Abstract
A Hilbert space operator \(T\in B({{{\mathcal {H}}}})\) is (m, P)-expansive, for some integer \(m\ge 1\) and positive operator \(P\in B({{{\mathcal {H}}}})\), if \(\sum _{j=0}^m{(-1)^j\left( \begin{array}{clcr}m\\ j\end{array}\right) T^{*j}PT^j}\le 0\). No Drazin invertible operator T can be (m, I)-expansive, and if T is (m, P)-expansive for some positive operator P, then necessarily P has a decomposition \(P=P_{11}\oplus 0\) and the Drazin inverse \(T_d\) of T is (m, P)-contractive. In particular, a Drazin invertible (2, P)-expansive operator is P isometric. If T is \((m,|T^n|^2)\)-expansive for some positive integer n, then \(T^n\) has a decomposition \(T^n=\left( \begin{array}{clcr}U_1P_1 & X\\ 0 & 0\end{array}\right) \), the operator \(P_1U_1\) is m-expansive, the operator \(P^{\frac{1}{2}}_1U_1P^{\frac{1}{2}}_1 \) is m-expansive in an equivalent norm, the operator \(\left( \begin{array}{clcr}P_1U_1 & P_1X\\ 0 & 0\end{array}\right) \) is (m, C)-expansive and the operator \(\left( \begin{array}{clcr}P^{\frac{1}{2}}_1U_1P^{\frac{1}{2}}_1 & P_1^{\frac{1}{2}}X\\ 0 & 0\end{array}\right) \) is (m, D)-expansive for some operators \(C, D\ge 0\).
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The authors are thankful to a referee for his very thoughtful, comprehensive comments on the original version of the paper, many of which have now been incorporated into the manuscript.
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Author I. H. Kim was supported by Basic Science Research Program through the National Research Foundation of Korea (NRF) funded by the Ministry of Education (NRF-2019R1F1A1057574).
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Duggal, B.P., Kim, I.H. Expansive operators and Drazin invertibility. Rend. Circ. Mat. Palermo, II. Ser 72, 341–353 (2023). https://doi.org/10.1007/s12215-021-00683-x
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DOI: https://doi.org/10.1007/s12215-021-00683-x