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Effects of Rub-Impact on Vibration Response of a Dual-Rotor System-Theoretical and Experimental Investigation

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Abstract

In order to understand the mechanism of fixed-point rub-impact in aero-engine, a dual-rotor system with inter-shaft bearing able to describe the mechanical vibration caused by unbalance and fixed-point rub-impact is developed in this paper. Firstly, a finite element (FE) model of the dual-rotor based on Timoshenko beam element and disk element is proposed, in which the effects of gyroscopic moments, rotary inertias, bending and shear deformations are taken into account. A rub-impact model is developed to derive the rubbing force between the rotor and fixed limiter, in which the softening characteristics of coating painted in casing is fully taken into account. Moreover, the Coulomb model is applied to describe the frictional behaviors. Secondly, the governing equations to describe the motion of the dual-rotor system with rub-impact are solved numerically by the Runge-Kutta method, and the dynamic characteristics are investigated by 3D water-fall plots and frequency spectrum. Combined harmonic frequency, whirling frequency and rotational frequency components of dual rotors are observed. Finally, the experiments of fixed-point rub-impact are performed on a dual-rotor test bench. Good agreement between the theoretical and experimental results shows the accuracy of the dual-rotor FE model and rub-impact model. The results indicate that (1) first backward whirling and forward whirling are excited under the influence of unbalance force; (2) several combination frequency components and second backward whirling and forward whirling frequency components are presented under fixed-point rubbing condition.

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Acknowledgments

The project is supported by the National Natural Science Foundations of China (No. 11572167). We would like to thank China Scholarship Council for support.

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Appendix

Appendix

The stiffness matrix of the Timoshenko beam element:

$$ {K}_T^{es}=\frac{EI}{l^3\left(1+{\Phi}_s\right)}\left[\begin{array}{ccc}12& & \kern1.00em \begin{array}{ccc}& & \begin{array}{cc}& \end{array}\end{array}\\ {}0& 12& \begin{array}{ccc}& & \begin{array}{ccc}& & \begin{array}{cc}& \end{array}\end{array}\end{array}\\ {}\begin{array}{c}0\\ {}6l\\ {}\begin{array}{c}-12\\ {}0\\ {}\begin{array}{c}0\\ {}6l\end{array}\end{array}\end{array}& \begin{array}{c}-6l\\ {}0\\ {}\begin{array}{c}0\\ {}-12\\ {}\begin{array}{c}-6l\\ {}0\end{array}\end{array}\end{array}& \begin{array}{ccc}\begin{array}{c}\left(4+\Phi \right){l}^2\\ {}0\\ {}\begin{array}{c}0\\ {}6l\\ {}\begin{array}{c}2{l}^2\\ {}0\end{array}\end{array}\end{array}& \begin{array}{c}\\ {}\left(4+\Phi \right){l}^2\\ {}\begin{array}{c}-6l\\ {}0\\ {}\begin{array}{c}0\\ {}\left(2-\Phi \right){l}^2\end{array}\end{array}\end{array}& \begin{array}{ccc}\begin{array}{c}\\ {}\\ {}\begin{array}{c}12\\ {}0\\ {}\begin{array}{c}0\\ {}-6l\end{array}\end{array}\end{array}& \begin{array}{c} symm\\ {}\\ {}\begin{array}{c}\\ {}12\\ {}\begin{array}{c}6l\\ {}0\end{array}\end{array}\end{array}& \begin{array}{cc}\begin{array}{c}\\ {}\\ {}\begin{array}{c}\\ {}\\ {}\begin{array}{c}\left(4+\Phi \right){l}^2\\ {}0\end{array}\end{array}\end{array}& \begin{array}{c}\\ {}\\ {}\begin{array}{c}\\ {}\\ {}\begin{array}{c}\\ {}\left(4+\Phi \right){l}^2\end{array}\end{array}\end{array}\end{array}\end{array}\end{array}\end{array}\right] $$
$$ {\Phi}_s=12 EI/{GA}_s{l}^2. $$

