Abstract
1.Solve the equation
where n is an integer greater than 1. Solution. For n = 2, the only solutions are (0, 2) and (0, –2). For n = 3, we have seen in Example 4 that the solutions are (2, 2), (–2, 2), (11, 5), and (–11,5). Lef now n ≥ 4. Clearly, for n even, the equation is not solvable, since no other squares differ by 4. For n odd, we may assume without loss of generality that n is a prime p ≥ 5. Indeed, if n = q k, where q is an odd prime, we obtain an equation of the same type: x 2 + 4 = (y k)q.
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© 2009 Birkhäuser Boston
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Andreescu, T., Andrica, D., Cucurezeanu, I. (2009). Solutions to Some Advanced Methods in Solving Diophantine Equations. In: An Introduction to Diophantine Equations. Birkhäuser Boston. https://doi.org/10.1007/978-0-8176-4549-6_8
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DOI: https://doi.org/10.1007/978-0-8176-4549-6_8
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