqslant 5\) and \(D>6\), it is easy to check the term in the first square bracket is positive. The term in the second square bracket is obviously positive. Thus the inequality (B.184) holds. So the \(D_1\) term in the difference (B.164) is positive.
Based on the positivity of the four terms in the difference (B.164), we obtain that
$$\begin{aligned} \text {sign}(b_{p})\geqslant \text {sign}(b_{p+1}), (D-3>p>0). \end{aligned}$$
(B.185)