The translational inertial matrix of the Timoshenko beam element:

$$ {M}_T^{es}=\frac{\uprho {A}_sl}{820{\left(1+{\Phi}_s\right)}^2}\left[\begin{array}{ccc}{M}_{T1}& & \kern1.00em \begin{array}{ccc}& & \begin{array}{cc}& \end{array}\end{array}\\ {}0& {M}_{T1}& \begin{array}{ccc}& & \begin{array}{ccc}& & \begin{array}{cc}& \end{array}\end{array}\end{array}\\ {}\begin{array}{c}0\\ {}{M}_{T2}l\\ {}\begin{array}{c}{M}_{T3}\\ {}0\\ {}\begin{array}{c}0\\ {}-{M}_{T4}l\end{array}\end{array}\end{array}& \begin{array}{c}-{M}_{T2}l\\ {}0\\ {}\begin{array}{c}0\\ {}{M}_{T3}\\ {}\begin{array}{c}{M}_{T4}l\\ {}0\end{array}\end{array}\end{array}& \begin{array}{ccc}\begin{array}{c}{M}_{T5}{l}^2\\ {}0\\ {}\begin{array}{c}0\\ {}-{M}_{T4}l\\ {}\begin{array}{c}-{M}_{T6}{l}^2\\ {}0\end{array}\end{array}\end{array}& \begin{array}{c}\\ {}{M}_{T5}{l}^2\\ {}\begin{array}{c}{M}_{T4}l\\ {}0\\ {}\begin{array}{c}0\\ {}-{M}_{T6}{l}^2\end{array}\end{array}\end{array}& \begin{array}{ccc}\begin{array}{c}\\ {}\\ {}\begin{array}{c}{M}_{T1}\\ {}0\\ {}\begin{array}{c}0\\ {}-{M}_{T2}l\end{array}\end{array}\end{array}& \begin{array}{c} symm\\ {}\\ {}\begin{array}{c}\\ {}{M}_{T1}\\ {}\begin{array}{c}{M}_{T2}l\\ {}0\end{array}\end{array}\end{array}& \begin{array}{cc}\begin{array}{c}\\ {}\\ {}\begin{array}{c}\\ {}\\ {}\begin{array}{c}{M}_{T5}{l}^2\\ {}0\end{array}\end{array}\end{array}& \begin{array}{c}\\ {}\\ {}\begin{array}{c}\\ {}\\ {}\begin{array}{c}\\ {}{M}_{T5}{l}^2\end{array}\end{array}\end{array}\end{array}\end{array}\end{array}\end{array}\right] $$
$$ {\displaystyle \begin{array}{l}{M}_{T1}=312+588{\Phi}_s+280{\Phi}_s^2,{M}_{T4}=26+63{\Phi}_s+35{\Phi}_s^2\\ {}{M}_{T2}=44+77{\Phi}_s+35{\Phi}_s^2,{M}_{T5}=8+14{\Phi}_s+7{\Phi}_s^2\\ {}{M}_{T3}=108+252{\Phi}_s+140{\Phi}_s^2,{M}_{T56}=6+14{\Phi}_s+7{\Phi}_s^2\end{array}}\kern0.5em {A}_s=\frac{A}{\frac{10}{9}\left(1+\frac{1.6 Dd}{D^2+{d}^2}\right)} $$

The rotational inertial matrix of the Timoshenko beam element:

$$ {M}_R^{es}=\frac{\uprho I}{30{\left(1+{\Phi}_s\right)}^2}\left[\begin{array}{ccc}{M}_{R1}& & \kern1.00em \begin{array}{ccc}& & \begin{array}{cc}& \end{array}\end{array}\\ {}0& {M}_{R1}& \begin{array}{ccc}& & \begin{array}{ccc}& & \begin{array}{cc}& \end{array}\end{array}\end{array}\\ {}\begin{array}{c}0\\ {}{M}_{R2}l\\ {}\begin{array}{c}-{M}_{R1}\\ {}0\\ {}\begin{array}{c}0\\ {}{M}_{R2}l\end{array}\end{array}\end{array}& \begin{array}{c}-{M}_{R2}l\\ {}0\\ {}\begin{array}{c}0\\ {}-{M}_{R1}\\ {}\begin{array}{c}-{M}_{R2}l\\ {}0\end{array}\end{array}\end{array}& \begin{array}{ccc}\begin{array}{c}{M}_{R5}{l}^2\\ {}0\\ {}\begin{array}{c}0\\ {}-{M}_{R2}l\\ {}\begin{array}{c}-{M}_{R4}{l}^2\\ {}0\end{array}\end{array}\end{array}& \begin{array}{c}\\ {}{M}_{R3}{l}^2\\ {}\begin{array}{c}-{M}_{R2}l\\ {}0\\ {}\begin{array}{c}0\\ {}-{M}_{R4}{l}^2\end{array}\end{array}\end{array}& \begin{array}{ccc}\begin{array}{c}\\ {}\\ {}\begin{array}{c}{M}_{R1}\\ {}0\\ {}\begin{array}{c}0\\ {}-{M}_{R2}l\end{array}\end{array}\end{array}& \begin{array}{c} symm\\ {}\\ {}\begin{array}{c}\\ {}{M}_{R1}\\ {}\begin{array}{c}{M}_{R2}l\\ {}0\end{array}\end{array}\end{array}& \begin{array}{cc}\begin{array}{c}\\ {}\\ {}\begin{array}{c}\\ {}\\ {}\begin{array}{c}{M}_{R3}{l}^2\\ {}0\end{array}\end{array}\end{array}& \begin{array}{c}\\ {}\\ {}\begin{array}{c}\\ {}\\ {}\begin{array}{c}\\ {}{M}_{R3}{l}^2\end{array}\end{array}\end{array}\end{array}\end{array}\end{array}\end{array}\right] $$
$$ {\displaystyle \begin{array}{l}{M}_{R1}=36,{M}_{R2}=3-15{\Phi}_s,{M}_{R3}=4+5{\Phi}_s+10{\Phi}_s^2\\ {}{M}_{R4}=1+5{\Phi}_s-5{\Phi}_s^2,I=\frac{\uppi}{64}\left({D}^4-{d}^4\right)\end{array}} $$

