, Volume 23, Issue 1, pp 121-127

A Theorem on Higher Bruhat Orders

Rent the article at a discount

Rent now

* Final gross prices may vary according to local VAT.

Get Access

Abstract.

We show that inclusion order and single-step inclusion coincide for higher Bruhat orders B(n,2) , i.e., \(B(n,2) = B_\subseteq(n,2)\) .