The gyroscopic matrix of the Timoshenko beam element:

$$ {G}^{es}=\frac{\uprho I}{15l{\left(1+{\Phi}_s\right)}^2}\left[\begin{array}{ccc}0& & \kern1.00em \begin{array}{ccc}& & \begin{array}{cc}& \end{array}\end{array}\\ {}{M}_{R1}& 0& \begin{array}{ccc}& & \begin{array}{ccc}& & \begin{array}{cc}& \end{array}\end{array}\end{array}\\ {}\begin{array}{c}-{M}_{R2}l\\ {}0\\ {}\begin{array}{c}0\\ {}-{M}_{R1}\\ {}\begin{array}{c}-{M}_{R2}l\\ {}0\end{array}\end{array}\end{array}& \begin{array}{c}0\\ {}-{M}_{R2}l\\ {}\begin{array}{c}{M}_{R1}\\ {}0\\ {}\begin{array}{c}0\\ {}-{M}_{R2}l\end{array}\end{array}\end{array}& \begin{array}{ccc}\begin{array}{c}0\\ {}{M}_{R3}{l}^2\\ {}\begin{array}{c}-{M}_{R2}l\\ {}0\\ {}\begin{array}{c}0\\ {}-{M}_{R4}{l}^2\end{array}\end{array}\end{array}& \begin{array}{c}\\ {}0\\ {}\begin{array}{c}0\\ {}-{M}_{R2}l\\ {}\begin{array}{c}{M}_{R4}{l}^2\\ {}0\end{array}\end{array}\end{array}& \begin{array}{ccc}\begin{array}{c}\\ {}\\ {}\begin{array}{c}0\\ {}{M}_{R1}\\ {}\begin{array}{c}{M}_{R2}l\\ {}0\end{array}\end{array}\end{array}& \begin{array}{c} antisymm\\ {}\\ {}\begin{array}{c}\\ {}0\\ {}\begin{array}{c}0\\ {}{M}_{R2}l\end{array}\end{array}\end{array}& \begin{array}{cc}\begin{array}{c}\\ {}\\ {}\begin{array}{c}\\ {}\\ {}\begin{array}{c}0\\ {}{M}_{R3}{l}^2\end{array}\end{array}\end{array}& \begin{array}{c}\\ {}\\ {}\begin{array}{c}\\ {}\\ {}\begin{array}{c}\\ {}0\end{array}\end{array}\end{array}\end{array}\end{array}\end{array}\end{array}\right] $$

where As is effective shear area, A is the cross-sectional area, E is elastic modulus, I is the second moment of area of the cross section about the neutral plane, G is shear modulus, l is the length of beam element, D and d are outer diameter and inner diameter, respectively.

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Wang, N., Jiang, D. & Xu, H. Effects of Rub-Impact on Vibration Response of a Dual-Rotor System-Theoretical and Experimental Investigation. Exp Tech 44, 299–311 (2020). https://doi.org/10.1007/s40799-019-00352-w

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